Jump to content

PHP Telnet script - Help


Marco C

Recommended Posts

Hello to all,

 

Is the first time I am programming with PHP and I am trying to do a php script for telnet to a switch.

And I have an error that sayed:

sometimes it says:

 

1 - TIME OUT line 118 (the bold line)

2 - 3

 Connect failed: Login failed - my login and password is correct i check it.

 

 

I don´t understand Why the error is in PHPTelnet.php main include file.

Can someone help me, please.

 

My code is:

 

And I have the file PHPTtelnet and in side i have:

 

<?php

/*

PHPTelnet 1.1

by Antone Roundy

adapted from code found on the PHP website

public domain

*/

 

class PHPTelnet {

var $show_connect_error=1;

 

var $use_usleep=0; // change to 1 for faster execution

// don't change to 1 on Windows servers unless you have PHP 5

var $sleeptime=125000;

var $loginsleeptime=1000000;

 

var $fp=NULL;

var $loginprompt;

 

var $conn1;

var $conn2;

 

/*

0 = success

1 = couldn't open network connection

2 = unknown host

3 = login failed

4 = PHP version too low

*/

function Connect($server,$user,$pass) {

$rv=0;

$vers=explode('.',PHP_VERSION);

$needvers=array(4,3,0);

$j=count($vers);

$k=count($needvers);

if ($k<$j) $j=$k;

for ($i=0;$i<$j;$i++) {

if (($vers[$i]+0)>$needvers[$i]) break;

if (($vers[$i]+0)<$needvers[$i]) {

$this->ConnectError(4);

return 4;

}

}

 

$this->Disconnect();

 

if (strlen($server)) {

if (preg_match('/[^0-9.]/',$server)) {

$ip=gethostbyname($server);

if ($ip==$server) {

$ip='';

$rv=2;

}

} else $ip=$server;

} else $ip='127.0.0.1';

 

if (strlen($ip)) {

if ($this->fp=fsockopen($ip,23)) {

fputs($this->fp,$this->conn1);

$this->Sleep();

 

fputs($this->fp,$this->conn2);

$this->Sleep();

$this->GetResponse($r);

$r=explode("\n",$r);

$this->loginprompt=$r[count($r)-1];

 

fputs($this->fp,"$user\r");

$this->Sleep();

 

fputs($this->fp,"$pass\r");

if ($this->use_usleep) usleep($this->loginsleeptime);

else sleep(1);

$this->GetResponse($r);

$r=explode("\n",$r);

if (($r[count($r)-1]=='')||($this->loginprompt==$r[count($r)-1])) {

$rv=3;

$this->Disconnect();

}

} else $rv=1;

}

 

if ($rv) $this->ConnectError($rv);

return $rv;

}

 

function Disconnect($exit=1) {

if ($this->fp) {

if ($exit) $this->DoCommand('exit',$junk);

fclose($this->fp);

$this->fp=NULL;

}

}

 

function DoCommand($c,&$r) {

if ($this->fp) {

fputs($this->fp,"$c\r");

$this->Sleep();

$this->GetResponse($r);

$r=preg_replace("/^.*?\n(.*)\n[^\n]*$/","$1",$r);

}

return $this->fp?1:0;

}

 

function GetResponse(&$r) {

$r='';

do {

$r.=fread($this->fp,1000);

[b] $s=socket_get_status($this->fp);

} while ($s['unread_bytes']);[/b]

}

 

function Sleep() {

if ($this->use_usleep) usleep($this->sleeptime);

else sleep(1);

}

 

function PHPTelnet() {

$this->conn1=chr(0xFF).chr(0xFB).chr(0x1F).chr(0xFF).chr(0xFB).

chr(0x20).chr(0xFF).chr(0xFB).chr(0x18).chr(0xFF).chr(0xFB).

chr(0x27).chr(0xFF).chr(0xFD).chr(0x01).chr(0xFF).chr(0xFB).

chr(0x03).chr(0xFF).chr(0xFD).chr(0x03).chr(0xFF).chr(0xFC).

chr(0x23).chr(0xFF).chr(0xFC).chr(0x24).chr(0xFF).chr(0xFA).

chr(0x1F).chr(0x00).chr(0x50).chr(0x00).chr(0x18).chr(0xFF).

chr(0xF0).chr(0xFF).chr(0xFA).chr(0x20).chr(0x00).chr(0x33).

chr(0x38).chr(0x34).chr(0x30).chr(0x30).chr(0x2C).chr(0x33).

chr(0x38).chr(0x34).chr(0x30).chr(0x30).chr(0xFF).chr(0xF0).

chr(0xFF).chr(0xFA).chr(0x27).chr(0x00).chr(0xFF).chr(0xF0).

chr(0xFF).chr(0xFA).chr(0x18).chr(0x00).chr(0x58).chr(0x54).

chr(0x45).chr(0x52).chr(0x4D).chr(0xFF).chr(0xF0);

$this->conn2=chr(0xFF).chr(0xFC).chr(0x01).chr(0xFF).chr(0xFC).

chr(0x22).chr(0xFF).chr(0xFE).chr(0x05).chr(0xFF).chr(0xFC).chr(0x21);

}

 

function ConnectError($num) {

if ($this->show_connect_error) switch ($num) {

case 1: echo '<br />[php Telnet] <a href="http://www.geckotribe.com/php-telnet/errors/fsockopen.php">Connect failed: Unable to open network connection</a><br />'; break;

case 2: echo '<br />[php Telnet] <a href="http://www.geckotribe.com/php-telnet/errors/unknown-host.php">Connect failed: Unknown host</a><br />'; break;

case 3: echo '<br />[php Telnet] <a href="http://www.geckotribe.com/php-telnet/errors/login.php">Connect failed: Login failed</a><br />'; break;

case 4: echo '<br />[php Telnet] <a href="http://www.geckotribe.com/php-telnet/errors/php-version.php">Connect failed: Your server\'s PHP version is too low for PHP Telnet</a><br />'; break;

}

}

}

?>

 

 

 

I have the file Telnet.php and in side of it i have:

 

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">

<title>Untitled Document</title>

</head>

<body>

<?php

require_once "PHPTelnet.php";

$telnet = new PHPTelnet();

$telnet->show_connect_error=0;

// if the first argument to Connect is blank,

// PHPTelnet will connect to the local host via 127.0.0.1

$result = $telnet->Connect('192.168.0.10','admin','admin'); //wwww.somewhere.com, username, password

echo $result;

switch ($result) {

case 0:

$telnet->DoCommand('show version', $result);

// NOTE: $result may contain newlines

echo $result;

#$telnet->DoCommand('show version', $result);

echo $result;

// say Disconnect(0); to break the connection without explicitly logging out

$telnet->Disconnect();

break;

case 1:

echo '[php Telnet] Connect failed: Unable to open network connection';

break;

case 2:

echo '[php Telnet] Connect failed: Unknown host';

break;

case 3:

echo '[php Telnet] Connect failed: Login failed';

break;

case 4:

echo '[php Telnet] Connect failed: Your PHP version does not support PHP Telnet';

break;

}

?>

</body>

</html>

 

 

Thanks in advanced,

Marco C

 

 

Link to comment
https://forums.phpfreaks.com/topic/101056-php-telnet-script-help/
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.