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Showing results for tags 'isset'.
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1. HTML FORM #for user to enter the data <html> <title>reg</title> <style type="text/css"> body { background-color: rgb(200,200,200); color: white; padding: 20px; font-family: Arial, Verdana, sans-serif;} h4 { background-color: DarkCyan; padding: inherit;} h3 { background-color: #ee3e80; padding: inherit;} p { background-color: white; color: rgb(100,100,90); padding: inherit;} </style> <form method="POST" action="login_back.php" enctype="multipart/form-data"></br>  <font color="DarkCyan"> Choose a user name:</font> <input type="text" name="username"> </br></br>  <font color="DarkCyan"> First name:</font> <input type="text" name="firstname"/> </br></br>  <font color="DarkCyan"> Last name:</font><input type="text" name="lastname"/> </br></br>  <font color="DarkCyan"> File: <input type="file" name="image"></font> </br></br> <input type="submit" value="Save and Proceed"> </form> </html> ---------- 2 STORING IN DATABASE #backend processing to store and retrieve data from db <?php #echo "<body style='background-color:rgb(200,200,200)'>"; session_start(); if( isset($_POST['username']) && isset($_FILES['image']) ) { $_SESSION['username']=$_POST['username']; $_SESSION['firstname']=$_POST['firstname']; $lastname=$_POST['lastname']; $file=$_FILES['image']['tmp_name']; $image_size=getimagesize($_FILES['image']['tmp_name']); if(!isset($file)) echo"please select an image"; else { $image_name=$_FILES['image']['name']; //grabing image name $image_size=getimagesize($_FILES['image']['tmp_name']); //getting image size } echo "</br>"; #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); #checking the available username $query = mysql_query("SELECT * FROM userdata WHERE username = '" . $_SESSION['username'] . "'" ); $ans=mysql_num_rows($query); if ($ans > 0) { echo "Username already in use please try another."; } else if($image_size==FALSE) { echo"That's not an image."; } else { #Insert data into mysql #1.Inserting user name & image into db $sql="INSERT INTO userdata(username, firstname, lastname, image)VALUES('" . $_SESSION['username'] . "', '" . $_SESSION['firstname'] . "', '$lastname','$image')"; $result1=mysql_query($sql); if($result1) { echo "</br>"; echo "Registration successful"; echo "</br>"; //displaying image $lastid=mysql_insert_id();//get the id of the last record echo "uploaded image is :"; echo "<img src='get.php?id=".$lastid."'>"; > this command has some mistake }#if insertion into db successful else { echo "Problem in database operation"; } }# else block of unique username n img }#end of isset ?> ---------- 3. GET.PHP #additional file that retrieve image from database <?php #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); if(isset($_REQUEST['id']) ) > this block of code is not runninng { $mid=(int)($_REQUEST['id']); $image=mysql_query("SELECT * FROM userdata WHERE id=$mid") or die("Invalid query: " . mysql_error()); $image=mysql_fetch_assoc($image); $image=$image['image']; header("Content-type: image/jpeg"); echo $image; } else { echo"error"; } ?>
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1. HTML FORM #for user to enter the data <html> <title>reg</title> <style type="text/css"> body { background-color: rgb(200,200,200); color: white; padding: 20px; font-family: Arial, Verdana, sans-serif;} h4 { background-color: DarkCyan; padding: inherit;} h3 { background-color: #ee3e80; padding: inherit;} p { background-color: white; color: rgb(100,100,90); padding: inherit;} </style> <form method="POST" action="login_back.php" enctype="multipart/form-data"></br>  <font color="DarkCyan"> Choose a user name:</font> <input type="text" name="username"> </br></br>  <font color="DarkCyan"> First name:</font> <input type="text" name="firstname"/> </br></br>  <font color="DarkCyan"> Last name:</font><input type="text" name="lastname"/> </br></br>  <font color="DarkCyan"> File: <input type="file" name="image"></font> </br></br> <input type="submit" value="Save and Proceed"> </form> </html> ---------- 2 STORING IN DATABASE #backend processing to store and retrieve data from db <?php error_reporting(0); #echo "<body style='background-color:rgb(200,200,200)'>"; session_start(); #if( isset($_POST['username']) && isset($_FILES['image']) ) #{ $_SESSION['username']=$_POST['username']; $_SESSION['firstname']=$_POST['firstname']; $lastname=$_POST['lastname']; $file=$_FILES['image']['tmp_name']; $image_size=getimagesize($_FILES['image']['tmp_name']); if(!isset($file)) echo"please select an image"; else { #$image=$_FILES['image']['tmp_image']; //grabing the file content $image_name=$_FILES['image']['name']; //grabing image name $image_size=getimagesize($_FILES['image']['tmp_name']); //getting image size } echo "</br>"; #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); #checking the available username $query = mysql_query("SELECT * FROM userdata WHERE username = '" . $_SESSION['username'] . "'" ); $ans=mysql_num_rows($query); if ($ans > 0) { echo "Username already in use please try another."; } else if($image_size==FALSE) { echo"That's not an image."; } else { #Insert data into mysql #1.Inserting user name & image into db $sql="INSERT INTO userdata(username, firstname, lastname, image)VALUES('" . $_SESSION['username'] . "', '" . $_SESSION['firstname'] . "', '$lastname','$image')"; $result1=mysql_query($sql); if($result1) { echo "</br>"; echo "Registration successful"; echo "</br>"; //displaying image $lastid=mysql_insert_id();//get the id of the last record echo "uploaded image is :"; echo "<img src='get.php?id=".$lastid."'>"; > this command has some mistake }#if insertion into db successful else { echo "Problem in database operation"; } }# else block of unique username n img }#end of isset ?> ---------- 3. GET.PHP #additional file that retrieve image from database <?php #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); if(isset($_REQUEST['id']) ) > this block of code is not running { $mid=(int)($_REQUEST['id']); $image=mysql_query("SELECT * FROM userdata WHERE id=$mid") or die("Invalid query: " . mysql_error()); $image=mysql_fetch_assoc($image); $image=$image['image']; header("Content-type: image/jpeg"); echo $image; } else echo"error"; ?>
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Hi all. i am trying to use php to include a javascript onto different pages, and then "sort of " pass it a var. The bulk of the code will be in an included footer php file. The var will be set in the main page. i have it working as follows: by just using echo 3 times.. the 1st with the first part of the script, the 2nd is the variable, and the 3rd is the rest of the script. The same endcode.php file needs to also be used for pages that wont have a var set, and wont be using the script - hense the isset. <!-- mainPage.php --> <?php $sion_gallery_id = '450'; ?> <?php include(endcode.php); ?> <!-- endcode.php --> <?php if (isset($sion_gallery_id)) {echo "start of javascript.......album/"; echo $sion_gallery_id; echo"/end of script"; } else { echo "var not on set";} ?> This works great, and i can set $sion_gallery_id do different numbers, and it pulls different albums through for diff pages. Is this secure enough as it is? I have read about whitelists, and tried the following: <!-- Headcode.php --> <?php $whitelist = array('465','6', '7','745','450'); ?> <!-- mainPage.php --> <?php include(Headcode.php);?> <?php $sion_gallery_id = '450'; ?> <?phpinclude(endCode.php); ?> <!-- endCode.php --> <?php if (isset($sion_gallery_id)) {if (in_array($sion_gallery_id, $whitelist)) {echo "java script content goes here.......album/"; echo $sion_gallery_id; echo"/end of script"; } else { echo "var not on white list";}} else { echo "No var set"; }; ?> This works when i try it at a basic level. However, when i set it up properly with the headcode and endcode pages being included, and also with all the actual javascript being echoed in endcode.php -- it worked perfectly for the first page. But when i changed the var to a different number, remembering to add this to the whitelist, it wont load - and echoes "var not on white list". ..... but it is? So, do i need to use a white list for this, or have i got the wrong end of the stick anyway. And if i do, can anyone see what may be happening? Is the first var getting cashed somewhere? Any help is much appreciated. Thanks, Sion.
