pommi

sadly no good

Just tried declaring the $row, no luck sadly... $row is the variable storing the results of my sql call "$row = mysql_fetch_array( $mysql )" So I know the the values are passing into the variable $row, but they don't seem to be feeding into the cost in my previous comment, and I am receiving the error msg i posted

Ok, the error I am receiving is: "Fatal error: Cannot use string offset as an array in" I know the database query is working and passing a value.... I believe its some issue with PHP5 but I can't find the answer anywhere.... and anyone help?? $card[] = array( id => $row['id'], name => $row['name'], bt_period => $row['bt_period'], transfer_rate => $row['transfer_rate'], fee => ($row['fee'] + $row['reward_fee']), rewards => $row['rewards'], interest_free => $row['interest_free'], image => $row['img'], url => $row['link'] );

seems to be a problem with my query / mysql database.... but the strange thing is it works perfeclty on my test server but not the prod server. They both are running PHP 5 and MySQL client version: 5.0.22 (test) MySQL client version: 5.0.45 (prod) can anyone tell me why I may get a different result from the two machines??

Can some one please help, I have a problem with my code which I believe I have isolated to some where here. The code seems to stop after "print "<p><img src='../font/images/divider.jpg' /></p>";" Any ideas??? $x = 5; $row = 0; array_multisort($card, SORT_DESC); //Sort Array while ($row < $x) { //Divider print "<p><img src='../font/images/divider.jpg' /></p>"; //table results print $query; print "<p><a href='../creditcard_features.php?id=" . $card[$row]["id"] . "'>" . $card[$row]["bank"] . " " . $card[$row]["name"] . " - More Details</a></p>"; print "<table>"; //Interest Rate, Fee and Score print "<tr><td class='tbl_title'>Interest Rate</td><td class='tbl_title'>Annual Fee</td><td class='tbl_title'>Score</td><td></td></tr>"; print "<tr><td class='tbl_text'>" . $card[$row]["rate"] . "%</td>"; print "<td class='tbl_text'>$" . $card[$row]["fee"] . "</td>"; print "<td class='tbl_score'>" . $card[$row]["score"] . "</td></tr>"; print "<tr><td class='tbl_text'><a href=../creditcard_features.php?id=" . $card[$row]["id"] . "><img class=img src=../images/cards/" . $card[$row]["image"] . " /></a></td>"; print "<td class='tbl_text'><p>" . $card[$row]["interest_free"] . " days interest free</p>"; //Balance Tranfer if($card[$row]["balance_transfer"] == "Yes") { print $card[$row]["transfer_rate"] . "% balance transfer"; if(!empty($card[$row]["bt_period"])) { print " for " . $card[$row]["bt_period"] ;} print "</td>"; } //Apply session_start(); $campaign = $_SESSION['campaign']; print "<td class='tbl_text'><a href='../tracking.php?id=" . $card[$row]["id"] . "&campaign=" . $campaign . "' target='_blank'><img src='../font/images/appy_now.jpg' class='img' alt='Apply Online' /></a></td></tr>"; //Obtain Card Ranking Result print "<tr><td class=main colspan='3' class='tbl_text'>"; require'../search_rank_script.php'; //Rank Card print "<a href='../rank_menu?cr=" . $card[$row]["id"] . "#' class=menuLink2>Rate the " . $card[$row]["bank"] . " " . $card[$row]["name"] . "card</a></td></tr></table>"; $row++; }

Thanks guys... to answer my question I assume I can add a switch within an If statement. The problem though is within my coding... Thanks!!

Hi Guys.... this will probably be an easy question. Can you use swtich statements within an if statement... So for example what i want to do it if(!empty($aa)) { switch($aa) { case: 1 break; case 2: break; } else switch($bb) { case:1 break; case: 2 break; } } I have writen some code in this format and it isnt working?? Can anyone help... Thanks ???

Thanks for the comments, took your advice and agree it is looking better!!

I have recently re-designed my site, I would love your feedback. Thanks www.CreditCardBroker.com.au