[SOLVED] image not displaying

[jasonhardwick]

I posted this question earlier but still no luck. for some reason my echo on the last line of the code doesn't produce an image and i'm not sure why any ideas.

 

thanks

 

 
<?php 

$img_path = "file/".$rows ['file'];

$image_t = getimagesize($img_path); 

imageResize($image_t[0],  
$image_t[1], 100); 

function imageResize($width, $height, $target) {  

if ($width > $height) { 
$percentage = ($target / $width); 
} else { 
$percentage = ($target / $height); 
} 

$width = round($width * $percentage); 
$height = round($height * $percentage); 

return "width=\"$width\" height=\"$height\""; 
} 

echo "<img src=$image_t>";

?>

[thebadbad]

The source to the image isn't $image_t, since that contains the array returned by getimagesize(). Also, you're not 'catching' the returned string of your function. Is this what you want?:

 

<?php
$img_path = "file/".$rows ['file'];

$image_t = getimagesize($img_path); 

//edited this
$wh = imageResize($image_t[0],  
$image_t[1], 100);

function imageResize($width, $height, $target) {

if ($width > $height) {
$percentage = ($target / $width);
} else {
$percentage = ($target / $height);
}

$width = round($width * $percentage);
$height = round($height * $percentage);

return "width=\"$width\" height=\"$height\"";
}

//and this
echo "<img src=\"$img_path\" $wh />";
?>

[jasonhardwick]

Thanks That worked.