[SOLVED] conditional help

[LemonInflux]

I have my regex function here:

 

preg_replace("#\{% $tag %\}#si", $replace, $str)

 

If that could be tidier, please tell me. Basically, what it does, is go through $str, find matches for:

 

{% TAG_NAME_HERE %}

 

and replace that all with $replace. For example, if $tag = bob and $replace = jim, this string:

 

'Hello, {% bob %}'

 

would be changed to:

 

'Hello, jim'

 

Now, what I want to do is add something so if I do, say...

 

'Hello {{% bob %}}' that doesn't change it, because it has a double brackets.

 

In a nutshell, what I'm asking is...

 

How do I change "#\{% $tag %\}#si" to only pick up {% tag %} and not {{% tag %}}

 

Sorry if this is terribly explained. Just ask and I'll try to explain it a bit more simply.

 

Thanks in advance!

 

Tom.

[effigy]

#(?<!\{)\{% $tag %\}(?!\{)#si

#(?<!\{)\{% $tag %\}(?!\})#si

 

If $tag is coming from an outside source, be sure to pass it through preg_quote.

[LemonInflux]

Thanks! Can't test it just yet, but if there's any problems I'll post again.

 

Many thanks!

[LemonInflux]

Haven't checked yet, but should it be....

 

[pre]#(?<!\{)\{% $tag %\}(?!\})#si[/pre]

 

Instead? Looking at the last bit on yours: (?!\{)#si, surely because the brace is facing right, that would mean {{TAG}{ would work, not {{% TAG %}}?

[effigy]

Right. My oversight.

[LemonInflux]

Ok, thanks