jamjam

Hi This is really driving me crazy, so please help. I have this code as shown below, it displays a list of dates for the next 7 days. Things i want the code achieve. 1. Display "Today and "Tomorrow" instead of the corresponding date. 2. Once a date is selected add "current" class, this way it is highlighted with a different color. 3. "Today" should be selected by default when the page is first loaded. The code below achieve this requirements <?php $today = date("d-m-Y", strtotime('today')); $tomorrow = date("d-m-Y", strtotime('tomorrow')); echo ' <li><a href="?date='.$today.'">'.(($_GET['date'] == $today) ? '<span class="current"' . '>Today</span>' : 'Today').'</a></li>'; echo ' <li><a href="?date='.$tomorrow.'">'.(($_GET['date'] == $tomorrow) ? '<span class="current"' . '>Tomorrow</span>' : 'Tomorrow').'</a></li>'; for ($time = strtotime('+2 days'), $i=0; $i < 5; $time = strtotime('+1 days', $time), $i++) {$date = date("d-m-Y", $time); echo ' <li><a href="?date='.$date.'">'.(($_GET['date'] == $date) ? '<span class="current">' : '') . date("D jS", $time) . ((isset($_GET['date']) && $_GET['date'] == $date) ? '</span>' : '') . "</a></li>";} ?> However recently i needed to change the formating of the date from d-m-Y to Y-m-d As result of this my third requirement the one about "Today" been selected by default no longer works. <?php $today = date("Y-m-d", strtotime('today')); $tomorrow = date("Y-m-d", strtotime('tomorrow')); echo ' <li><a href="?date='.$today.'">'.(($_GET['date'] == $today) ? '<span class="current"' . '>Today</span>' : 'Today').'</a></li>'; echo ' <li><a href="?date='.$tomorrow.'">'.(($_GET['date'] == $tomorrow) ? '<span class="current"' . '>Tomorrow</span>' : 'Tomorrow').'</a></li>'; for ($time = strtotime('+2 days'), $i=0; $i < 5; $time = strtotime('+1 days', $time), $i++) {$date = date("Y-m-d", $time); echo ' <li><a href="?date='.$date.'">'.(($_GET['date'] == $date) ? '<span class="current">' : '') . date("D jS", $time) . ((isset($_GET['date']) && $_GET['date'] == $date) ? '</span>' : '') . "</a></li>";} ?> Can someone please help with this. Thanks in advance

Hi I am complete javascrpt newbie, I have this script. Not my work. function fav() { var newT = document.createTextNode('Add to Favourites'); var s = document.getElementById('fav'); if (window.sidebar) { s.appendChild(newT); s.style.cursor = 'pointer'; s.onclick = function() {window.sidebar.addPanel(document.title,self.location,'')}; } else if (window.external) { s.appendChild(newT); s.style.cursor = 'pointer'; s.onclick = function() {window.external.AddFavorite(self.location,document.title)}; } else if (window.opera) { s.appendChild(newT); s.style.cursor = 'pointer'; s.onclick = function() { var e = document.createElement('a'); e.setAttribute('href',self.location); e.setAttribute('title',document.title); e.setAttribute('rel','sidebar'); e.click(); } } } var pageLoaded = 0; window.onload = function() {pageLoaded = 1;} function loaded(i,f) { if (document.getElementById && document.getElementById(i) != null) f(); else if (!pageLoaded) setTimeout('loaded(\''+i+'\','+f+')',100); } loaded('fav',fav); The script adds a add to favourites link to a page. This works without any problems. My intention is to adapt the script so instead of outputting a link(text) it outputs a image. But I don't how to do this. Please help. Thanks

I worked it out It seems there was conflicting class as when I added "email" nothing was showing up. Chooosing a different class solved the problem.

Hi This is very silly question, but can someone please tell what is wrong. I have a small piece of javascript code Here it is. google.load("jquery", "1.3.1"); jQuery.fn.fadeToggle = function(speed, easing, callback) { return this.animate({opacity: 'toggle'}, speed, easing, callback); }; $(document).ready(function() { $('#tellfriend').hide(); $('li a.email, #tellfriend a.close').click(function() { $("#tellfriend").fadeToggle('slow'); }); }); Once a email icon button is clicked this code fades in a email form. The associated html looks like this <li><a class="email" href="#tellafreiend" alt="Email" id="emails">Email</a></li> This all works. But I need to change the associated html to something like this <li><a href="#tellafreiend" alt="Email"><img src="/files/email.png" alt="Email"/></a></li> However once I do this the fade in effect no longer works and I do not see the email form. I know the problem is properly a result of incorrect class or id. But I cannot fix it. Thanks.

YES Finally it worked. However the HTML formatting got lost along the way. So have to figure that out now. Thanks for all your help guys.

YES Finally this works. But the my original HTML formatting has been lost. So I have to figure how to but this back. Thanks for all your help guys.

Hi Pikachu2000 When I tried your solution I got this error Notice: Undefined variable: totalRows in F:\wamp\www\includes\info\credits.php on line 6 I think I fixed by changing totalRows to totalRows_director Having done this, I get blank results with this code. Even though the director field contains at least 2 rows of data.

Hi litebearer I tried your solution but there seems to be syntax errors. I replace the double quotes with single quotes and that did reduce the error but there is at lease one syntax error I am unable to fix. Please double check Thanks

That's what I am trying to do but I don't how to. Can you show me how achieve this?

If your referend to the database connection etc litebearer here it is mysql_select_db($database_main, $main); $query_director = "SELECT information.title, director FROM information INNER JOIN director ON information.title = director.title"; $director = mysql_query($query_director, $main) or die(mysql_error()); $row_director = mysql_fetch_assoc($director); $totalRows_director = mysql_num_rows($director); HTML <?php if($row_director['director'] == "") {echo "";} else {echo " <table> <th> <h4>Directed by</h4> </th> <td> <h5> $row_director['director'] </h5> <br /> </td> </table> <br /> ";}?> I can echo all results contained in the $director['director'] quite easily, the problem is that I want place these results inside an if else statment. This way if $director['director'] is empty then the html is not displayed. Hope that makes sense

Hello Thanks for the quick reply. Your solution looks good but it don't work. I want to echo all the results in {$row_director['director']}. But this is only one result showing in the browser. The database table contains two rows and I wanted to output both to show the while is working. Thanks again

I want to control the output of php code with if else statement like this. <?php if($row_director['director'] == "") {echo "";} else {echo " <table> <th> <h4>Directed by</h4> </th> <td> <h5> $row_director['director'] </h5> <br /> </td> </table> <br /> ";}?> I also want to loop through the results contained in $row_director['director'] Having tried various ways to achieve this, I have now given up. Can someone please help me.

Thanks Matthew It worked perfectly.

Hi I am developing a page that has this PHP code <?php echo $row_Programme['status']; ?> This code basically looks in a MySQL database table and echo’s the value of the status field. The value of the Status field will only ever have 5 possible values. I want to add an ‘if statement’ to the above code. So for example if the value returned by the code was “Coming Soon” I can add something like “Programme will be available soon” A second example would be if the value returned by the code was “Not Available” I can add something like “Sorry programme is not available” This properly really basic PHP. But am really new to this and will really appreciate the assistance. Thanks in advance.

Any one? Please help me.