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Showing results for tags 'collumns'.
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hopefully this will be the end of this little project but ive been trying to do this for a while now i need to get 2 different collumns one of which is hidden which will be the ID one has the value of the field e.g. test, im hopefully down to the last error. ( ! ) Warning: mysqli_fetch_row() expects parameter 1 to be mysqli_result, boolean given in C:\wamp\www\AddLeads\addeadstemplate.php on line 254 Call Stack # Time Memory Function Location 1 0.0000 186408 {main}( ) ..\addeadstemplate.php:0 2 0.0156 194880 mysqli_fetch_row ( ) ..\addeadstemplate.php:254 <tr> <td>Type of Business:</td> <td> <select name="typeofbusiness"> <option value=''> - select type of business -</option> <?php $sql = "SELECT tbl_typesofbusiness.id, tbl_typesofbusiness.Agent FROM tbl_typesofbusiness"; $res = mysqli_query($con, $sql) or (mysqli_error($con)); while (list($id, $tob) = mysqli_fetch_row($res)); { echo "<option value='$id'>$tob</option>\n"; } ?> </select> </td> <td><span class="error">* <?php if (isset($errors['typeofbusiness'])) echo $errors['typeofbusiness']; ?></span></td> </tr> i can get rid of the error bie adding 'or die' on line 253 other than just or but what this does is stop everything under or die stops working cause ive got another 6 or 7 fields under type of business aswell as this no error occurs so im confused to hell, hopefully its not to complicated any help will be greatly appreciated
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right what i need to do is create 2 collumns for a html form, one of these is the ID and needs to be hidden and one collumn is full of options associated with these ID's the table which these two collumns are located on the database is called tbl_typesofbusiness and i just cant figure this out ive got the option box up but thats as far as i got i cant get two collumns up and they is no options in the option box, i just cant hack it ive been trying for a while and im confused to hell. <tr> <td>Type of Business:</td><td> <select name="typeofbusiness"> <?php $sql = sprintf("SELECT tbl_typesofbusiness.id, tbl_typesofbusiness.Agent FROM tbl_typesofbusiness")?></td> <td><span class="error">* <?php if (isset($errors['typeofbusiness'])) echo $errors['typeofbusiness']; ?></span></td> </tr> they is no errors on this code but i still cant seem to find a solution to it aswell theres only one record in the table at the moment which is called test1 with an id of 1. please help i just cant seem to hack it.