[SOLVED] SQL AVG of values with common value in same table

[hnumar7]

I hope I can explain this well enough for someone to offer me some help.

 

I have a table called rate which has values 1-5 and an ID

 

the table looks like this:

 

rated - ID

 

5        10

4        10

3        8

2        8

 

I am attempting to try and get the highest average of any ID based on the values in column rated

 

so in the above example ID 10 would have an average of 4.5  and ID 8 would have an average of 2.5  ,  so ID 10 would be have the highest average and ID 8 would have the lowest average.

 

Does anyone know what my select statement or php code should look like to accomplish this?  I am somewhat comfortable with PHP. Any help or suggestions would be very much appreciated

 

Thanks

 

Henry

 

   

[mezise]

If I get you correctly, to get ID with highest AVG use this query:

SELECT
  ID
  , AVG(rated) avgRate
FROM rate
GROUP BY
  ID
ORDER BY
  avgRate DESC
LIMIT 1
;

 

To get the lowest, change "avgRate DESC" to "avgRate ASC".

[hnumar7]

If I get you correctly, to get ID with highest AVG use this query:

SELECT
  ID
  , AVG(rated) avgRate
FROM rate
GROUP BY
  ID
ORDER BY
  avgRate DESC
LIMIT 1
;

 

To get the lowest, change "avgRate DESC" to "avgRate ASC".

 

 

Thanks so much.... I knew this was easy just couldn't figure it out!!... Thanks again for helping out a Newbie