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TomBullock

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Posts posted by TomBullock

    PHP Include Problem

    in PHP Coding Help

    Posted

    As a follow up to this, I tried to use the same code method on another site but the class="current" won't work.

    Here is the code:

     

    <body>
<html>

<?php $page = basename($_SERVER['PHP_SELF']);?>
  
<div class="menu_nav">

<ul>

<?php $class = ($page == 'index.php') ? 'active' : '';?>
<li><a class"<?php echo $class; ?>" href="index.php">Home</a></li>
	  
<?php $class = ($page == 'facilities.php') ? 'active' : '';?>
<li><a class"<?php echo $class; ?>" href="facilities.php">Facilities</a></li>
	  
<?php $class = ($page == 'activities.php') ? 'active' : '';?>
<li><a class"<?php echo $class; ?>" href="activities.php">Activities</a></li>
	  
<?php $class = ($page == 'ssp.php') ? 'active' : '';?>
<li><a class"<?php echo $class; ?>" href="ssp.php">SSP</a></li>
	  
<?php $class = ($page == 'bookings.php') ? 'active' : '';?>
<li><a class"<?php echo $class; ?>" href="bookings.php">Bookings</a></li>
	  
<?php $class = ($page == 'contacts.php') ? 'active' : '';?>
<li><a class"<?php echo $class; ?>" href="contacts.php">Contacts</a></li>

  
</ul>

     

    One thing I did notice is that before adding the inlcude to where the menu would go, the class was set to class="active". I did try changing the all the "current" in the code to "active" but with no joy?

     

    PHP Include Problem

    in PHP Coding Help

    Posted

    Another issue that has arrised (nothing to do with the above code) is with a footer include.

     

    The include code is:

     

    <body>
<html>
<p>
Copyright © 2010 <a href="http://www.company.co.uk">Company</a> · Design by <a href="http://www.designer.co.uk">Designer</a></p>

     

    When I view this in a browser, it gives me:

     

    Copyright © 2010 Company · Design by Designer

     

    I remember reading before that I need to put something before the © and the - but Im not sure if thats the correct way?

    PHP Include Problem

    in PHP Coding Help

    Posted

    Off the top of my head, maybe:

     

    $page = basename($_SERVER['PHP_SELF']);

     

    Then something like this for every link:

     

    <?php $class = ($page == 'index.php') ? 'current' : '';
<li><a class="<?php echo $class; ?>" href="index.php">Home</a></li>

     

    Ahh, thank you! Worked a treat!

    PHP Include Problem

    in PHP Coding Help

    Posted

    Hi

     

    Ive only just started using PHP so go easy :)

     

    I have a PHP include for a menu on a site I run.

     

    <body>
<html>

<ul class="avmenu">

<li><a class="current" href="index.php">Home</a></li>

<li><a href="about.php">About</a></li>

<li><a href="services.php">Services</a></li>

<li><a href="projects.php">Projects</a>

<ul>

<li><a href="highcroft_house.php">Highcroft House</a></li>

<li><a href="barn_conversion.php">Barn Conversion</a></li>

<li><a href="sunroom_extension.php">Sunroom Extension</a></li>

<li><a href="dance_school.php">Dance School</a></li>

</ul>

</li>
<li><a href="testimonials.php">Testimonials</a></li>

<li><a href="offers.php">Special Offers</a></li>

<li><a href="links.php">Links</a></li>

<li><a href="contact.php">Contact</a></li>

</ul>

     

    As you can see, on the first link, the index link, it has the class="current" property which displays a little tab next to the menu to show what link is currently selected.

    With using the include, obviously the class="current" is passed on to every page.

    Is there a way that I can tell the include file to change according to what page its on?

     

    Any help appreciated!

     

    Thanks

    Tom

    Inserting validation into PHP upload script

    in PHP Coding Help

    Posted

    Hello

    I have this script, but i only want it to be able to upload music files, such as mp3, wma and wav.

