kasitzboym

Merry Christmas to you to!!!!

You know what i figured figured it out... i dont know why but it didnt like the number in the if statement i changed it to this and i had the variable set like $size = $_FILES["upload"]["size"]; i just type it like that when i was on here... but changing it to a variable seamed to have worked... ill have to do more reading on it maybe it is a bug in PHP they haven't found yet or something... But Anyway thanks for the help!!! $size = $_FILES["upload"]["size"]; $max_file_size = 1024000; if($size > $max_file_size){ echo'entered if statement<br />'; } else{ echo'entered else statement<br />'; }

Thanks but im having more trouble with this than i am with my if else statement... If i take out the statement and just echo $_FILES["upload"]["size"] then it prints out the file size every time its just when i have it in an if statement that it has trouble. Any other ideas? i really would like to use this setup.

I am trying to check to see if a file size is acceptable before an upload but cant seem to get the right result no matter what i do. if i have my if statement below coded like this if($_FILES["upload"]["size"] < 1024000){ echo'entered if statement<br />'; } else{ echo'entered else statement<br />'; } Then i always am entereing the if statememnt but if i have my if statement like this if($_FILES["upload"]["size"] > 1024000){ echo'entered if statement<br />'; } else{ echo'entered else statement<br />'; } then i always seem to enter the else staement. I have tried with a VIREITY of differnt size files some from like 2kb to 10mb... i believe somewhere near the > or < is my problem but i dont seem to see it

Awesome thanks again!

Hey guys there is probably a simple fix to this but i am just not seeing it ... Im createing a form that has error catching and self submitting valuse. I am trying to use a for loop to create all of the values and if the form is returned with an error then the correct values will still be filled out but i cant seem to get this loop to work. Every time i submit the form it doesnt matter what option i select it always comes back with the last one in the list or 30 in this case. the problem code is below.. Any help would be appreciated. <?php for($i=1; $i<=30; $i++){ echo'<option value="'.$i.'"'; if(isset($_POST['petsAge'])== $i){ echo ' selected="selected"';} echo '>'.$i.'</option>'; } ?>

That kind of makes since. Although i am kind of lost on the syntax that you are explaining do you mean someting like this? <?php require("includes_database/mysqli_connect.php"); //$query="SELECT * FROM phpbb_topics WHERE (forum_id='13' OR forum_id='14') AND topic_status = '0'"; //$query2="SELECT * FROM phpbb_topics WHERE (forum_id='15' OR forum_id='16') AND topic_status = '0'"; $query="SELECT * FROM phpbb_topics WHERE (forum_id='13' OR forum_id='14')"; $query2="SELECT * FROM phpbb_topics WHERE (forum_id='15' OR forum_id='16')"; $result=mysqli_query($dbc, $query); $result2=mysqli_query($dbc, $query2); $num = mysqli_num_rows($result); $num2 = mysqli_num_rows($result2); echo''.count($num).'<br>'; echo''.count($num2).'<br>'; echo "<table border=1 cellpadding=2>"; echo "<tr><td>Lost</td><td>Found</td></tr>"; while(($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) && ($row2 = mysqli_fetch_array($result2, MYSQLI_ASSOC))) { echo'<tr>'; if ($row){ while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){ echo "<td width='15%'><a href=/sahbb/viewtopic.php?f=".$row['forum_id']."&t=".$row['topic_id'].">".$row['topic_title']."</a></td>"; } } if($row2){ while($row2 = mysqli_fetch_array($result2, MYSQLI_ASSOC)){ echo "<td width='15%'><a href=/sahbb/viewtopic.php?f=".$row2['forum_id']."&t=".$row2['topic_id'].">".$row2['topic_title']."</a></td>"; } } echo'</tr>'; } echo "</table>"; mysqli_free_result($result); mysqli_free_result($result2); mysqli_close($dbc); ?>

This seems to have returned the same result as my version. ManiacDan I will try this however i would like to keep a single table with two columns instead of splitting them up They are currently using the same div tag as they are both in a marque that scrolls.

Hey everyone I've been working on converting my old mysql code to to the mysqli version and am running into some trouble. I am pulling posts form phpbb and displaying them in a script. My first script below works just fine. <?php require("connect.php"); $query="SELECT * FROM phpbb_topics WHERE (forum_id='13' OR forum_id='14') AND topic_status = '0'"; $query2="SELECT * FROM phpbb_topics WHERE (forum_id='15' OR forum_id='16') AND topic_status = '0'"; $result=mysql_query($query); $result2=mysql_query($query2); echo "<table border=0 cellpadding=2>"; echo "<tr><td>Lost</td><td>Found</td></tr>"; while($row=(mysql_fetch_array($result)) || $row2=(mysql_fetch_array($result2))) { $forum_id=mysql_result($result,$k,"forum_id"); $topic_id=mysql_result($result,$k,"topic_id"); $topic_title=mysql_result($result,$k,"topic_title"); $forum_id2=mysql_result($result2,$k,"forum_id"); $topic_id2=mysql_result($result2,$k,"topic_id"); $topic_title2=mysql_result($result2,$k,"topic_title"); echo "<tr><td width='15%'><a href=/sahbb/viewtopic.php?f=$forum_id&t=$topic_id>$topic_title</a></td> <td width='15%'><a href=/sahbb/viewtopic.php?f=$forum_id2&t=$topic_id2>$topic_title2</a></td> </tr>"; $k++; } echo "</table>"; mysql_close($connect); ?> however its not very clean or memory efficient so i have converted it to the following. <?php require("includes_database/mysqli_connect.php"); $query="SELECT * FROM phpbb_topics WHERE (forum_id='13' OR forum_id='14')"; $query2="SELECT * FROM phpbb_topics WHERE (forum_id='15' OR forum_id='16')"; $result=mysqli_query($dbc, $query); $result2=mysqli_query($dbc, $query2); echo "<table border=1 cellpadding=2>"; echo "<tr><td>Lost</td><td>Found</td></tr>"; while(($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) || ($row2 = mysqli_fetch_array($result2, MYSQLI_ASSOC))) { echo "<tr><td width='15%'><a href=/sahbb/viewtopic.php?f=".$row['forum_id']."&t=".$row['topic_id'].">".$row['topic_title']."</a></td> <td width='15%'><a href=/sahbb/viewtopic.php?f=".$row2['forum_id']."&t=".$row2['topic_id'].">".$row2['topic_title']."</a></td> </tr>"; } echo "</table>"; mysqli_free_result($result); mysqli_free_result($result2); mysqli_close($dbc); ?> I know the error is in my while loop but i cant seem to figure out exactly where. The new code displays all of the first query in the table and then below that it displays the next query insted of displaying them side by side below would be an example of what is happening [table Lost Found Lost, Australian Sheppard [/td] Lost German Shepherded / Collie Mix Lost Golden Retriever/Cocker Mix Lost Female Grey Tiger Lost Pitbull Mix Lost 2 Chihuahua Lost Black Lab Lost - German Shepard Mix and Lab Mix Lost - Female German Sheperd Aprox 8 Week Old Kitten Found! 2 Pugs FOUND Found 1 Corgi female/ 1 Shih Tzu male Found Tan and Black Australian Shepard Found Australian Shepard [td]Found Intact Male Pitbull/Lab Mix Any help that any of you could provide would be greatly appreciated!