php.ajax.coder

You need to use Sessions check it out at php.net

Try this 'SCRIPT_FILENAME' if not you should be able to find it here -> http://uk3.php.net/manual/en/reserved.variables.server.php

Would highly recommend wordpress because of the free plugins and designs

Try using a cms like wordpress it's free add has lots of cool features http://wordpress.org/

Try using a cms like wordpress it's free add does this and more http://wordpress.org/

try removing '$conn =' and add a closing } to the foreach statement on the line $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');

you don't need the quote makes around the db name in the insert query INSERT INTO sample_db

Try using xampp http://www.apachefriends.org/en/xampp-windows.html or EasyPhp http://www.easyphp.org/index.php both open source and include PHP Apache Mysql plus others

You have to request the file through the web browser http://localhost/file.php

I found a good tutorial to do this http://www.tanguay.info/web/tutorial.php?idCode=phpDevelopment&sectionIdCode=installApache

Try using a tool like noIP

Try looking at this http://www.w3schools.com/php/php_mysql_create.asp

Have a look at this http://uk.php.net/manual/en/function.mysql-fetch-row.php

This is more of an SQL question post it there and you might get you answer

I would have three tables in the database 1. Users - UserID, IP 2. Posts/Announcements PostID etc 3. viewed - UserID and PostID Add each new IP to the users table and then add an entry to the viewed table when the post is read. Then check for entry to see if viewed

Try looking at this post http://www.phpfreaks.com/forums/index.php/topic,95433.0.html

Try this Script <?PHP $chars = array("A","B","C","D","E","F","G","H","I","J","K","L","M","N", "O","P","Q","R","S","T","U","V","W","X","Y","Z","a","b", "c","d","e","f","g","h","i","j","k","l","m","n","o","p", "q","r","s","t","u","v","w","x","y","z", "1","2","3","4","5","6","7","8","9","0"); //Lenght of String $string_length = 6; //Result String $result = ""; //Array Length $count = count($strs) - 1; for ($i = 0; $i <= $string_length; $i++){ $rand = rand(0, $count); $result = $result . $strs[$rand]; } echo $result; ?>

Try looking at this http://uk2.php.net/manual/en/function.mysql-fetch-row.php

make it clear what you want to do

You could use a timestamp with a random number added to the end e.g. <?Php echo time() + rand(0,9); ?>

Try Something like this <?php $con = mysql_connect("localhost","peter","abc123"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_db", $con); $result = mysql_query("SELECT * FROM person"); while($row = mysql_fetch_array($result)) { echo $row['FirstName'] . " " . $row['LastName']; echo "<br />"; } mysql_close($con); ?>

Try this script <script type="text/Javascript"> var xmlHttp; try{ // Firefox, Opera 8.0+, Safari xmlHttp=new XMLHttpRequest(); }catch (e){ // Internet Explorer try{ xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); }catch (e){ try{ xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); }catch (e){ window.location="noajax.html"; return false; } } } function pageRequest(page){ xmlhttp.open('GET', page); xmlHttp.onreadystatechange=function(){ if(xmlHttp.readyState==4){ document.getElementById('content').innerHTML=xmlHttp.responseText; }else{ document.getElementById('content').innerHTML='<center><img src="images/loading.gif" alt="Loading" style="border:0px;"/><br />Loading, Please Wait...</center>'; } } xmlhttp.send(null); } </script> Just use the GET method by adding the value to the page name EXAMPLE news.php?value=4 <a href='javascript:pageRequest("news.php?value=4")'> From the file use <?Php echo $_GET['value']; ?> to get the value

Just use the GET method by adding the value to the page name e.g. news.php?value=4 From the file use <?Php echo $_GET['value']; ?> to get the value

Try <?PHP $category = $_GET['category']; $sql = "SELECT * FROM products where category= '$category' "; ?>

try phpmailer