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Showing results for tags '$_post variables'.
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Hi there. My problem is quite simple, but carries lots of questions of why the hell is this happening. I'm new at PHP but I'm familiar with the syntax, since It's been 3 years since I code in C, 1 in Java and half year in JS (with HTML and CSS of course). I was creating a page where I could validate a HTML form using PHP script, it was going everything allright, until I couldn't use the data that was going to the $_POST array. I tested it on some other file and It was like the server just didn't allowed me to do it so. I searched around on internet and I found the print_r() function, which shows the data as an associative array in $_POST, like this: array(KeyName => ValueName). Check the code and please, help me find why is this happening. I'm brazillian and all I know about english came from netflix, so i'm sorry if I wrote anything wrong. Thanks S&Z <!DOCTYPE html> <html lang = "pt-br" > <head> <title> Formulário </title> <meta charset="utf-8"> </head> <body> <form method = "POST" action = "<?php htmlspecialchars($_SERVER["PHP_SELF"]);?>" autocomplete = "off"> Nome: <br> <input type = "text" name = "Name" placeholder = "Ex: Guilherme" required autofocus> <?php if($_SERVER["REQUEST_METHOD"] == $_POST){ echo $_POST["Name"]; } ?> <br><br> <input type = "submit" value = "Enviar"> </form> <?php print_r($_POST); ?> </body> </html>
- 3 replies
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- form validation
- $_post variables
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Hello PHP freaks I'm a newbie so bear with me. I have a generic problem and I'm sure code already exists to solve it. I need to have a dynamic sql string variable that will only produce an insert statement with database column names corresponding to input fields on the form that contain values, ignoring the blank ones. I know some looping function like foreach might be used, but if I use it on the $_POST array I'll get the values, not the keys. (the first field, well_no, is a primary key and is held in a session variable, so I know I'll be inserting a value for that column) $ins = "well_no,"; foreach($_POST as $field) if (!empty($field)){ $ins .=$_POST[$field].","; } And I get a warning "Warning: Undefined array key "production in... Here "production" is actually a form input. the problem is my insert statement is hard-coded: $sql = "INSERT INTO well_parent (well_no, easting, northing, purpose, country, admin1, admin2, admin3, settlement, orig_wellno, date_completed, coord_sys, elev, status) VALUES (:well_no, :easting, :northing, ... How can I adjust the sql statement and also the $data array holding the variables. Here's the context: $sql = "INSERT INTO well_parent (well_no, easting, northing, purpose, country, admin1, admin2, admin3, settlement, orig_wellno, date_completed, coord_sys, elev, status) VALUES (:well_no, :easting, :northing, :purpose, :country, :admin1, :admin2, :admin3, :settlement, :orig_wellno, :date_completed, :coord_sys, :elev, :status)"; $stmnt = $pdo->prepare($sql); $data = [':well_no'=>$well_no, ':easting'=>$easting, ':northing'=>$northing, ':purpose'=>$purpose, ':country'=>$country, ':admin1'=>$admin1, ':admin2'=> $admin2, ':admin3'=>$admin3, ':settlement'=>$settlement, ':orig_wellno'=>$orig_wellno, ':date_completed'=> $date_completed, ':coord_sys'=> $coord_sys, ':elev'=>$elev, ':status'=>$status]; $stmnt->execute($data);
- 2 replies
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- pdo
- $_post variables
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