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I need to check whether the user has uploaded a file when submitting a form using isset. If they have, the file path is recorded to the database. If they haven't nothing needs to occur, the file path field will just be NULL. Here is my issue: When I test it with uploading no file I'm still getting "images/" from my $ filelocation variable recorded to the database. How can I fix this? <?php if(isset($_FILES['userfile'])) { $fileupload = $_FILES['userfile']['name']; $filetype = $_FILES['userfile']['type']; $filesize = $_FILES['userfile']['size']; $tempname = $_FILES['userfile']['tmp_name']; $filelocation = "images/$fileupload"; } else { $filelocation = NULL; } if (!move_uploaded_file($tempname,$filelocation)) { switch ($_FILES['userfile']['error']) { case UPLOAD_ERR_INI_SIZE: echo "<p>Error: File exceeds the maximum size limit set by the server</p>" ; break; case UPLOAD_ERR_FORM_SIZE: echo "<p>Error: File exceeds the maximum size limit set by the browser</p>" ; break; default: echo "<p>File could not be uploaded </p>" ; } } if ($_POST["productName"] == "") { header("Location:getProductDetails.php"); exit(); } elseif ($_POST["productDescription"] == "") { header("Location:getProductDetails.php"); exit(); } else { $conn = @mysqli_connect("localhost", "root", ""); if (!$conn) { echo "The connection has failed: " . mysqli_error($conn); } else { //echo "Successfully connected to mySQL!"; $query = "CREATE DATABASE IF NOT EXISTS bazaar"; $dbName =""; if (!mysqli_query($conn,$query)) { echo "<p>Could not open the database: " . mysqli_error($conn)."</p>"; } else { //echo "<p>Database successfully created</p>"; if (!mysqli_select_db($conn,"bazaar")) { echo "<p>Could not open the database: " . mysqli_error($conn)."</p>"; } else { //echo "<p>Database selection successful</p>"; $query = "CREATE TABLE IF NOT EXISTS products(productid int primary key not null auto_increment,productname varchar(50), productdesc text, colour varchar(25), price decimal(5,2) not null,imagepath varchar(250));"; if (!mysqli_query($conn,$query)) { echo "table query failed1: " . mysqli_error($conn); } else { //echo "<p>table query successful</p>"; $insert = "INSERT INTO products (productname, productdesc, colour, price, imagepath) VALUES ('$_POST[productName]','$_POST[productDescription]','$_POST[colour]','$_POST[price]','$filelocation');"; if (mysqli_query($conn,$insert)) { $customerId = mysqli_insert_id($conn); } else { echo "table query failed: " . mysqli_error($conn); } } } } } mysqli_close($conn); } ?>
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I want an if statement that not only checks for the existence of a variable, but which also checks all the variables already created for one with a specific value. For example, I have a loop which creates variables, but I don't want it to make two variables with the same value. The problem is, using if(isset(${'h'.$x}==false) && ${'h'.$x} != 3{ } won't work since the variable equal to 3 could be named h4, whereas this one will be named h5. I hoped I explained this efficiently enough, sorry about any confusion.
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this code works but i need to insert isset so that when i select a country the dropdown list remains selected for that particuar country i tries this if(isset($_POST['country']) but it doesnt work???? <form action="index.php" method="post" id="selected_country"> <p for="country_list">Please Select A Country:</p> <select name="country" id="country_list" onchange="this.form.submit();" > <?php foreach($countries as $name): ?> <option value="<?php echo $name['country'] ?>"><?php echo $name['country'] ?></option> <?php endforeach; ?> </select> <!-- <input </div>type="submit" value="View Culture" />--> </form> <br /> <br /> <?php $c_name = $_POST['country']; $pdb2 = new CountryDB(); $countries1 = $pdb2->GetCountryByCountry($c_name); ?> <h1> Culture of <?php echo $c_name ?> </h1> <?php foreach($countries1 as $list): ?> <table> <td> <img src="<?php echo $list['image'] ?>"> </img> </td> </table>
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I originally had the error: "undefined index: password" I researched the error and figured out that I needed to be using isset() When should I use isset(every time I use the post array?) Why does this prevent that error from showing up? Also, is this how I should be coding it: // Check whether a password was entered and confirmed correctly if (isset($_POST["password"])=="") { $passwordIsEmpty = true; } if (isset($_POST["password2"])=="") { $password2IsEmpty = true; } if (isset($_POST["password"])!= isset($_POST["password2"])) { $passwordIsValid = false; } Instead of: if ($_POST['password'] == "") { $passwordIsEmpty = true; } if ($_POST['password2'] == "") { $password2IsEmpty = true; } if ($_POST['password'] != $_POST['password2']) { $passwordIsValid = false; }
