Clinton Posted April 24, 2008 Share Posted April 24, 2008 I don't see why this wouldn't work but can I not set a parameter using a parameter? $cdlmedicaltrue = $cdlmedical; <? $result = mysql_query("SELECT lname, fname, cdlmedical FROM training ORDER BY lname"); $now = date('n/j/Y'); $cdlmedicaltrue = $cdlmedical; echo "Real Date: $cdlmedicaltrue"; $cdlmedicaltrue = date('n/j/Y',$cdlmedicaltrue); while ($row=mysql_fetch_assoc($result)){ extract($row); $cdlmedical = strtotime($cdlmedical.'+ 11 months'); $cdlmedical = date('n/j/Y',$cdlmedical); if ($now>=$cdlmedical) echo "$fname $lname is due for a CDL Medical Evaluation! It Expires $cdlmedicaltrue"; else echo " "; } ?> Link to comment https://forums.phpfreaks.com/topic/102735-solved-setting-parameter-using-parameter/ Share on other sites More sharing options...
haku Posted April 24, 2008 Share Posted April 24, 2008 You have to declare $cdmedical before you can use it. Link to comment https://forums.phpfreaks.com/topic/102735-solved-setting-parameter-using-parameter/#findComment-526134 Share on other sites More sharing options...
Clinton Posted April 24, 2008 Author Share Posted April 24, 2008 Yea, that was a bone headed mistake. Thank you. Link to comment https://forums.phpfreaks.com/topic/102735-solved-setting-parameter-using-parameter/#findComment-526146 Share on other sites More sharing options...
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