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Found 2 results

  1. I am new to PHP and I am having some problems and I am hoping someone can point me in the right direction. Here is what I need to do: Create a Web Form for uploading pictures for a high school reunion. The form should have text input fields for the person's name and a description of the image, and a file input field for the image. To accompany each file, create a text file that contains the name and description of the image. Create a separate Web Page that displays the pictures with a caption showing the name and description fields. Make sure the folder has read and write for everyone. Here is what I have but it isnt working properly: Process page of the page! an errow here: This is the message I get! Parse error: syntax error, unexpected '\' (T_NS_SEPARATOR) in C:\ITEC315\htdocs\users\ramojumder0\Reinforcement Exercises\Ch. 5\R.E.5-5_FillPictureForm.php on line 28 which deals with the picture! My problem is that it is having a problem uploading a picture and showing it! How do I fix the issue with uploading a picture and then showing it! Input page <form method="POST" action="R.E.5-5_Fillrrr.php"> <p>Name <input type="text" name="name" /></p> <p>Description <input type="text" name="description" /></p> <p>Choose a file to upload: <input type = "file" name = "picture" accept = "image/*" /></p> <p><input type="submit" value="Submit" /></p> </form> <p><a href="R.E.5-5_ShowPictures.php">Show Pictures </a></p> </body> </html> Processing page! <?php if (empty($_POST['name']) || empty($_POST['description'])) echo "<p>You must enter your name and description about your picture. Click your browser's Back button to return to the Picture Input Page!</p>\n"; else { $Name = addslashes($_POST['name']); $Description = addslashes($_POST['description']); $Picture = addslashes($_POST['picture']); $ShowPic = fopen("showpic.txt", "ab"); if (is_writeable("showpic.txt)) { if (fwrite($ShowPic, $Name . "," . $Description . "," . $Picture . "\r\n")) echo "<p>Thank you for filling out the Picture Input Page!</p>\n"; else echo "<p>Cannot add your name to the Picture Input Page!</p>\n"; } else echo "<p>Cannot write to the file.</p>\n"; fclose($ShowPic); } ?><!--End PHP Script-->
  2. I have a table contained by a form. Each row of the table contains the following data cells: <td> <input type='text' name='cart[ccr-01-002]' size='2' /> </td> <td> <input type='checkbox' name='delete[ccr-01-002]' /> </td> Rather than returning whether or not the checkbox is checked (such as ON or OFF), it is instead returning the value of the text input field. Here is how I am trying to reference it: var_dump($_POST['delete']); This prints out the string contents of the text fields instead of ON or OFF. Is it possible (without having to put the checkbox into its own form) to reference the checkbox as a separate entity from the text input? I would like to reference $_POST['cart'], and not have it affect $_POST['delete']. Please let me know if you need any other information!
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