[SOLVED] Converto to an array of values

[Julian]

Hi guys

 

I'm making a calendar for my web page, but I want to show the days as events and link those events to the correspondent page.

 

I have this to get the days:

 

$sd = '2008-04-01';
$ed = '2008-04-15';
	for ($z=strtotime($sd);$z<strtotime($ed);$z+=86400)
	echo date('d',$z);

 

This works excellent to get the days between to dates.  Here's the code for the links in the calendar:

 

$days = array(); $c = 0;
        $d = ?????;//Here's should be days I got from the previous code
        $l = 'users.php?day='.$d.'&month='.$month.'&year='.$year;
	$days[$d][] = $l;
echo generate_calendar(date('Y', $time), date('n', $time), $days, 1, NULL, 0, $pn);
setlocale(LC_TIME, $oldlocale);

 

I have to create a loop on $d in order to reflect all the days in between the dates.

 

Any help will be highly appreciated.

[Zhadus]

I believe the following code would build an array with all the days between the event dates.

$sd = '2008-04-01';
$ed = '2008-04-15';
   for ($z=strtotime($sd);$z<strtotime($ed);$z+=86400)
   $dArray[] = date('d',$z);

[p2grace]

He's already doing that.  I believe what he wants to know is how to show events during that time.  You'd have to create a database table that saves a begin date and an end date.  Then query the table before generating the calendar and save all of the upcoming events for the given month into an array.  Then while you're looping through the days of the month check to see if it is within the range of one of the events from the array.  If it is show the event.

[Julian]

Thanks guys

 

I already have everything on the database, start_date and end_date, I just put a sample code not including the database query to simplify my request.

 

$days = array(); $c = 0;
        $d = ?????;//Here's should be days I got from the previous code
        $l = 'users.php?day='.$d.'&month='.$month.'&year='.$year;
	$days[$d][] = $l;
echo generate_calendar(date('Y', $time), date('n', $time), $days, 1, NULL, 0, $pn);
setlocale(LC_TIME, $oldlocale);

 

How can I call the array ($dArray[]) into this script? or convert $dArray[] to a variable...

 

Thanks for the help.

[p2grace]

Instead of echoing out the days just save them to an array then do a foreach on the array to start looping through them.  Is that what you're asking?  Otherwise could you elaborate?

[Julian]

Hi

 

Yes that is what I'm looking for.  How can translate that into a scrip?

 

Regards

[p2grace]

Do this to create your array:

 

<?php
$sd = '2008-04-01';
$ed = '2008-04-15';
$days = array();
	for ($z=strtotime($sd);$z<strtotime($ed);$z+=86400){
	    echo date('d',$z);
                    $days [] = $z;
                }

//Then foreach through it
foreach($days as $key => $day){
     $d = $day;
        $l = 'users.php?day='.$d.'&month='.$month.'&year='.$year;
	$days[$key]['l'] = $l;
echo generate_calendar(date('Y', $time), date('n', $time), $days, 1, NULL, 0, $pn);
setlocale(LC_TIME, $oldlocale);
}
?>

 

Something simple like that should do the trick.

[Julian]

Thanks dude, being great help...

 

I get this error: 

Warning: Cannot use a scalar value as an array in /home/redcul/public_html/php/calendario.php on line 60

 

Line 60:  $days[$key]['l'] = $l;

 

Sorry for ask but what for is ['l']?

 

Thanks again

[p2grace]

Actually just remove that line, I just changed what you had originally to one that wouldn't interfere with my array.

[Julian]

Hi thanks again, but the code isn't workin, but gave me a hint.  I modified the code a little bit but the problem I have now i that I can't reset the array.  It's supposed to start at 01 not at 10.  Bellow the calendar I echoed the array.

 

Working example at: http://www.redcultura.com/php/calendario.php

 

Here's the code:

$sd = '2008-04-01';
$ed = '2008-04-15';
$days = array();
	for ($z=strtotime($sd);$z<strtotime($ed);$z+=86400)
		$day[] = date('d',$z);

$days = array(); $c = 0;

foreach($day as $value){
	$c++;
     	$d = $value;
        $l = 'users2.php?dia='.$d.'&mes='.$mes.'&ano='.$ano;
	$days[$d][] = $l;
}
echo generate_calendar(date('Y', $time), date('n', $time), $days, 1, NULL, 0, $pn);
setlocale(LC_TIME, $oldlocale);

[p2grace]

Try this:

 

<?php
$sd = '2008-04-01';
$ed = '2008-04-15';
$days = array();
	for ($z=strtotime($sd);$z<strtotime($ed);$z+=86400)
		$day[] = date('d',$z);

$days = array(); $c = 0;

foreach($day as $value){
               if($c == 09){
                  $c = 01;
               }else{
	   $c++;
                }
     	$d = $value;
        $l = 'users2.php?dia='.$d.'&mes='.$mes.'&ano='.$ano;
	$days[$d][] = $l;
}
echo generate_calendar(date('Y', $time), date('n', $time), $days, 1, NULL, 0, $pn);
setlocale(LC_TIME, $oldlocale);
?>

 

Is this what you want it to do?

[Julian]

Hi

 

No, if you check the $sd and $ed values, the numbers should start on 01, this will depend on the $sd value.  If I

foreach ($day as $value) {
    echo "Days: $value . 'This day should be in the calendar'<br />\n";
}

 

I get all the days in the array.  But this is not showing on the calendar script.  I think here's the problem:

 

$days = array(); $c = 0;

 

Thanks for looking.

[p2grace]

If I had to guess, it's probably because the calendar array isn't saving the array as "01" it's saving it as "1" so it doesn't think there's an event for that day.

[Julian]

If I echo the array it shows the 01 -02 .....

 

Here's an example:  http://www.redcultura.com/php/calendario.php

[Julian]

Hi guys

 

Thanks for the help.  Now I finished the code.  I realized that the problem was in how I was calling the date format.  Changed 'd' for 'j' solved the problem.

 

Regards