     

    <?php
//set where you want to store files
//in this example we keep files in folder upload 
//$HTTP_POST_FILES['ufile']['name']; = upload file name
//for example uploads file name cartoon.gif . $path will be uploads/cartoon.gif
$path= "uploads/".$HTTP_POST_FILES['ufile']['name'];
if($ufile !=none)
{
if(copy($HTTP_POST_FILES['ufile']['tmp_name'], $path))
{
echo "Successful<BR/>"; 

//$HTTP_POST_FILES['ufile']['name'] = file name
//$HTTP_POST_FILES['ufile']['size'] = file size
//$HTTP_POST_FILES['ufile']['type'] = type of file
echo "File Name :".$HTTP_POST_FILES['ufile']['name']."<BR/>"; 
echo "File Size :".$HTTP_POST_FILES['ufile']['size']."<BR/>"; 
echo "File Type :".$HTTP_POST_FILES['ufile']['type']."<BR/>"; 
echo "<img src=\"$path\" width=\"150\" height=\"150\">";
}
else
{
echo "Error";
}
}
?>

     

    Can anyone help me so if they try to upload anything apart from the music files i mentioned, they get an error.

     

    Thanks

    Tom Bullock

     

    PHP Shoutcast Script

    in PHP Coding Help

    Posted

    Haha, what a poor insult.

     

    You tell me whats so hard about this:

     

    $server = "000.000.000.000"; // IP Address Of Shoutcast Server.
$port = "000"; // Shoutcast Port
$online = "/images/online.gif"; // Online Image
$offline = "/images/offline.gif"; // Offline Image

     

    Maybe your the big idiot.

    Changing PHP Script

    in PHP Coding Help

    Posted

    Can anyone help me change this script from images to text?

     

    $server = "212.72.165.23"; // IP address to your shoutcast server.
$port = "8681"; // port of your shoutcast server
$online = "http://www.streamsolutions.co.uk/scripts/status_img/online.gif"; // Online Gif image
$offline = "http://www.streamsolutions.co.uk//scripts/status_img/offline.gif"; // offline gif image

    PHP Shoutcast Script

    in PHP Coding Help

    Posted

    Right, what im looking for is a code that i can put into my site. When the Shoutcast server is broadcasting there is a bit of text saying Online in green and when the Shoutcast server isn't broadcasting there is a bit of text saying Offline in red.

    PHP Contact Form

    in PHP Coding Help

    Posted

    How I do is with a form that posts to an external file, then the file routes you to different files depending on whether it was a successful submission.

     

    Here's my form code.  Put something like this on your form page, looks like you have it up there.  Your action should be the other file example: action="feedback.php"

     

    <form name="form" method="post" action="feedback.php">
<p class="bodymd">Your Name<br>
<input type="text" name="name">
</p>
<p class="bodymd">Your Bands Name<br>
<input type="text" name="bname">
</p>
<p class="bodymd">Your Email (for us to get back to you)<br>
<input type="text" name="email">
</p>
<p class="bodymd">Additional Stuff To Add?<br>
<textarea name="comments" rows="5" cols="40"></textarea>
</p>
<p class="bodymd">
<input type="submit" name="Submit" value="Submit" class="mainoption">
<input type="reset" name="Reset" value="Clear Form" class="liteoption">
</p>
</form>

     

    Now the external file:

     

    <?php
// ------------- CONFIGURABLE SECTION ------------------------

// $mailto - set to the email address you want the form
// sent to, eg
//$mailto		= "youremailaddress@example.com" ;

$mailto = 'admin@metalhead.tc' ;

// $subject - set to the Subject line of the email, eg
//$subject	= "Feedback Form" ;

$subject = "Band Forum Request" ;

// the pages to be displayed, eg
//$formurl		= "http://www.example.com/feedback.html" ;
//$errorurl		= "http://www.example.com/error.html" ;
//$thankyouurl	= "http://www.example.com/thankyou.html" ;

$formurl = "http://www.metalhead.tc/heavy-metal-bands-forum.php" ;
$errorurl = "http://www.metalhead.tc/contact-error.php" ;
$thankyouurl = "http://www.metalhead.tc/contact-thanks.php" ;

$uself = 0;

