buzzkip
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Posts posted by buzzkip
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Hi All,
I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result.
Please help?
<?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?>
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table: inplace
columns: field, value, stock
The drop down displays the value columns perfectly, but when I hit the submit button... nothing happens.
<?php //create_topic.php include 'connect.php'; include 'header.php'; echo '<h2>Delete an item in the database</h2>'; if($_SESSION['signed_in'] == false) { echo 'Sorry, you have to be signed in.'; } else { if($_SERVER['REQUEST_METHOD'] != 'POST') { $sql = "SELECT field, value, stock FROM inplace"; $result = mysql_query($sql); if(!$result) { echo 'Error while selecting from database. Please try again later.'; } else { if(mysql_num_rows($result) == 0) { if($_SESSION['user_level'] == 1) { echo 'You have not created any items yet.'; } else { echo 'Before you can post an item, you must wait for an admin to create some locations.'; } } else { echo '<form method="post" action=""> Item: <select name="field">'; while($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['field'] . '">' . $row['value'] . '</option>'; } echo '</select><input type="submit" value="Delete item" /></form>'; } } } else { $query = "BEGIN WORK;"; $result = mysql_query($query); if(!$result) { echo 'An error occured while deleting your item. Please try again later.'; } else { $sql = "DELETE FROM inplace WHERE value = ' " . $_POST['value'] . " ' "; $result = mysql_query($sql); if(!$result) { echo 'An error occured while deleting your data. Please try again later.<br /><br />' . mysql_error(); $sql = "ROLLBACK;"; $result = mysql_query($sql); } else { $topicid = mysql_insert_id(); $sql = "DELETE FROM inplace WHERE value = ' " . $_POST['value'] . " ' "; $result = mysql_query($sql); if(!$result) { echo 'An error occured while deleting your item. Please try again later.<br /><br />' . mysql_error(); $sql = "ROLLBACK;"; $result = mysql_query($sql); } else { $sql = "COMMIT;"; $result = mysql_query($sql); echo 'You have succesfully deleted your new item.'; } } } } } include 'footer.php'; ?>
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Hi all,
Please could someone guide me as to how I would create a simple php page, that has a dropdown list populated by a database table - and then a submit button.
When I select an option in the dropdown list and then click submit, it deletes the row from the database table.
Would be very much appreciative of some help
echo data of an SQL query.. nothing echo'ing?
in PHP Coding Help
Posted
When I use:
I get error:
Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /removedURL/forumdisplay.php(1123) : eval()'d code on line 39
When I take away the set of line 39 and use this:
I get this error:
Error Type:
Catchable Fatal Error (4096)
Error Message:
Object of class mysqli_result could not be converted to string