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Hello, I'm coding a log in page and I keep getting this problem with mysqli_result. It's a mysqli server. My error is: Fatal error: Cannot use object of type mysqli_result as array in /home/a7017672/public_html/login.html on line 34 My code is: <?PHP if(isset($_SESSION['loggedin'])) { die("You are already logged in!"); } if(isset($_POST['submit'])) { $email = mysqli_real_escape_string($con,$_POST['username']); $pass = mysqli_real_escape_string($con,$_POST['password']); $mysql = mysqli_query($con,"SELECT * FROM users WHERE email_address = '{$email}' AND password = '{$pass}'"); $mysql2 = mysqli_fetch_array($mysql); if (!$mysql ||mysqli_num_rows($mysql) < 1) { die("Incorrect password!"); } $_SESSION['loggedin'] = "YES"; $_SESSION['email'] = $email; $_SESSION['fname'] = $mysql['first_name']; $_SESSION['lname'] = $mysql['last_name']; $_SESSION['add1'] = $mysql['address_1']; $_SESSION['add2'] = $mysql['address_2']; $_SESSION['county'] = $mysql['county']; $_SESSION['postcode'] = $mysql['postcode']; $_SESSION['tel'] = $mysql['tel_no']; $_SESSION['mobile'] = $mysql['mobile_no']; $_SESSION['team'] = $mysql['team']; $_SESSION['ismanager'] = $mysql['is_manager']; $_SESSION['isadmin'] = $mysql['is_admin']; $_SESSION['sysadmin'] = $mysql['is_sysadmin']; die("You are now logged in!"); } echo "<form method='POST'> <p style='font-size: 14pt;'>Username (Email): <br><input type='text' name='username' maxlength='50' size='30'> <br /> <p style='font-size: 14pt;'>Password:<br><input type='text' name='password' maxlength='50' size='30'><br /> <input type='submit' name='submit' value='Login'> </form>"; ?> Any help is greatly appreciated!