fm1
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Everything posted by fm1
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been strugling,how do i sort it out
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what does this mean Warning: include(4darkm.php) [function.include]: failed to open stream: No such file or directory in C:\xampp\htdocs\mysite\Images\includes\template.php(101) : eval()'d code on line 99 Warning: include() [function.include]: Failed opening '4darkm.php' for inclusion (include_path='.;C:\xampp\php\pear\') in C:\xampp\htdocs\mysite\Images\includes\template.php(101) : eval()'d code on line 99
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what do you mean, if you dont understand my question, then how do you build a website, using php only or does it have to be compiled in html
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hi guys,im a bit new to php can you create a full website using just php,for instance, is a php website just php code. or does the website compile of html and added php to give it some features. reason im asking is because i cant find any tutorials on how to make a full php website. should you code the site in html then add php to it
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same result, please correct me, but doesnt the image.php file work as a css file, because i can see the image, if i view it in view.php another Q. how do I view the data inside my tables in my database, the image gets written to the database if im not mitake, whats the syntax to see if it was loaded in the database. if you dont cum rite,thanks anyway for helping
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actually i do, when i view my "view.php" file with code <html> <body> .. <img src="image.php?img=1" border="0" alt="" /> .. </body> </html> i see the pic, but when i open the image.php script in browser i get that error,dont know why
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heres my code <? $dbcnx = mysql_connect("localhost", "fawaaz", "honda"); mysql_select_db("base64imgdb"); $img = $_REQUEST["img"]; $result = mysql_query("SELECT * FROM images WHERE imgid=" . $img . ""); if (!$result) { echo("<b>Error performing query: " . mysql_error() . "</b>"); exit(); } while ($row = mysql_fetch_array($result) ) { $imgid = $row["imgid"]; $encodeddata = $row["sixfourdata"]; } mysql_close($dbcnx); echo base64_decode($encodeddata); ?> and my error Error performing query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 is this a general error, or what am i doing wrong here
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Object not found! The requested URL was not found on this server. The link on the referring page seems to be wrong or outdated. Please inform the author of that page about the error. If you think this is a server error, please contact the webmaster. Error 404 localhost 01/23/08 16:07:42 Apache/2.2.6 (Win32) DAV/2 mod_ssl/2.2.6 OpenSSL/0.9.8e mod_autoindex_color PHP/5.2.4
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Heres my code <? //the host, name, and password for your mysql mysql_connect("localhost","fawaaz","honda"); //select the database mysql_select_db("news"); if($submit) { //use the PHP date function for the time $time=date("h:ia d/j/y"); // inserting it into the shoutbox table which we made in the mysql statements before $result=MYSQL_QUERY("INSERT INTO shoutbox (id,name,message,time)". "VALUES ('NULL','$name', '$message','$time')"); } ?> <? //returning the last 5 messages $result = mysql_query("select * from shoutbox order by id desc limit 5"); //the while loop while($r=mysql_fetch_array($result)) { //getting each variable from the table $time=$r["time"]; $id=$r["id"]; $message=$r["message"]; $name=$r["name"]; ?> <? echo $time ?><br> <? echo $name ?><br> <? echo $message ?><br> <? } ?> <form action="<? echo $php_self ?>" method="post"> <INPUT TYPE='TEXT' value='name' NAME='name' SIZE=30 maxlength='100'><br> <INPUT TYPE='TEXT' value='message' NAME='message' SIZE=30 maxlength='100'> <input type="submit" name="submit" value="submit"> </form> my problem, create database already, when opening script in browser opens fine, but as soon as you fill in the name and comment and press submit,it returns back to the previous page,(like it refreshes),no data is displayed and no data is recorded in mysql
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thanks well I guese im sorted now thanks to you.are you perhaps on msn messenger,gmail or skype, how much years exp you got, i got about only +4months exp,need to learn more
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thanks, both home.php and about.php are working how do i add a link to home.php to link about.php to home. so that when I open home.php then there a link to about.php
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functions.php still blank about.php Fatal error: Call to undefined function display_header() in C:\xampp\htdocs\test3\about.php on line 2 dont you think theres an error maybe in my home.php file. please note, i only have 3 scripts home.php about.php functions.php heres my home.php <html> <head> <title>My Title</title> <style type="text/css"> body{ background-color: black; color: white; } </style> </head> <body> <h1>Page Title</h1> <p>Page content goes here...</p> <p>Copyright 2007 Company Name</p> </html> the other 2scripts are changed to the ones you gave me now
