reyes99

Thanks guys, looks like I have to do some more research.

Hello all, I have this javascript that I am calling when I push a button. I want to load the popup programatically not by a button event. in popup.js I have the following function that loads the popup. //LOADING POPUP //Click the button event! $("#button").click(function(){ //centering with css centerPopup(); //load popup loadPopup(); }); My question is how do I load the popup from a php script by assigning a variable. for example <?php if ($loadpup = 'yes') { load the popup ( what command can I use that will activate the popup??) } ?> Thanks in advance

Sorry, I am kind of a newbie but I figured it out now with your help. Thanks you so much!!!

Thank you for your quick response but I tested it with the $key and when I check any of the checkboxes and then click the Delete Button I always get : Array ( [0] => on [1] => on ) for example if I delete the second one I should get Array ( [0] => on [2] => on ) Right? but I am getting 0 & 1 Thanks again. Ralph

Hi all, I have been trying to figure this out for a few days already and can't seem to figure it out. I want to display a few images with a checkbox next to it so I can delete multiple images at once when I press the delete button. My problem is that I can't seem to figure out how to check if the checkbox is checked. if I uncheck one of them and click the delete button it deletes one from the array but I don't know which one was unchecked. For example if I uncheck the second one the array shows: Array ( [0] => on [1] => on ) but I don't know which of the three was unchecked? Here is the code I have been testing with: <?php // if submit button is clicked if(isset($_POST['submit'])) { // do delete function(); } // display deletethis[] array if (isset($_POST['deletethis'])) { echo "<pre>"; print_r ($_POST['deletethis']); echo "</pre>"; } $separate = array("http://funnypicturesimages.com/images/image/funny-dog-pictures.jpg", "http://1.bp.blogspot.com/-35wQMpYtNZc/TXWNx8y2xCI/AAAAAAAB_2o/9vZYNfWrGn8/s400/funny_demotivational_posters_01.jpg", "http://3.bp.blogspot.com/-TFnzZ8zFtgg/TXWNpodBkGI/AAAAAAAB_2Q/O_fOOSqFM6w/s400/funny_demotivational_posters_04.jpg"); echo '<form action="'.$_SERVER['PHP_SELF'].'" method="post">'; // display each image from array foreach ($separate as $value) { echo "<img src=".$value.">"; if ($_POST['deletethis'] = "on") { $checked="checked"; } else { $checked=""; } if ($_POST['deletethis'] != "") { echo "checked"; } else{ echo "unchecked"; } // if checkbox currently checked display it checked else display unchecked if ($checked == "checked") { echo '<input type="checkbox" name="deletethis[]" checked="checked"/><br /><br />'; } else { echo '<input type="checkbox" name="deletethis[]"/><br /><br />'; } } ?> <center><input type="submit" name="submit" value="Delete Checked"></center> </form>

That worked!! Thank you guys for your help. xtopolis here is what I did to fix it from your example, I have been tryting to get this to work for a week!! <?php echo "<form id='form1' name='form1' method='post' action=''><p> <label><input type='text' name='memberid[]' value='memberid' /></label></p><p> <label><input type='text' name='memberid[]' value='memberid' /></label></p><p> <label><input type='submit' name='submit' value='Submit' /></label></p> </form>"; foreach($_POST['memberid'] as $value){ echo "The value was $value<br />"; } ?> Thank you Daniel0 for the tutorial I will go through it.

Hi Everyone, I am having trouble figuring out how to store data from my form into an array and reading it. This is what I have so far. <?php echo "<form id='form1' name='form1' method='post' action=''><p> <label><input type='text' name='memberid[]' value='memberid' /></label></p><p> <label><input type='text' name='memberid[]' value='memberid' /></label></p><p> <label><input type='submit' name='submit' value='Submit' /></label></p> </form>"; $memberid = array("$memberid"); echo "output = " . print_r("$memberid"); ?> I get the following error: Notice: Undefined variable: memberid in C:\Program Files\EasyPHP 2.0b1\www\test.php on line 8 Arrayoutput = 1 Thanks Ralph