// -------------------- END OF CONFIGURABLE SECTION ---------------

$headersep = (!isset( $uself ) || ($uself == 0)) ? "\r\n" : "\n" ;
$name = $_POST['name'] ;
$bname = $_POST['bname'] ;
$email = $_POST['email'] ;
$comments = $_POST['comments'] ;
$http_referrer = getenv( "HTTP_REFERER" );

if (!isset($_POST['email'])) {
header( "Location: $formurl" );
exit ;
}
if (empty($name) || empty($email) || empty($bname)) 
{
  header( "Location: $errorurl" );
  exit ;
}
if ( ereg( "[\r\n]", $name ) || ereg( "[\r\n]", $email ) ) 
{
header( "Location: $errorurl" );
exit ;
}

if (get_magic_quotes_gpc()) 
{
$comments = stripslashes( $comments );
}

// composing the message to be sent to you

$messageproper =

"This message was sent from:\n" .
"$http_referrer\n" .
"------------------------------------------------------------\n" .
"Your Name: $name\n" .
"Bands Name: $bname\n" . 
"Email: $email\n" .
"------------------------- COMMENTS -------------------------\n\n" .
$comments .
"\n\n------------------------------------------------------------\n" ;

mail($mailto, $subject, $messageproper,
"From: \"$name\" <$email>" . $headersep . "Reply-To: \"$name\" <$email>" . $headersep . "X-Mailer: chfeedback.php 2.08" );
header( "Location: $thankyouurl" );
exit ;

?>

     

    You'll have to add variables to your feedback file depending on the fields in your form.  Make sure your form is right first...

     

    If i used this and added my fields to the form, would i have to add more script into the php script?

    PHP Contact Form

    in PHP Coding Help

    Posted

    Hello

    Im starting my own hosting company and i am offering my client to customize thier own packages.

    I have this code, and i want all the information from it to go to my email.

     

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
</head>

<body>
<form id="form1" name="Custom Quote Form" method="post" action="">
  <u>Contact Information</u><br />
  <br />
  Name:<br />
  <label>
  <input name="Name" type="text" size="20" />
  </label>
  <br />
  E-Mail:<br />
  <label>
  <input name="E-Mail" type="text" size="20" />
  </label>
  <br />
  Address:<br />
  <label>
  <input name="Address" type="text" size="20" />
  </label>
  <br />
  <label></label>
  Town:<br />
<label>
<input name="Town" type="text" size="20" />
</label>
<br />
County:<br />
<label>
<input name="County" type="text" size="20" />
</label>
<br />
Post Code:<br />
<label>
<input name="Post Code" type="text" size="20" maxlength="6" />
</label>
<br />
Country:<br />
<label>
<input name="Country" type="text" size="20" />
</label>
<p><u>Package Information<br />
  <br />
</u>Webspace:<br />
  <label>
    <input name="Webspace" type="text" size="15" />
  </label>
    MB<br />
    Transfer:<br />
    <input name="Transfer" type="text" size="15" />
    MB<br />
E-Mail Boxes:<br />
<input name="E-Mail Boxes" type="text" size="15" />
<br />
Sub-Domains:<br />
<input name="Sub-Domains" type="text" size="15" />
<br />
SQL Databases:<br />
<input name="SQL Databases" type="text" size="15" />
<br />
FTP Accounts:<br />
<input name="FTP Accounts" type="text" size="15" />
</p>
<p>
  <label>
  <input type="submit" name="Submit" value="Submit" />
  </label>
</p>
</form>
<p>  </p>
</body>

</html>

     

    Can anyone tell me where to go from here?

     

    Thankyou

    Tom Bullock

    [SOLVED] Server Status Script

    in PHP Coding Help

    Posted 

    <?php

  $server  = "127.0.0.1";
  $port   = "80";
  $timeout = "10";

  if ($server and $port and $timeout) {
    $verbinding =  @fsockopen("$server", $port, $errno, $errstr, $timeout);
  
  }
  if($verbinding) {
    echo "<img src='./images/on.gif'>Website is online<br>";
  }
  else {
    echo "<img src='./images/off.gif'>Website is offline<br>";
  }
fclose($verbinding);
?>

     

    Yes that is exactly what im looking for except instead of having images to display the status, i need it to be text.

     

    Many thanks

    Tom Bullock  :)

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