[SOLVED] php date

[trilbyfish]

How would i set uo the php date function so that at 6pm it prints the following day?

 

So it would say 'table for 'today's date'' upto 5:59pm and then at 6pm it was say 'table for 'tomorrow's date''?

 

I hope i have explained this so someone can understand it, its hard to explain.

 

Thanks in advance

[tibberous]

echo (if(date('G') < 14) ? date('l') : date('l', time()+60*60*24));

 

That work?

[trilbyfish]

Ahha i didnt think of that!

 

No that didnt work, but maybe if i did something like if hour<6 echo todays date

else echo tomorrows date.

 

How would i do that?

[GingerRobot]

Tibberous was pretty much there - just you dont need the if keyword with the ternary operator, and that we should be checking if the hour is less than 18, not 14:

 

echo ((date('G') < 18) ? date('l') : date('l', time()+60*60*24));

[trilbyfish]

Thanks for that, it was really helpful.

 

One more thing, how could i improve on that so that also tomorrows date is displayed after 6pm, and not just the day?

 

Thanks in advance

[GingerRobot]

Take a look at the date() function. It will show you how to achieve whatever output you're looking for. Basically, you need to change the 'l' for whatever you want.

[Yesideez]

Just to be picky...

 

There's now two sets of brackets so you could use this:

echo (date('G')<18) ? date('l') : date('l',time()+60*60*24);

[trilbyfish]

How do i do the (date('G')<18) ? date('l') : date('l',time()+60*60*24) thing so that if the next day is a saturday or sunday, it shows monday?

[GingerRobot]

Well im guessing you want this to show monday at any time over the weekend too?

 

Try:

 

<?php
$x=0;
$day = date('N');
$hour = date('G');
if($day == 5 && $hour >= 18){//after 6 on friday
    $x = 3;
}elseif($day == 6){//saturday
    $x = 2;
}elseif($day == 7){//sunday
    $x=1;
}elseif($hour >= 18){//any other day of the week
    $x=1;
}
echo date('l dS F',time()+60*60*24*$x);
?>

[trilbyfish]

Thank you very much