Fallen_angel

This is the example your looking for: Code: <?php /* This example assumes that www.example.com is configured to parse .php * files and not .txt files. Also, 'Works' here means that the variables * $foo and $bar are available within the included file. */ // Won't work; file.txt wasn't handled by www.example.com as PHP include 'http://www.example.com/file.txt?foo=1&bar=2'; // Won't work; looks for a file named 'file.php?foo=1&bar=2' on the // local filesystem. include 'file.php?foo=1&bar=2'; // Works. include 'http://www.example.com/file.php?foo=1&bar=2'; $foo = 1; $bar = 2; include 'file.txt'; // Works. include 'file.php'; // Works. ?> If your going to include a file, with ?foo=1&bar=2, you need to use an absolute path. Thankyou both very much , thats is exactly what i was tryign to go through but it wasn't workign for me however yes the full path was working but not apropriate for the situation this script is setup in unfortunatly. I have ended up goign with $_GET['id]=foo ; include "file.php" ; then on the other page i simply pulled the get vairable out and it works wonderfully thankyou both so so much again

Hi , I am hopign someon can help me out here I am trying to use the following include include "./file.php?foo=var1&bar=var2" ; However its not working because the server is obiously looking for a file called "file.php?id=var1&bar=var2" not just file.php then parsing the variables to it. I have read a few peoples sugestions in the includes manual liek settign the variable outside of the include and then passing it into the include itself ie $vars= '?foo=var1&bar=var2' ; include './file.php$vars ; : but that did what i thought it would and just spat back the same error. I am sure it's the variable thats causign the issue because when i take it away the include works however this makes it so that my script doesn't work properly without manually setting the variable Thanx to anyone that can help out

Ok figured it out for some reason my script didn';t liek the collom with the name group no matter what i put in there , however as soon as i changed group to grp it worked so go figure lol could someone possibly explain that cause i have the script workign now but i'm kinda scratching my head as to what i did wrong before

I relised that I made an error with my example I gave i put $group[]=$_POST['location[]'] ; instead of just $group=$_POST['location'] ; after doing some more testign i have discovered the issue is when i add a certain feild of my database to the sql script , even if I vet the value manually it still makes the whoel thing fail so the issue is in part of my sql script that I'm sure i can knuckle out thanx anyways hehe

Hi , I am having a bit of an issue getting a foreach statement i have made to work , essentially what this for each statement is suposed to do is write a row to a database for each one of the check boxes selected here is the code <Form enctype='multipart/form-data' action="process_add_banner.php" method="post"> <input type='hidden' name='send' value='1' /> <tr><td>Name:</td><td><input type="Text" name="name"><br></td></tr> <tr><td>Locations</td><td> <table width="100%"> <tr ><td><INPUT TYPE=CHECKBOX NAME="location[]" VALUE="None">None</td> <td><INPUT TYPE=CHECKBOX NAME="location[]" VALUE="Forums">Fourms</td> <td><INPUT TYPE=CHECKBOX NAME="location[]" VALUE="Extras">Extras</td> <td><INPUT TYPE=CHECKBOX NAME="location[]" VALUE="Portal">Portal</td> </tr> </table> </td><tr> <tr><td></td><td><input type="Submit" name="submit" value="Submit Information"></td><tr> </form> and the processing code is $name=$_POST['name']; $group[]=$_POST['location[]'] ; foreach ($group as $loc) { $sql = "INSERT INTO database (name,group) VALUES ('$name','$loc')"; $result = mysql_query($sql); } Can someone please tell me where i am going wrong ? I don't get any syntax errors it just doesn't do the insert . Thanx allot for your assistance