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about.php now comes up with a black screen in browser, no text functions.php is still white in browser. and home.php has text but no links to the other pages
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Hi guys,im trying to create a php template. heres what i done 3 pages page 1 : home.php <html> <head> <title>My Title</title> <style type="text/css"> body{ background-color: black; color: white; } </style> </head> <body> <h1>Page Title</h1> <p>Page content goes here...</p> <p>Copyright 2007 Company Name</p> </html> page opens in browser but has no links to any other pages like my about .php page then page 2: functions.php <?php function display_header($title){ ?> <html> <head> <title><?php echo $title; ?></title> <style type="text/css"> body{ background-color: black; color: white; } <style> </head> <body> <h1><?php echo $title; ?></h1> <?php } function display_footer(){ ?> <p>Copyright 2007 Company Name</p> </html> <?php } ?> nothing just blank white comes out in the browser, dont know why then page 3: about.php <?php include('functions.php'); display_header('About Company Name'); ?> <p>This is the content for the about page...</p> <?php display_footer(); ?> function display_footer(){ ?> <p>Copyright <?php echo date('Y'); ?> Company Name</p> <html> <?php } ?> Parse error: syntax error, unexpected '}' in C:\xampp\htdocs\test3\about.php on line 14 please help, or is there any other easier way to create a std php web template
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Kinda a lot to ask but try this: <?php if (isset($_POST['submit'])){ $uname = mysql_escape_string($_POST['uname']); $pass = mysql_escape_string($_POST['pass']); $ver_pass = mysql_escape_string($_POST['vpass']); $email = mysql_escape_string($_POST['email']); $mobile = mysql_escape_string($_POST['mobile']); if ($pass == $ver_pass){ // need help here. What should the message be? $msg = ""; // edit in admin email mail("admin_email", "subject", $msg); }} <form method='post'> <input type='text' name='uname' /><br /> <input type='password' name='pass' /><br /> <input type='password' name='ver_pass' /><br /> <input type='text' name='email' /><br /> <input type='text' name='mobile' /><br /> <input type='submit' name='submit' value='submit' /> </form> ?> Something like that? with the above script results return syntax error in line 17
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I dont need you to write the whole script,i need guid lines,u didnt know what i meant so I posted what im trying to do,how do i recall the information from an sql databse i created so that its displayed as a form in the web webrowser,
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I see where you coming at but is this script somhow connected to the mysql database "members" ,this is the original project details if it might help, you script looks like a standlone form,am i wrong Code an php web form . The form must accept and store a user's details. It must then retrieve/update/edit those details from the SQL DB and display it. Some of the fields will include: username password verify password email address mobile Please note: Validation is required on all fields Access must be through stored procedures No SQL allowed in code
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okay basically what i mean is , now that I got the databse created with the tables,the sql part is done, now i want to create a new php script, and when i open up that script in my browser the follwing script i created should open with the following fields to fill in and submit username: password: verifypassword: email address: mobile: then the visitor should type in their details and click submit, then those details should go to the admins email address, in other words its a web form whereby the data should be retrieved, stored,updated and editted by the mysql database members that I created earlier. is this info im giving sounding dumb, if yes can you guys offer a better solution to the problem
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i have phpmyadmin but why would i need to edit the database if it was already created with the above table statement, all I need now is to publish this database in a php script so that it can be used
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that was a quick reply you see, i need to able to open the form in a web browser, but obv in order to do that you need to compile a php script, what should my script look like
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hi guys im noobie and very new to php, im trying to learn php on my own seeing that I dont have the funds to attend any lessons. I need to create a webform, but firstly i need to create a table in mysql, im struggling for 2days now, how do i do this what i done so far, 1. logged into mysql(obv) 2.created the database called members what i need is a table called dbUsers with the following fields: username password verify password email address mobile from there i need to access this database using a php script(dont know what to do here) so that users can access the webform and fill in the details any help on this guys