tapewormbyte

Respectively: - I don't know, are you? - Because the username/password combination isn't a valid login to MySQL. - Probably not, actually. But it wouldn't be a problem. - Maybe. - Try taking the error message at face value. I'm sorry, this really has my head spinning... The following code works, successfully connecting to the database: if($_POST['passwd'] == $_POST['passwd2']) { $test = db_query("SELECT * FROM INVENTORY WHERE INV_ID = 1"); echo $test[0]['NAME']; $passwd = $_POST['passwd']; However if I change the code ever so slightly, it doesn't work, giving me the connection error: if($_POST['passwd'] == $_POST['passwd2']) { $passwd = $_POST['passwd']; $test = db_query("SELECT * FROM INVENTORY WHERE INV_ID = 1"); echo $test[0]['NAME']; I don't get it... EDIT: oh my god... I just realized I'm resetting the $passwd variable... Same variable I previously set for the database connection. DUH.. Thanks for the help...

I'm working offline, with apache on ubuntu. I have written my own session handler and my mysql connects, inserts and updates the session handler just fine. I'm in the process of writing a "registration" form, and when I attempt to INSERT the data after it has been validated I get the warning: mysql_connect(): Access denied for user 'root'@'localhost' (using password: YES) But, I'm already connected? Why would this happen? I'm sure if it were attempting to connect when already connected, it would tell me so. Likewise if it were a syntax error. Any ideas?