[SOLVED] Running this function without a form

[unknown101]

Hi guys, im using an ID3 class which extracts data from .mp3s.

 

Everything works but fine I want to make one further change.  I have added a upload part at the start of the script which copies the file to a given directory and I then went to the script to scan that directory automatically when that file is uploaded, rather than having to press 2 seperate buttons.

 

Currently I have to upload then hit another button to run the scan function.

 

The form which scans the directory looks like below:

 

echo '<hr><form action="'.FixTextFields($_SERVER['PHP_SELF']).'">';

echo '<b>Warning:</b> Scanning a new directory will erase all previous entries in the database!<br>';

echo 'Directory: <input type="text" name="scan" size="50" value="'.FixTextFields($text).'"> ';

echo '<input type="submit" value="Go" onClick="return confirm(\'Are you sure you want to erase all entries in the database and start scanning again?\');">';

echo '</form>';

 

The $text variable is a static var which has alrdy been set so I dont need the above within a form, i just need it to run when an upload is carried out.  (So I can just set the action of the upload form to run the whole script).

 

How can i modify the above to just run those functions without the initialisation of user pressing the button?

 

Thanks in advance

[GingerRobot]

Well, you could use some javascript to submit the form once the page has loaded, but that seems a bit stupid. You need to address this with the section of code which is executed when the form has been submitted - basically remove the check to see if the form has been submitted, then instead to taking the values from the forms, define them with the values you want.

[unknown101]

Cheers, removed all checks and works great