$var = $_POST['var']

[porta325]

Hey guys, i wanna do something like this:

$var1 = $_POST['var1']; but i wanna doit dinamic;

My ideea is something like this :

$id = "1";

 

$var.$id = $_POST['var.$id'];

 

Problem is it's not working. Any ideeas? i would apreciate. Thx.

 

 

[marklarah]

What? Could you please explain what you want a little more clearly please?

[porta325]

I have several generated textboxes. Each has a name like text1, text2, text3 and text4

 

After i post them to next page all i get is the last value.

So the solution would be to write them manualy as:

$text1 = $_POST['text1'];

$text2 = $_POST['text2'];

$text3 = $_POST['text3'];

$text4 = $_POST['text4'];

 

or

 

to do something like

$id1 = "1";

$id2 = "2";

$id3 = "3";

$id4 = "4";

and use

$text.$id1 = $_POST['text$id1'];

$text.$id2 = $_POST['text$id2'];

.... and so on. The id's i take from a database using a while loop, it's just to make the example clear.

[marklarah]

Ooooh okay. Dont do it manually, use

$wi = "-1";
while (list($key,$value) = each($_POST)){
$wi++;
$result1 = "SELECT * FROM `temp3` WHERE `ID` = '$key' ";

 

Something like that

[hellbringer]

@marklarah

 

Very insecure!

 

 

@porta325

 

Use Arrays:

 

<input type="text" name="text[]" id="text1" />
<input type="text" name="text[]" id="text2" />
<input type="text" name="text[]" id="text3" />

 

$text = (array) $_POST['text'];