I have a script in which I allow users to upload 4 files , this script works fine and does the job I want perfectly , However I wanted to add a comments section for each of the images , I tried playing around a little but I can't seem to get it to work so if someon could help me here i woudl really apreciate it the relivant part of the forum itself says <?php // max number of files allowed to upload at one tome define ( 'MAX_FILES', '4' ); for ( $i = 1; $i <= MAX_FILES; $i++ ) { echo " <tr><td>Image Comments</td><td><TEXTAREA rows='2' cols='35' name='comments[$i]' ></textarea></td></tr>\r\n"; echo " <tr><td>Select image</td><td><input type='file' name='up[$i]' size='36'></td></tr>\r\n"; echo " <br />\r\n"; } ?> Now as mentioned the "up" one works fine as part of the bellow upload script however I am not sure how to echo the comments on the next page which is what i need help with <?php define ( 'UPLOAD_PATH', '../uploads/' ); // max number of files allowed to upload at one tome define ( 'MAX_FILES', '4' ); // define the max single file size (bytes) define ( 'MAX_SIZE', '1048576' ); // allowed types $allow = array ( 'png', 'jpg' ); /* e - config */ if ( ! empty ( $_POST['send'] ) ) { $return = array(); $x = 1; for ( $i = 1; $i <= sizeof ( $_FILES['up'] ); $i++ ) { if ( is_uploaded_file ( $_FILES['up']['tmp_name'][$i] ) ) { if ( $_FILES['up']['tmp_name'][$i] != 'none' ) { $ss = filesize ( $_FILES['up']['tmp_name'][$i] ); if ( $ss > 10 && $ss <= MAX_SIZE ) { $sn = strtolower ( $_FILES['up']['name'][$i] ); $ran= md5(rand() * time()); // make a random filename $randName = $ran."." ; $ce = substr ( $sn, ( strrpos ( $sn, '.' ) + 1 ) ); if ( in_array ( $ce, $allow ) ) { if ( move_uploaded_file ( $_FILES['up']['tmp_name'][$i], UPLOAD_PATH . $randName.$ce ) ) { $return[$x]['name'] = $randName; $return[$x]['type'] = $ce; $return[$x]['size'] = $ss; $x++; } } } } } } } ?> <html> <head> <?php if ( ! empty ( $return ) ) { ?> <div align='center'> <table width='672'> <tr> <td align='center'>FILES UPLOADED</td> </tr> <tr> <td> <table width='100%'> <tr> <td align='center' width='4%' height='21'>#</td> <td width='2%'></td> <td align='center' width='52%' height='21'>FILE NAME</td> <td width='2%'></td> <td align='center' width='24%' height='21'>FILE SIZE</td> <td width='2%'></td> <td align='center' width='16%' height='21'>FILE TYPE</td> </tr> <?php for ( $i = 1; $i <= sizeof ( $return ); $i++ ) { echo " <tr> <td align='center' width='4%' height='21'>" . ( $i < 10 ? '0' . $i : $i ) . "</td> <td width='2%'></td> <td align='center' width='52%' height='21'>" . $return[$i]['name'] . "</td> <td width='2%'></td> <td align='center' width='24%' height='21'>" . $return[$i]['size'] . " bytes</td> <td width='2%'></td> <td align='center' width='16%' height='21'>" . $return[$i]['type'] . "</td> </tr> "; } ?> </table> </td> </tr> <tr> <td width='100%' height='8'></td> </tr> </table> </div> <a href="javascript:history.back()"><< Go Back</a> </body> </html> thankyou to anyone that can assist me with this I would really apreciate it basicly all I need to be shown is how i can call the comments aray from the previous forum

Hi , I need a little bit of help tidying up the bellow search script, it does the search and returns the results perfectly however I wanted to make one expantion to it , I would like to make it so that it only displays a certain number of results per page , ( say 15 ) and over that number it gives a link to move onto the next 15 results . with the size of my tutorial system at the moment it isn't effecting me too badly but as it grows it will and i plan to have the content people working on it in a week or two anyways here is the code i have so far <html> <head> <title></title> </head> <body> <div class="search_bar"> <table><tr><td> <form name="form" action="search.php" method="Get"> <input class="whitebox" type="text" size="21" name="q" /></td><td class="go_button"> <input type="image" height="21px" src="./images/go.gif" name="Submit" /> </form></td></tr></table> </div> <?php $var = @$_GET['q'] ; $q=$_GET['q']; //Connect To database include "connect.php"; //collects Data $data=mysql_query(" SELECT t_id,t_notes,t_name,img FROM table WHERE file LIKE '%$q%' ") or die(mysql_error()); Print "<br><br><table class='print_list_alpha';>" ; while ($info= mysql_fetch_array($data) ) { Print "<tr class='result_row'><td><img src=./uploads/mini_thumbs/".$info['img']."></td><td class='result_col'><table><tr><td><a href=../tutorial.php?id=".$info['t_id']."><b>".$info['t_name']."</b></a></td><tr><td><p>"; Print substr($info['t_notes'],0,350); Print "<a href=../tutorial.php?id=".$info['t_id']."><b>.....</b></a></p></td></tr></table>"; } Print "</table>" ; ?> </body> </html> If someone could show me how to edit this or point me in the direction of a relevant guide ect I would be greatly appreciative. thankyou very much in advance regards, fallen_angel

