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darphas

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About darphas

  • Birthday 05/01/1990

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  1. i tried this code and workds perfect show the actual time of my city but the code what i want is flettching the time stored in a database... <?php date_default_timezone_set("America/Monterrey"); echo "La hora en Victoria es: " . date ("H:i:s",time()) . "<br />"; ?>
  2. hello i have a shared hosting in hostgator so, i cant change the default server clock. then i code a script to show my local city date, but doesnt work. anyone can help me? function muestrafecha($fecha){ $mes[1]="Enero"; $mes[2]="Febrero"; $mes[3]="Marzo"; $mes[4]="Abril"; $mes[5]="Mayo"; $mes[6]="Junio"; $mes[7]="Julio"; $mes[8]="Agosto"; $mes[9]="Septiembre"; $mes[10]="Octubre"; $mes[11]="Noviembre"; $mes[12]="Diciembre"; date_default_timezone_set("America/Monterrey"); return date("j",$fecha).' '.$mes[date("n",$fecha)].' '.date("Y",$fecha).'('.date("H:i:s",$fecha).')'; return $muestra; } the date works perfect, but the time zone appears + hour
  3. Somethink like this <div class="MyDiv"> <h2>Title</h2> <p>Description</p> <img src="photo/img1.jpg"> </div> a little title with info and sometimes images.
  4. I'm making a system and i want to add a button that if you click it.. will send some info from a div to a friend, but to be honest i dont have any idea how can i do this.. i used google to find info and i think is something like that can works <?php if (isset($_POST['email'])) { $to = "friendemail"; $subject = "Website Info"; $email = 'email'; $message = ???div content???; $headers = "From: $email"; $sent = mail($to, $subject, $message, $headers); if ($sent) { echo "<script>alert('Email has been sent')</script>"; } else { echo "<script>alert('Sorry Cannot send this email')</script>"; } } ?> the div sometimes contains images so i think this can help $str=htmlspecialchars("<div>testing the div</div>", ENT_QUOTES); $message = $str; $message =htmlspecialchars_decode($orignal_msg_body); Please help. x.x
  5. Hi, i have a catalog that display 6 pictures in every item.. sometimes i need to send a specific photho from the item very quickly.. but i cant i tried everthing.. the process that i do is download the image and send it in outlook.. and thats very very low process! i try this code. Config mysql_query( "SELECT photo_caption,photo_description,photo_code,photo_filename,photo_filename2,photo_filename3,photo_filename4,photo_filename5,photo_filename6,photos FROM gallery_photos WHERE photo_id='".addslashes($pid)."'" ); list($photo_caption,$photo_description,$photo_code,$photo_filename,$photo_filename2,$photo_filename3,$photo_filename4,$photo_filename5,$photo_filename6,$photos) = mysql_fetch_array( $result ); <?php include_once('./phpMailer_v2.3/class.phpmailer.php'); $mail = new PHPMailer(); // defaults to using php "mail()" $body = "<body><img src='".$images_dir."/".$photo_filename."'></body>"; $mail->From = "[email protected]"; $mail->FromName = "First Last"; $mail->Subject = "Test Subject via mail()"; $mail->AltBody = "To view the message, please use an HTML compatible email viewer!"; // optional, comment out and test $mail->MsgHTML($body); $mail->AddAddress("[email protected]", "John Philips"); //$mail->AddAttachment("images/phpmailer.gif"); // attachment if(!$mail->Send()) { echo "Mailer Error: " . $mail->ErrorInfo; } else { echo "Message sent!"; } ?> i;m newbie in php i try some crazy things only if works but no all the time..
  6. i want to print a variable if existe in a costum field on mysql database for example, the problem is that a make id query like index.php?id=1, index.php?id=2, etc.. and for example only the id=3 have a content in var. php code: $myvar="somecode or thins here" mysql table: name: Horse description: Black and 4 years old var:$myvar php code: function printvar(&$myvar) { if (isset($myvar)) { echo $myvar; } } i don't know what it happens but doesnt work please help
  7. ok the problem is if i try to add andother row in the table.. all the other products have too an other space. and i only want to add more photho in a specific products but i dont know how i can make this change in that mini system. thanks for your reply jessica.
  8. Hello everybody.. I'm a kind of newbie in php coding. i'm making a online catalog, of my dads company. it's works perfect but in some products i want to show more photos and i cant and when i add one more in a product all the other products appears the problem. i dont know what i can so to solve this problem. please help me. Database: Table: and here is the code that i use to show the images... $result = mysql_query( "SELECT photo_caption,photo_description,photo_code,photo_filename,photo_filename2,photo_filename3,photo_filename4,photo_filename5,photo_filename6 FROM gallery_photos WHERE photo_id='".addslashes($pid)."'" ); list($photo_caption,$photo_description,$photo_code,$photo_filename,$photo_filename2,$photo_filename3,$photo_filename4,$photo_filename5,$photo_filename6) = mysql_fetch_array( $result ); $nr = mysql_num_rows( $result ); mysql_free_result( $result ); if( empty( $nr ) ) { $result_final = "\t<tr><td>There is no Photos</td></tr>\n"; } else { $result = mysql_query( "SELECT category_name FROM gallery_category WHERE category_id='".addslashes($cid)."'" ); list($category_name) = mysql_fetch_array( $result ); mysql_free_result( $result ); $result_final .= " <div class='baseline'> <ul> <li><a href='javascript:history.back()'>Back</a> </li> <li><a href='index.php?pag=gallery'>Categories</a> </li> <li><a href='index.php?pag=ver&cid=$cid'>$category_name</a></li> </ul> <br style='clear:left;'/> </div> "; $result_final .= " <div class='descripcion'> <div id='slides'> <div class='slides_container'> <img src='".$images_dir."/".$photo_filename."' width='640' height='480' border='0' alt='Slide 1'/> <img src='".$images_dir."/".$photo_filename2."' width='640' height='480' border='0' alt='Slide 2'/> <img src='".$images_dir."/".$photo_filename3."' width='640' height='480' border='0' alt='Slide 3'/> <img src='".$images_dir."/".$photo_filename4."' width='640' height='480' border='0' alt='Slide 4'/> <img src='".$images_dir."/".$photo_filename5."' width='640' height='480' border='0' alt='Slide 5'/> <img src='".$images_dir."/".$photo_filename6."' width='640' height='480' border='0' alt='Slide 6'/> </div> <a href='#' class='prev'><img src='img/prev.png' width='28' height='44' alt='Arrow Prev'></a> <a href='#' class='next'><img src='img/next.png' width='28' height='44' alt='Arrow Next'></a> </div> <div class='textodesc'> <h2>$photo_caption</h2> <p><b></br></b>$photo_description</p> </div></div> "; } } and this is how appears in the browser
  9. Thank you very much!
  10. great brow.. and the link looks like?
  11. i'm making a online catalog. upload images to the server and save the nanem in the db like 92.jpg,93.jpg etc.. so i wanto to know how to make a button to download the images.. i tried to put the url of the image but only display it in the browser. so please help.
  12. oh my god! thank you very much! it works perfect
  13. hello everybody. i'm making a online catalog and i have all it done, but i want to include a button to send the page product for e-mail or print it, so i want to know how i can search it in google or how is named kind of button to find examples or how it works.. please help. i'm newbie in php.
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