problem with retrieving an id

joinx · April 29, 2008

I have to display information about a product ...to do that i have to retrieve the id from the database..

when the user click on more info it goes to the info page...the product i d is being recognised

like this

http://localhost/jacey/info.php?product_id=16

but nothing is being displayed in the next page..

here is the code for info.php

<?php require_once('../Connections/JaceyConn.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") 
{
  $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;

  $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

  switch ($theType) {
    case "text":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;    
    case "long":
    case "int":
      $theValue = ($theValue != "") ? intval($theValue) : "NULL";
      break;
    case "double":
      $theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL";
      break;
    case "date":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;
    case "defined":
      $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
      break;
  }
  return $theValue;
}
}

$colname_info = "-1";
if (isset($_SERVER['product_id'])) {
  $colname_info = $_SERVER['product_id'];
}
mysql_select_db($database_JaceyConn, $JaceyConn);
$query_info = sprintf("SELECT product_id, product_model, product_image, Product_name, product_price, `Description`, products_status FROM product WHERE product_id = %s", GetSQLValueString($colname_info, "int"));
$info = mysql_query($query_info, $JaceyConn) or die(mysql_error());
$row_info = mysql_fetch_assoc($info);
$totalRows_info = mysql_num_rows($info);
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"
"http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html>

<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
<meta name="description" content="description"/>
<meta name="keywords" content="keywords"/> 
<meta name="author" content="author"/> 
<link rel="stylesheet" type="text/css" href="bntemplate590/images590/default.css"/>
<title>Jacey</title>
<style type="text/css">
<!--
.style4 {font-size: 14pt}
body,td,th {
font-size: 9pt;
}
-->
</style></head>

<body>

<div class="main">

<div class="main_left">

<div class="header">
		<h1 align="center">Jacey Computers</h1>
  </div>

	<div class="link_menu">
		<a href="main.php" accesskey="1">Home</a>
		<a href="category.php" accesskey="2">Product</a>
		<a href="support.php" accesskey="3">Support & Help</a>
		<a href="contact.php" accesskey="4">Contact Us</a>		</div>

	<div class="content">
		       
      
	 <p> </p>
	 <table border="2">
         <?php  while ($row = mysql_fetch_array($info)){ ?>
		<?php $imageurl = $row['product_image']; ?>

<tr>
<td>
<img src="<?php echo $imageurl;?>" />
    <?php echo $row['Product_name']."<br><font color=red>Price:</font>Rs".$row['product_price'];?>

<form name="form" action="showcart.php" method="POST">
<input name="product_id" type="hidden" value="<?php echo $row['product_id'];?>" />
<input type="submit" value="Add To cart">
<input type="hidden" name="MM_insert" value="form" />
</form>

</td>
</tr>
<?php }?>

   </table>
   <?php echo $row['product_id'];?>
            
  </div>
</div>

</div>
<div class="footer"></div>
</div>
<br style="clear: both;" />

</body>

</html>

I am having this same problem evrywhere..i can't add to cart also..

theinfamousmielie · April 29, 2008

... you're using $_SERVER ??? why not use $_GET??

joinx · April 29, 2008

i was using $_GET first..but still not working...

when we echo something like $a=$row['product_id']...how to retrieve it on the next page..

dptr1988 · April 29, 2008

Yes, you need to use $_GET['product_id'] rather then $_SERVER['product_id'].

If you don't understand why, add print_r($_GET); and print_r($_SERVER); and you will see the contents of both of those variables.

moselkady · April 29, 2008

Try to print the variable $query_info to see how the query looks like and maybe post it to us

theinfamousmielie · April 29, 2008

okay first of all, here's the deal

i reckon you're getting an empty page because there's no 'productid' of -1 ... here's what you're doing:

$colname_info = "-1";

if (isset($_SERVER['product_id'])) {

$colname_info = $_SERVER['product_id'];

}

You're defining the default, then running a check on a server global variable (which should be get) to see if it's set, but not 'overriding' it if it isn't. This is what i'd do instead:

if (!isset($_GET['product_id'])) {

header('location:back-to-the-previous-page.php');

} else {

$colname_info = $_GET['product_id'];

}

That should help out? I hope ... heheh

joinx · April 29, 2008

ok made the changes...

now it looks like that...

<?php require_once('../Connections/JaceyConn.php'); ?>
<?php
$colname_info = (int)$_GET['product_id']

mysql_select_db($database_JaceyConn, $JaceyConn);
$query_info = sprintf("SELECT product_id, product_model, product_image, Product_name, product_price, `Description`, products_status FROM product WHERE product_id = $colname_info" );
$info = mysql_query($query_info, $JaceyConn) or die(mysql_error());
$row_info = mysql_fetch_assoc($info);
$totalRows_info = mysql_num_rows($info);
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"
"http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html>

<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
<meta name="description" content="description"/>
<meta name="keywords" content="keywords"/> 
<meta name="author" content="author"/> 
<link rel="stylesheet" type="text/css" href="bntemplate590/images590/default.css"/>
<title>Jacey</title>
<style type="text/css">
<!--
.style4 {font-size: 14pt}
body,td,th {
font-size: 9pt;
}
-->
</style></head>

