Jump to content

Search the Community

Showing results for tags 'working date'.

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


Forums

  • Welcome to PHP Freaks
    • Announcements
    • Introductions
  • PHP Coding
    • PHP Coding Help
    • Regex Help
    • Third Party Scripts
    • FAQ/Code Snippet Repository
  • SQL / Database
    • MySQL Help
    • PostgreSQL
    • Microsoft SQL - MSSQL
    • Other RDBMS and SQL dialects
  • Client Side
    • HTML Help
    • CSS Help
    • Javascript Help
    • Other
  • Applications and Frameworks
    • Applications
    • Frameworks
    • Other Libraries
  • Web Server Administration
    • PHP Installation and Configuration
    • Linux
    • Apache HTTP Server
    • Microsoft IIS
    • Other Web Server Software
  • Other
    • Application Design
    • Other Programming Languages
    • Editor Help (PhpStorm, VS Code, etc)
    • Website Critique
    • Beta Test Your Stuff!
  • Freelance, Contracts, Employment, etc.
    • Services Offered
    • Job Offerings
  • General Discussion
    • PHPFreaks.com Website Feedback
    • Miscellaneous

Find results in...

Find results that contain...


Date Created

  • Start

    End


Last Updated

  • Start

    End


Filter by number of...

Joined

  • Start

    End


Group


AIM


MSN


Website URL


ICQ


Yahoo


Jabber


Skype


Location


Interests


Age


Donation Link

Found 1 result

  1. hello, i am printing the days with php: $i = 0; $date = 0; while ($i < 3) { $nexttime = strtotime("+$date days", strtotime("thursday")); if(date("D", $nexttime) == "Sat") { echo "saturday...skipping one day...<br />\n"; $date++; } else { echo "it's ".date("D", $nexttime)."<br />\n"; $i++; } $date++; } i am trying to check if the day is working or not, for this purpuse i have one table with two rows - arrays for working and rest days: ["11.02","03.06"...] this is the final result but .. something is wrong because today is working day but it was not printed: if((date("D",$nexttime)=="Sat" || (date("D",$nexttime)=="Sun") && !in_array(date("d.m",$nexttime),$workingdaysarray) ){$date++; ...
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.