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Showing results for tags 'select options'.
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Keep getting these two errors when trying to UPDATE a field called "type" to 'banana' based on the fuitid. Why is this happening? Undefined index: fruitid in update.php You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 <form method="POST" action="update.php"> <select> <option value="">Select</option> <?php $sql = "SELECT fruitid, datefrom, dateto FROM fruits"; $sqlresult = $link->query($sql); $sqllist = array(); while($row = mysqli_fetch_array($sqlresult)) { echo "<option>".$row['datefrom']." - ".$row['dateto']."</option>"; } ?> </select> <input type="hidden" value="<?php echo $fruitid;?>" name="fruitid"/> <input type="submit" value="Submit" name="submit"/> </form> <?php if(isset($_POST['submit'])) { $fruitid= mysqli_real_escape_string($link,$_POST['fruitid']); $sql = "UPDATE `fruits` SET `type`='banana' WHERE fruitid = $fruitid"; if (mysqli_query($link, $sql)) { echo "updated"; } else { echo "problem: " . mysqli_error($link); } } ?>