Jump to content

terrymechan

New Members
  • Posts

    1
  • Joined

  • Last visited

    Never

Posts posted by terrymechan

  1. I have a code problem

     

    I havea list/menu box in a form, which will be updated on submission

     

    The list is a list of countries from a My Sql Table.

     

    I wish to pre-enter the record which already exists, which I can do from identifying the Unique record ID.

     

    However, I then want the drop down box reveal all the countries listed in that table

     

    For some reason, I can either populate the drop down list with this coding

     

    <select name="Ecom_ShipTo_Postal_CountryCode" >

    <?php

    while(!$countrylist->EOF){

    ?>

    <option value="<?php echo $countrylist->Fields('COUNTRY')?>"><?php echo $countrylist->Fields('COUNTRY')?></option>

    <?php

    $countrylist->MoveNext();

    }

    $countrylist->MoveFirst();

    ?>

     

    or insert the existing choice of the user, by adding this code.

     

    <select name="Ecom_ShipTo_Postal_CountryCode" title="<?php echo $existingrecord->Fields('Country'); ?>" >

     

    <?php

    while(!$countrylist->EOF){

    ?>

    <option value="<?php echo $countrylist->Fields('COUNTRY')?>"><?php echo $countrylist->Fields('COUNTRY')?></option>

    <?php

    $countrylist->MoveNext();

    }

    $countrylist->MoveFirst();

    ?>

    </select>

     

    What I need is code which will display the existing entry, AND allow the drop down list box to display the countries from the MYsql table

     

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.