Hi , I have made a form where I have a few area's that contain drop down options the last option in the drop box is an other option , what I want to do is have a text box appear when other is selected. I belive i am on my way with the code bellow however there is something wrong with how I did the seccond dropdown ( or junction not sure wich ) if somone could please have a look at this and tell me what i have missed or done wrong I woudl really apreaciate it , the top drop down works pretty much as it's suposed to ( drops down a line instead of apearing next to the drop down ) however the seccond other box is always there and never hides itself the first ( workign ) function is if(document.all && !document.getElementById) { //IE4 support document.getElementById = function(id) { return document.all[id]; } } /* This works in Firefox, Netscape 6+, IE4+/Win, Opera 7+, Konqueror 3, Safari, IE5/Mac, and iCab 3. */ function customOption(selected) { //selected is the selected option if(!document.getElementById) return; // selected's value property is retrieved and converted to lower case to make // comparing it to another string simpler var val = selected.value.toLowerCase(); // gets the object reference for the element var el = document.getElementById('other1label'); // if val is set to 'customoption' show the textbox if(val == 'customoption') { el.style.display='block'; } else { // otherwise hide it or keep it hidden. el.style.display='none'; } } function dss_addLoadEvent(fn) { if(typeof(fn)!="function")return; var tempFunc=window.onload; window.onload=function() { if(typeof(tempFunc)=="function")tempFunc(); fn(); } } dss_addLoadEvent(function() { // we find the form element and the select element and attach the event // handlers to them var f = document.StrainReport; f.onsubmit = function(){return false;} var sel = f.medium_type; sel.onchange=function(){customOption(this.options[this.selectedIndex])} // we call the function when the page loads to hide #other1label initially sel.onchange(); }); // --> and the box that corrasponds with that working function has the following code <label> <div class="cont"> <div class="label"><label for="medium_type" ><select name="medium_type" id="select1"> <option name="medium_type" value="General Soil">General Soil</option> <option name="medium_type" value="Option 1">Option 1</option> <option name="medium_type" value="Option 2">Option 2</option> <option name="medium_type" value="Option 3">Option 3</option> <option name="medium_type" value="Option 4">Option 4</option> <option name="medium_type" value="Option 5 ">Option 5 </option> <option value="customoption">Other...</option> </select></label></div> <div class="label" id="other1label"><label for="other1" >Other: <input type="text" name="other1" id="other1"></label></div> </div> the seccodn funtion which doesn't work is if(document.all && !document.getElementById) { //IE4 support document.getElementById = function(id) { return document.all[id]; } } /* This works in Firefox, Netscape 6+, IE4+/Win, Opera 7+, Konqueror 3, Safari, IE5/Mac, and iCab 3. */ function customOption2(selected) { //selected is the selected option if(!document.getElementById) return; // selected's value property is retrieved and converted to lower case to make // comparing it to another string simpler var val = selected.value.toLowerCase(); // gets the object reference for the element var el = document.getElementById('other2label'); // if val is set to 'customoption2' show the textbox if(val == 'customoption2') { el.style.display='block'; }else { // otherwise hide it or keep it hidden. el.style.display='none'; } } function dss_addLoadEvent2 (fn) { if(typeof(fn)!="function")return; var tempFunc=window.onload; window.onload=function() { if(typeof(tempFunc)=="function")tempFunc(); fn(); } } dss_addLoadEvent2(function() { // we find the form element and the select element and attach the event // handlers to them var f = document.StrainReport; f.onsubmit = function(){return false;} var sel = f.system_type; sel.onchange=function(){(this.options[this.selectedIndex])} // we call the function when the page loads to hide #other2label initially sel.onchange(); }); // --> with the drop box code of <label> <div class="cont" <div class="label"><label for="system_type"><select name="system_type" id="select2"> <option name="system_type" value="Option 1">Option 1</option> <option name="system_type" value="Option 2">Option 2</option> <option name="system_type" value="Option 3">Option 3</option> <option name="system_type" value="Option 4">Option 4</option> <option name="system_type" value="Option 5 ">Option 5 </option> <option value="customoption2" onselect="customOption2(selected)">Other...</option> </select></label></div> <div class="label" id="other2label"> <label for="other1" > Other: <input type="text" name="other1" id="other1"></label></div> </div> I have been over and over the script and can't see what i'm doign wrong would really apreaciate any help peopel can provide I have attached a copy of the full page so that you can easly look at the two together thankyou again in advance to anyone that can help [attachment deleted by admin]