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I have the following: .. This is the button with hidden type .. <input type="hidden" name="s2member_pro_paypal_registration[nonce]" id="s2member-pro-paypal-registration-nonce" value="xxx"> <input type="hidden" name="s2p-option" value=""> <input type="submit" name="r_submit" id="s2member-pro-paypal-registration-submit" class="s2member-pro-paypal-submit s2member-pro-paypal-registration-submit" value="Register" tabindex="1000"> My code to detect the submit button: if (!isset($_POST['r_submit']) && $_POST['s2member_pro_paypal_registration']['nonce'] == 'xxx') { // Do nothing } else { var_dump($something); // Do something } My site spits out var_dump() automatically when the form hasn't been submitted yet and I'm not sure why. Can someone please help me? Thanks, Hal -
I need this to only print the little note at the bottom if the user has put in all the information.. Help please.. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html lang="EN" dir="ltr" xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Assignment2</title> </head> <body> <h3>Personal Information </h3> <?php $chkErrors = FALSE; if(!empty($_POST['fName']) && isset($_POST['fName'])) { } else { echo 'First Name Fieldis empty'; } if(!empty($_POST['lName']) && isset($_POST['lName'])) { } else { echo 'Your last name field is empty'; } if(!empty($_POST['city']) && isset($_POST['city'])) { } else { echo 'Your city field is empty'; } if(!empty($_POST['state']) && isset($_POST['state'])) { } else { echo 'Your state field is empty'; } if(!empty($_POST['zipCode']) && isset($_POST['zipCode'])) { } else { echo 'Your zipcode field is empty'; } { $fName = filter_input(INPUT_POST, "fName"); $lName = filter_input(INPUT_POST, "lName"); $city = filter_input(INPUT_POST, "city"); $state = filter_input(INPUT_POST, "state"); $zipCode = filter_input(INPUT_POST, "zipCode"); } if($chkErrors == FALSE) { echo <<<HERE <h3> Hi there, $fName $lName, <br /> so you live in $city,<br /> in the great state of $state.<br /> I hear the climate around $zipCode is great this time of year. <br /> $fName, I hear that $state has alot to offer as far as recreation goes.<br />I hope that you have a great summer in $city. <br /></h3> HERE; }
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How are these not saying to check for the same thing, because when I run the isset it's thinking $_POST['message']! that a blank entry is something there, but !='' is saying that a blank entry isn't there? I tried the isset a few times, but every time it came out allowing a blank message the same way. Is that a bug with WAMP:Apache Version :2.2.17/PHP Version :5.3.4?
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Hi. I have a problem and don´t know hot to solve it. I guess is a very basic thing but after fighting with it a whole week, I decide to ask here... The thing is the following: I have a database that I read perfectly, but, in that database, I have a field that can be with content or "came" empty. I want to make this ... If that field came empty, don´t do nothing, else (with content) do the other thing... like this; if ( isset ( myfield )) { // DO THE CONDITION in myfield } else { // DONT DO NOTHING } Is this correct?? How can I check thefield empty or not and do things depending on this condition?? Please, help. Thanks. Regards
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I have worked up a login page and everything and works great, as well as on all the other pages set to if not logged in it will redirect to the login page. Code is here: <?php session_start(); if (!(isset($_SESSION['forteid']) && $_SESSION['forteid'] != '')) { header ("Location: login.php"); } ?> Now trying to add in certain pages where only certain access can access the page if not it will redirect back to the home page. This is what I have, but when not logged in and go to a page with this at the top, it just seems to skip over the first if (!isset) check: <?php session_start(); if (!(isset($_SESSION['forteid']) && $_SESSION['forteid'] != '')) { header ("Location: login.php"); } if (!(isset($_SESSION['accesslevel']) && $_SESSION['accesslevel'] != '1')) { header ("Location: noaccess.php"); } ?> I thought if else statement but not sure how to write that. Thanks for the help in advance!
