sana
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I am trying to build a login.php page and I want to keep the content template (the HMTL content with PHP variables referring to class). All I want is to read this login.php inside my main php file and execute it so that HMTL content is rendered as it is and the variables are executed at server side....
example of my login.php content template would like...
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<form action='{$this->self}?a=login&s=on' method='post'>
<table>
<tr>
<td class='header' colspan='2'>{$this->lang->login_header}</td>
</tr>
<tr>
<td class='tablelight' style='width:30%'>{$this->lang->login_user}</td>
<td class='tablelight'>
<input class='input' type='text' name='user' size='30' tabindex='1' />
</td>
</tr>
<tr>
<td class='tabledark'>
{$this->lang->login_pass}<br />
<a href='{$this->self}?a=login&s=pass'>{$this->lang->login_forgot_pass}</a>
</td>
<td class='tabledark'>
<input class='input' type='password' name='pass' size='30' tabindex='2' />
</td>
</tr>
<tr>
<td align='center' colspan='2' class='footer'>
<input type='hidden' name='request_uri' value='' />
<input type='submit' name='submit' value='submit' tabindex='3' />
</td>
</tr>
</table>
</form>
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Yes, file B contains just this line because I wanted to test it whether this will work or not. The idea is to keep all variables in a file and dynamically serve them to build a html file
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hi there.
File A contains a class with set of variables and one of the variables is invoked from another file B.php. When we execute, A.php the output is $this->lang->login_user as opposed to displaying it's value. Could anyone help what I am missing?
File A:
*************
[code=php:0]
<?php
include './fglobal.php';
class junk extends ClassBase
{
public $len;
function __construct()
{
$this->len=5;
}
function execute()
{
return $this->generate_pass($this->len);
}
public $login_user="User";
public $login_pass="password" ;
public $submit ="submit";
public function displaypage()
{
$this->get_lang_file();
$this->lang->login();
//echo($this->file_open());
//echo($this->lang->login_user);
$temp=$this->file_open();
echo ($temp);
}
function file_open()
{
$filename = "Flogin.php";
if($fp = @fopen($filename, "r"))
{
//$fp = @fopen($filename, "r");
$contents = fread($fp, filesize($filename));
fclose($fp);
return $contents;
}else{
return 'file not found';
}
}
}
$a = new junk();
$a->displaypage();
//eval("echo(\$temp);");
?>
[/code]
**************
File B
*************
[code=php:0]
$this->lang->login_user
[/code]
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How to render dynamic variable from a php file
in PHP Coding Help
Posted