MySQLi - search a database field

[MNSarahG]

Hi,

 

I'm trying to run a search of table in my database.  I have a page with this form:

 

<form name="form" action="results.php" method="get">
  <input type="text" name="q" />
  <input type="submit" name="Submit" value="Search!" />
</form>

 

That then uses this code to execute a search:

 

<?php

  // Get the search variable from URL

  $var = @$_GET['q'] ;
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=10; 

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>We dont seem to have a search parameter!</p>";
  exit;
  }

mysqli_connect("localhost","meetings","m33tings123"); 

mysqli_select_db("meetingsEventLocation") or die("Unable to select database"); 

// Build SQL Query  
$query = "select * from listings where name like \"%$trimmed%\"  
  order by name"; 

$numresults=mysqli_query($query);
$numrows=mysqli_num_rows($numresults);

// If we have no results, offer a google search as an alternative

if ($numrows == 0)
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";

// google
echo "<p><a href=\"http://www.google.com/search?q=" 
  . $trimmed . "\" target=\"_blank\" title=\"Look up 
  " . $trimmed . " on Google\">Click here</a> to try the 
  search on google</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " limit $s,$limit";
  $result = mysqli_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";

// begin to show results set
echo "Results";
$count = 1 + $s ;

// now you can display the results returned
  while ($row= mysqli_fetch_array($result)) {
  $title = $row["1st_field"];

  echo "$count.) $title" ;
  $count++ ;
  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< 
  Prev 10</a>&nbsp ";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

  echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
  }

$a = $s + ($limit) ;
  if ($a > $numrows) { $a = $numrows ; }
  $b = $s + 1 ;
  echo "<p>Showing results $b to $a of $numrows</p>";
  
?>

 

As of now, my error is "Unable to select database."  I have triple checked my username, PW, database name, location, and all that, so I think it's coming from my attempt to change this code to work with MySQLi.  Does anyone have any ideas?

 

Thanks,

Sarah

 

 

[GingerRobot]

Echo the error that mysql gives:

 

mysqli_select_db("meetingsEventLocation") or die("Unable to select database<br />".mysqli_error()); 

 

 

[MNSarahG]

Hey,

 

I pasted that code into the file and it still just comes back with "Unable to Select Database" (no extra info).

 

- Sarah -

[GingerRobot]

Looks like you need the mysqli_connect_error() function rather than mysqli_error(). Try that and see what it says.

[MNSarahG]

This (like all of these problems) is blowing my mind.  I changed my connect statement to this:

 

mysqli_connect("localhost","meetings","m33tings123","meetingsEventLocation")
or die("<strong>Couldn't connect to database</strong>".mysqli_connect_error());

 

And now it seems to connect to the DB okay.  Now my error is "Couldn't execute query."  Not sure why.

 

Thanks again for any advice!