need help with a variable :)

[sinista]

Hi guys can somone help me with this please ,

 

the problem is a cant get my php variable ($link)  into the hidden input box's value, any help wold be great.

 

<?php
			  

$host="localhost";
$username="root";
$password="sarah2004"; 
$db_name="user";
$tbl_name="members";


mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

$result = mysql_query("SELECT * FROM $tbl_name ");


while($row = mysql_fetch_array($result))
  {
echo "<br>";
echo $row['username'];
echo"<br>";
echo $row['avatar']; 
echo"<br>";
$link=$row['username'];
echo'<form name="form2" method="post" action="profiletemplate.php">
  <input name="searchname" type="hidden" id="searchname" Value="<?php echo $link; ?> ">
  <label>
  <input type="submit" name="Submit" value="MyProfile">
  </label>
</form>';
echo"<br>";
  }

mysql_close();

?>

 

thanks in advance.

 

[monkeypaw201]

PHP cannot parse variables in single quotes, flip flop it.. in HTML put single quotes and put double around HTML and it should work

[jonsjava]

<?php
			  

$host="localhost";
$username="root";
$password="sarah2004"; 
$db_name="user";
$tbl_name="members";


mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

$result = mysql_query("SELECT * FROM $tbl_name ");


while($row = mysql_fetch_array($result))
  {
echo "<br>";
echo $row['username'];
echo"<br>";
echo $row['avatar']; 
echo"<br>";
$link=$row['username'];
echo"<form name='form2' method='post' action='profiletemplate.php'>
  <input name='searchname' type='hidden' id='searchname' Value='$link'>
  <label>
  <input type='submit' name='Submit' value='MyProfile'>
  </label>
</form>";
echo"<br>";
  }

mysql_close();

?>

[sinista]

Thanks so much  for the replys,  that works perfectly, lol ive been trying to work that out all day the damn quotes get me everytime:))