Thanx for picking up on the error but it seems to be working the same way still doing that , However after being given a bit more time I have come up with the bellow code that checks for the cookie itself first and then echo's what it's supposed to if the user is not logged in , and ofcourse once they login it all works fine already so thats not a problem either If somone could please have a look at what i have now though and see if I have bloated it a bit too much or if they can advise of weaknesses in doing my checking this way I would really appreciate it think I have it but could you guys have a look and see if I am beign a bit sloppy or doing anything un needed here please <?php include "connect2.php"; if (isset($_COOKIE['session_id'])) { $mid = intval($_COOKIE['member_id']); $ses = intval($_COOKIE['session_id']); // Look up member $result = mysql_query("SELECT m.id, members_display_name, member_login_key, mgroup_others, g.g_access_cp FROM ibf_members m, ibf_groups g WHERE id = $mid AND m.mgroup = g.g_id"); $member = mysql_fetch_array($result); // Look up session $result2 = mysql_query("SELECT id,member_name,member_id FROM ibf_sessions WHERE member_id= $mid AND id = $ses"); $member2 = mysql_fetch_array($result2); // Name/password matches? if (($member['id'] == $mid) and ($member['member_login_key'] == $_COOKIE['pass_hash'])) { echo "<div class='welcome'>Welcome ".$member['members_display_name']."</div><br />"; return true; } else { echo "<div class='loginmessage'>Welcome Guest.</div><br />"; } } else { echo "<div class='loginmessage'>Welcome Guest.</div><br />"; } ?> thanx again to anyone in advance

Hi , I am making a web app tutorial system and was hoping someone could help me out with a flaw in my session check code because it is doing something very strange. Before i go any further I should say that this session check is to check an invision session I have Invision 2.2 on my localhost where I am building the webapp so that could be related to the issue although I don't think it is i thought it was worth a mention . anyways first the code <?php include "connect.php"; $mid = intval($_COOKIE['member_id']); // Look up member $result = mysql_query("SELECT m.id, members_display_name, member_login_key, mgroup_others, g.g_access_cp FROM ibf_members m, ibf_groups g WHERE id = $mid AND m.mgroup = g.g_id"); $member = mysql_fetch_array($result); // Name/password matches? if (($member['id'] == $mid) and ($member['member_login_key'] == $_COOKIE['pass_hash'])) { echo "<div class='welcome'>Welcome ".$member['members_display_name']."</div><br />"; return true; } else { echo "<div class='loginmessage'>Welcome Guest.</div><br />"; } ?> Anyways onto explaining whats happening, I by default clear all cookies when i close off my browser and when I open a fresh copy of a page that is supposed to do a session check it doesn't seem to work , the bellow code is basically supposed to do a session check and then eighther echo , Welcome (username ) if a forum user is logged in , or it is supposed to echo Welcome Guest , Instead though for some unknown reason it just echo's Welcome. However and this is where it gets weird , if I log into my dev version of invision and then go back to the same page it works fine for logged in members and echo's Welcome (Username). So i figured it must be the else part of the statement , but before i fiddled with it i decided to try and use the Delete cookies set by this board function. when I used that function and then went back to my webapp , it echoed Welcome Guest as it should !! Closed my browser and it went back to not working again until I repeat the above steps If someone could tell me what they think is happening here and how to fix it I would really appreciate it

Hi thanx for the reply what I am actually trying to do is que up a series of images , to be used in a slide show the webapp I have made is a tutorial guide and I want the users to be able to click on a link in the tutorial and view a slide show for all the images relating to it , I want to display these one by one thanx again for the help

thanx allot guys  the as statement was where i was totally going wrong , I saw it used in the php manual and  I now have it so that I get no errors with the bellow code [code]<?php //Connect To database include "connect.php"; $id = $_GET['id']; //collects Data $data=mysql_query(" SELECT imagefile FROM strain_images where strain_id='$id' ") or die(mysql_error()); $row=mysql_fetch_array($data) ; $i=0 ; foreach ($row as $image) {   $i++ ;   $image[$i]=$row[$i]['imagefile'];   }   echo "<img src='./uploads/$image[0]'>" ?> [/code] however I think I am a little confused as to how the value gets echoed or mabey i set something wrong ( perhaps how i used as )  because when I do what i would normally do to insert an array into a database or echo it on the screen it simply doesn't work the above code for example gives me the letter b as the value of $image[0] which is not what it's database value is ,  if I change the 0 int to 1 though then I get a instead of b any idea's ? thanx again in advance

I was trying to do what was suggested in the bellow link [url=http://www.phpfreaks.com/forums/index.php/topic,123109.msg508469.html#msg508469]http://www.phpfreaks.com/forums/index.php/topic,123109.msg508469.html#msg508469[/url] basicly the end result is that I want to create a slide show , the array is meant to contain each imagefile name from each relevant row , the above code is basicly just to change $i from 0 to what ever number, incrementing one number relivant per row  for example the first would become image[0]  would be the first , image[1] woudl be the seccond and image[8] would be the final hope that makes sense

you could use get instead of post then at the top of the page have  something like [code]$id = $_GET['id'];[/code] then the variable is set in the url , for example for january you could have www.yoursite.com/page.php?id=january hope that helps

sorry i must have been editing as you posted the error I am getting is unexpected T_VARIABLE on line 14