<body>

<div class="main">

<div class="main_left">

<div class="header">
		<h1 align="center">Jacey Computers</h1>
  </div>

	<div class="link_menu">
		<a href="main.php" accesskey="1">Home</a>
		<a href="category.php" accesskey="2">Product</a>
		<a href="support.php" accesskey="3">Support & Help</a>
		<a href="contact.php" accesskey="4">Contact Us</a>		</div>

	<div class="content">
		       
      
	 <p> </p>
	 <table border="2">
         <?php  while ($row = mysql_fetch_array($info)){ ?>
		<?php $imageurl = $row['product_image']; ?>

<tr>
<td>
<img src="<?php echo $imageurl;?>" />
    <?php echo $row['Product_name']."<br><font color=red>Price:</font>Rs".$row['product_price'];?>

<form name="form" action="showcart.php" method="POST">
<input name="product_id" type="hidden" value="<?php echo $row['product_id'];?>" />
<input type="submit" value="Add To cart">
<input type="hidden" name="MM_insert" value="form" />
</form>

</td>
</tr>
<?php }?>

   </table>
   <?php echo $row['product_id'];?>
            
  </div>
</div>

</div>
<div class="footer"></div>
</div>
<br style="clear: both;" />

</body>

</html>

to display from that array..we should use

$row = mysql_fetch_array($id); is this wrong??

Because some of my pages are not being displayed and not even retrieving the data from the database...

what should i do?

theinfamousmielie · April 29, 2008

Replace the top block of PHP with this for me, and paste in the results

<?php require_once('../Connections/JaceyConn.php'); ?>

<?php

$colname_info = (int)$_GET['product_id']

mysql_select_db($database_JaceyConn, $JaceyConn);

$query_info = sprintf("SELECT product_id, product_model, product_image, Product_name, product_price, `Description`, products_status FROM product WHERE product_id = $colname_info" );

$info = mysql_query($query_info, $JaceyConn) or die(mysql_error());

$row_info = mysql_fetch_assoc($info);

$totalRows_info = mysql_num_rows($info);

echo '<pre>';

echo '$query_info = ';

var_dump($query_info)

echo ' ';

echo '$info = ';

var_dump($info)

echo ' ';

echo '$row_info= ';

var_dump($row_info)

echo ' ';

echo '</pre>';

?>

joinx · April 29, 2008

here is the output:

$query_info ="SELECT product_id, product_model, product_image, Product_name, product_price, `Description`, products_status FROM product WHERE product_id = $colname_info" string(143) "SELECT product_id, product_model, product_image, Product_name, product_price, `Description`, products_status FROM product WHERE product_id = 16" $info = mysql_query($query_info, $JaceyConn) or die(mysql_error())resource(4) of type (mysql result) $row_info= mysql_fetch_assoc($info)array(7) { ["product_id"]=> string(2) "16" ["product_model"]=> string(4) "H755" ["product_image"]=> string(39) "C:/Apache2.2/htdocs/Prod/Laptop/hp2.jpg" ["Product_name"]=> string(23) "HP Compaq Presario F755" ["product_price"]=> string(5) "50000" ["Description"]=> string(853) "Full Specifications: HP Compaq Presario F755 Brand processor : AMD Processor Class: Turion 64x2 Processor Speed: 1.9 GHz Installed Memory: 2 GB Maximum Memory: 3 GB Memory Technology: DDR II SDRAM Cache Size :1 MB Video Memory: 128 MB Hard Drive Capacity :160 GB Included Drives: DVD±RW (±R DL) / DVD-RAM / HD DVD-ROM CD Write Speed :16 X CD Rewrite Speed: 10 X CD Read Speed: 24 X DVD Read Speed: 8 X DVD Write Speed :4x (DVD±R), 2x (DVD-R DL), 2.4x (DVD+R DL) Display Size: 15.4 in Display Type :TFT active matrix Graphics Processor: Intel GMA X1300 GT Resolution :1280 x 800 pixels Battery Life: 3.0 hrs Battery Type :Lithium ion Wireless Technology :Bluetooth Modem Speed :56 Kbps Software Operating System Microsoft Windows Vista installed Warranty 1 year " ["products_status"]=> string(1) "1" } $totalRows_info = mysql_num_rows($info)int(1)

moselkady · April 29, 2008

It seems that you have only one row in your table as $totalRows_info is equal to 1 and you already fetched that row before you start your HTML part. After that you make a loop to fetch the next rows and display their info, but there are no more rows.

I think you should remove this line from the top part of your code.

$row_info = mysql_fetch_assoc($info);

joinx · April 29, 2008

if i remove it then i should only use the array to retrieve the data..like that

while($row=mysql_fetch_array($info){

$row['product_id'];

.

.}

i am having that problem in almost all my pages...nothing is being retrieved from the database n displayed...

thnx a lot for ur help..

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