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Showing results for tags 'mysql_fetch_array() error'.
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i'm sorry im newbie of php... i found this... http://forums.phpfreaks.com/topic/181256-solved-warning-mysql-fetch-array-expects-parameter-1-to-be-resource/ but in my case i didn't use $result in my while....why it doesnt work? somebody help me...thx before ERROR on line 17coba.php $total_record = mysql_fetch_array(mysql_query('SELECT COUNT(`product_id`) AS rows FROM `product`' )); //ERROR $total_record=$total_record['rows']; $total_page=ceil($total_record/$per_page); if($page>$total_page) $page=$total_page; $query_exec = get_all_product(); echo "<table align='center'>"; echo "<tr align=center>"; echo"<th>Image</th><th>Name</th><th>About</th><th>Price</th><th>Stoks</th><th>Category</th>"; echo "</tr>"; while ($row = mysql_fetch_assoc($query_exec)){ echo "<tr align=center>"; echo"<td><img src='".$row['product_image']."'/><td>"; echo "<td>" .$row['product_name']. "</td>"; echo "<td>" .$row['product_description']. "</td>"; echo "<td>" .$row['product_price']. "</td>"; echo "<td>" .$row['product_stok']. "</td>"; echo "<td>" .$row['category_name']. "</td>"; echo "<td><input type=button value=delete name='delete' onClick = lemparproduct('".$row['product_id']."')></td>"; echo "<td><input type='hidden' id='idproducthidden' value='".$row['product_id']."'> <input type=button value=update name='updates' onClick = wew('".$row['product_id']."')></td>"; echo "</tr>";} echo "</table>"; echo 'page : <select onchange="window.location=\'?p=\'+this.value">'; for($i=1;$i<=$total_page;$i++) echo '<option' . ( $i==$page ? ' selected' : '' ) . '>' . $i . '</option>'; echo '</select><br>';