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rockindano30

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Posts posted by rockindano30

    [SOLVED] media player for videos on website

    in Miscellaneous

    Posted

    this is how i solved it using js.

     

    <html>
<head>
<title>Embed Media Player</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<script type"text/javascript">
function PlayMedia(clipName){
document.getElementById("player").innerHTML='<object id="mediaPlayer" width="265" height="190" '
      +'classid="CLSID:22d6f312-b0f6-11d0-94ab-0080c74c7e95" '
      +'codebase="http://activex.microsoft.com/activex/controls/mplayer/en/nsmp2inf.cab#Version=5,1,52,701" '
      +'standby="Loading Microsoft Windows Media Player components..." type="application/x-oleobject">'
      +'<param name="fileName" value="'+clipName+'">'
      +'<param name="autoStart" value="true">'
      +'<param name="showControls" value="true">'
      +'<param name="ShowStatusBar" value="1">'
      +'<param name="loop" value="false">'
      +'<embed type="application/x-mplayer2" '
      +'pluginspage="http://microsoft.com/windows/mediaplayer/en/download/" '
      +'showcontrols="true" width="265" height="190" '
      +'src="'+clipName+'" autostart="true" loop="false">'
      +'</embed>'
     +'</object>'
}
</script>
<style type="text/css">
<!--
#playerframe {
width: 268px;
position: relative;
padding: 5px;
}
#playerframe ul {
background-color: #590002;
padding: 0px;
}
#playerframe a {
line-height: 35px;
text-decoration: none;
display: block;
color: #CCCCCC;
padding: 5px;
}
#playerframe a:hover {
background-color: #800003;
border: 1px solid #CCCCCC;
}
#playerframe li {
list-style-type: none;
display: block;
}
-->
</style>
<script src="Scripts/AC_ActiveX.js" type="text/javascript"></script>
<script src="Scripts/AC_RunActiveContent.js" type="text/javascript"></script>
</head>
<body>
<div id="playerframe">
<div id="player">
  <script type="text/javascript">
AC_AX_RunContent( 'id','mediaPlayer','codebase','http://activex.microsoft.com/activex/controls/mplayer/en/nsmp2inf.cab#Version=5,1,52,701','type','application/x-oleobject','width','265','height','190','standby','Loading Microsoft Windows Media Player components...','classid','CLSID:22d6f312-b0f6-11d0-94ab-0080c74c7e95','pluginspage','http://microsoft.com/windows/mediaplayer/en/download/','showcontrols','true','src','','autostart','true','loop','false','filename','','showstatusbar','1' ); //end AC code
</script><noscript><object id="mediaPlayer"
                  codeBase="http://activex.microsoft.com/activex/controls/mplayer/en/nsmp2inf.cab#Version=5,1,52,701"
                  type="application/x-oleobject"
                  width=265
                  height="190" 
                  standby="Loading Microsoft Windows Media Player components..." 
                  classid=CLSID:22d6f312-b0f6-11d0-94ab-0080c74c7e95>
    <PARAM NAME="fileName" VALUE="" />
    <PARAM NAME="autoStart" VALUE="true" />
    <PARAM NAME="showControls" VALUE="true" />
    <PARAM NAME="ShowStatusBar" VALUE="1" />
    <PARAM NAME="loop" VALUE="false" />
    <embed
                  	type="application/x-mplayer2"         
                    pluginspage="http://microsoft.com/windows/mediaplayer/en/download/" 
                    showcontrols="true" 
                    width="265" 
                  	height="190"
                  	src="" autostart="true" 
                  	loop="false">
  </embed></object></noscript>
</div>
<ul>
  <li><a href="http://link.to.your.clip.here.mpg" onClick="PlayMedia(this.href);return false">Video one </a></li>
  <li><a href="http://link.to.different.clip.here.mpg" onClick="PlayMedia(this.href);return false">Video Two</a></li>
  <li><a href="http://link.to.different.clip.here.mpg" onClick="PlayMedia(this.href);return false">Video Three</a></li>
</ul>
</div>
</body>
</html>

    hosting multiple sites

    in Apache HTTP Server

    Posted

    hello all,

     

    well i have a webserver that i'm working on. now for all my websites i used apache/php/mysql. my question is how do i host three or multiple website in my server using apache as a server with php/mysql? no i have to set it up in the config file for apache if so how would i go about that?

    [SOLVED] help with login php script and forms

    in PHP Coding Help

    Posted

    Hi everyone,

     

    i am working on a app. for a client. now i have my login.php page with a simple form. this page calls my validation2.php page and then validation2 page calls my update page.

     

    now when i type in the user name and password, my validation page displays my error that i have:

     

    "invalid username and password. login first"

     

    but if i hit go back on my browser and refresh the page and retype the info, it logs me in. i typed my info in correctly. but seems that the first time that i run it it doesn't finds anything in the mysql table users, so when i go back and refresh and retype it finds it in the table and continues with the update form.??? ??? ???

     

    i will be including my files here:

     

    login.php

      <form method="post" action="validate2.php">
    User Name:<Br />
      <input name="user_name" type="text" value=" " size="15" maxlength="25" /><br /><br />
      Password:<br />
  <input name="psswrd" type="password" value="" size="15" maxlength="25" /><br /><br />
      <input name="submit" type="submit" value="Login" />
</form>

     

    validate2.php

    			<?php 
			if(!isset($_POST["user_name"]) || !isset($_POST["psswrd"]))
			die("invalid operation");
			$goback = "<br /><br />Please <a href=\"login.php\">go back</a> and try again.";

			//print "$_POST[\"user_name\"]<br />";
			if(empty($_POST["user_name"])) die("<br />The email field cannot be left blank.");
			if(empty($_POST["psswrd"])) die("<br />The Password field cannot be left blank");
			$user_name = $_POST["user_name"];
			$psswrd = md5(trim($_POST["psswrd"]));

			if (!($db = mysql_connect('localhost','user_db','db_password')))
			{
				print"Error: could not connect to the database.";
				exit;
			}
			mysql_select_db(test);

//$query = "SELECT * FROM users WHERE user_name='{$_POST['user_name']}' AND psswrd='{$_POST['psswrd']}'";
			$query = "SELECT * FROM users WHERE user_name = '{$user_name}' AND psswrd = '{$psswrd}'";
			$result = mysql_query($query);

			if(mysql_num_rows($result)==0)
			die("<br />Invalid email or passwordmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm!<br />{$goback}");

			$row = @ mysql_fetch_array($result);
			session_start();
			$_SESSION["user_id"]=$row["user_id"];
			$_SESSION["ip_addr"]=$_SERVER["REMOTE_ADDR"];
			$_SESSION["user_name"]=$row["user_name"];
			header("LOCATION: update.php");
		?>

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