firedrop84 Posted May 24, 2006 Share Posted May 24, 2006 Hi .. I have a problem with the following code. I got a page that displays some results based on the data that is in the databse. the output it displays in a table.in that table there are 5 coloums. the the first row it just display the number. the second display the name. The forth coloumn it displays a button and the name of the button is the same name of the customer on that row. the last coloumn it just basically displays another button. my porblem is with the forth coloumn. that is with the buttons. I want when the employee clicks on that button it should go to another page. I tired to use isset with for loop nested with if but it didn't work. can anybody help me on solving the mistake that I have in my code. I changed the header to just print "Hello";and that just to test if it is going to display but it didn't. // The databse result has already been retrieved// the problem is with this code $y = 0; for ($v = 0; $v < $HowMany; $v++) { $y++; if (isset($_POST["$Name[$y]"])) { print "Hello"; } }// Then I have displayed the table Quote Link to comment https://forums.phpfreaks.com/topic/10345-for-loop-nested-with-if/ Share on other sites More sharing options...
eves Posted May 24, 2006 Share Posted May 24, 2006 can you post the codes on the page where it is posted from?also you might want to check if the checkbox is named as "Name[]" Quote Link to comment https://forums.phpfreaks.com/topic/10345-for-loop-nested-with-if/#findComment-38551 Share on other sites More sharing options...
firedrop84 Posted May 24, 2006 Author Share Posted May 24, 2006 Here is the code for the page[code]<?php // connect tot he database require ('connection.php');$GetFollowUp = mysql_query("SELECT p.ProspectID, p.RegDate, p.Title, p.Surname, p.GivenName, p.FlatRoomNumber, p.StreetNumber, p.StreetName, p.Suburb, p.State, p.PostCode, p.Primary, p.Other, p.Email, p.EnquiryType, p.Source FROM prospect p, followup f WHERE (f.ProspectID = p.ProspectID)"); $HowMany = mysql_num_rows($GetFollowUp); $y = 0; for ($v = 0; $v < $HowMany; $v++) { $y++; if (isset($_POST["$Name[$y]"])) { print "Hello"; } } if ($GetFollowUp && $HowMany != 0) { $i = 0; while($data = mysql_fetch_array($GetFollowUp)) { $ProspectID[$i] = $data["ProspectID"]; $RegDate[$i] = $data["RegDate"]; $Title[$i] = $data["Title"]; $ProspectSearch[$i] = $data["Surname"]; $ProspectGivenName[$i] = $data["GivenName"]; $FlatRoomNumber[$i] = $data["FlatRoomNumber"]; $StreetNumber[$i] = $data["StreetNumber"]; $StreetName[$i] = $data["StreetName"]; $Suburb[$i] = $data["Suburb"]; $State[$i] = $data["State"]; $PostCode[$i] = $data["PostCode"]; $Primary[$i] = $data["Primary"]; $Other[$i] = $data["Other"]; $Email[$i] = $data["Email"]; $EnquiryType[$i] = $data["EnquiryType"]; $Source[$i] = $data["Source"]; $i++; } } for ($w = 0; $w < $HowMany; $w++) { $Name[$w] = "$ProspectSearch[$w]" . " $ProspectGivenName[$w]"; } mysql_close(); // Assign the Data that has been retrieved into an array if ($GetFollowUp && $HowMany != 0) { // Dispalay the headings print "<form name=\"form1\" method=\"post\" action=\"\">"; print "<table width=\"500\" border=\"0\" align=\"center\">"; print "<tr bgcolor=\"#0033FF\">"; print "<td><div align=\"center\"><span class=\"style3\">No. </span></div></td>"; print "<td><div align=\"center\"><span class=\"style3\">Follow Ups </span></div></td>"; print "<td bgcolor=\"#0033FF\"> Quick Add </td>"; print "<td> Prospect Details </td>"; print "<td> Completed </td>"; print "</tr>"; $n = 1; // Display the data for ($x = 0; $x < $HowMany; $x++) { $BtnCompleted[$n] = "BtnCompleted$n"; print "<tr bgcolor=\"#EEEEEE\">"; print "<td>$n</td>"; print "<td>$ProspectSearch[$x] $ProspectGivenName[$x] </td>"; print "<td> No</td>"; print "<td> <input type=\"submit\" name=\"$Name[$x]\" value=\"Details\"></td>"; print "<td> <input type=\"submit\" name=\"$BtnCompleted[$n]\" value=\"Completed\"></td>"; print "</tr>"; $n++; } } elseif ($HowMany == 0) { // Dispalay the headings print "<form name=\"form1\" method=\"post\" action=\"\">"; print "<table width=\"200\" border=\"0\" align=\"center\">"; print "<tr bgcolor=\"#0033FF\">"; print "<td width=\"40\"><div align=\"center\"><span class=\"style3\">No. </span></div></td>"; print "<td width=\"144\"><div align=\"center\"><span class=\"style3\">Follow Ups </span></div></td>"; print "</tr>"; print "<tr bgcolor=\"#EEEEEE\">"; print "<td colspan=2> <center> No Follow Ups </center></td>"; print "</tr>"; print "</table> </form>"; }?>[/code] Quote Link to comment https://forums.phpfreaks.com/topic/10345-for-loop-nested-with-if/#findComment-38556 Share on other sites More sharing options...
.josh Posted May 24, 2006 Share Posted May 24, 2006 [code] if (isset($_POST["$Name[$y]"])) { print "Hello";[/code]that's fine and dandy... except that you have not set $Name anywhere, so the condition will never be true. Quote Link to comment https://forums.phpfreaks.com/topic/10345-for-loop-nested-with-if/#findComment-38650 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.