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with curl i want to send this form http://dezend.me/dezend/ <form method="post" action="process.php" enctype="multipart/form-data"> <input type="file" name="bestand"><br> <input type="submit" name="upload" value="uploaden"> </form> this is sended via form into this url http://dezend.me/dezend/process.php -----------------------------146043902153 Content-Disposition: form-data; name="bestand"; filename="fileupload.php" Content-Type: text/php <?php some php file ... ?> -----------------------------146043902153 Content-Disposition: form-data; name="upload" uploaden -----------------------------146043902153--

How to send multipart/form-data ? via curl or so ... here i am going to send it - http://dezend.me/dezend/

i need to decode that file, normal download that file from mediafire and open - this is what i want, i dont want nothing decode on mediafire

i need to see source code not that crappy code ones, also it wont require any loader or what just replace eval to **** and u see source code but this for me wont works :/

i mean how to decode that file inside that zip, i am uploaded that file on medaifire

How to decode this? http://www.mediafire.com/?niwske5oy33wzrz