How to refer to an undefined offset in an array?

[benphp]

This will error out if the example number is a whole number (3, 9 33, etc.). I want to do something like:

 

if (strlen($ex[1]) == NULL)

 

but that doesn't work. How do you refer to an undefined element? or can you?

 

<?php 
print "<form method=\"post\">";
print "<input type=\"text\" name=\"example\" size=\"6\" maxlength=\"6\">";
print "<input type=\"submit\" name=\"btnSubmit\" value=\"Round It\">";
print "</form>";

$example = "";
if (isset($_POST['example'])) {
$example = $_POST['example']/3;
$example = round($example, 2);
$ex = explode(".", $example);
if (strlen($ex[1]) == 0) {
	$example = $example."00";
} else if (strlen($ex[1]) == 1) {
	$example = $example."0";
}
print "$example";
}
?>

[Lumio]

<?php
   if (isset($ex[1]) === true && strlen($ex[1]) == 0) {
      //do it!
   }
?>

Also convert $example into a string. That's better for php:

$example = strval($example);
$ex = explode($example);

 

greetings

[benphp]

I've tried variations of that - no good. I still get "Undefined offset" for that line.

 

BTW what does the three === do that == doesn't? I've seen it around but never used it.

[sasa]

just use

$example = number_format($_POST['example']/3,2);

[benphp]

Yes, that's easier.