Matching A Field's Multiple Comma Seperated Values to Another Field's Values

CloudSex13 · May 15, 2008

To MadTechie:

THAT WORKED.

But it only displayed one entry, for the White Tee.

What if AccountProductList = "1, 1, 3, 1, 71"

Could it display each one?

The Little Guy · May 15, 2008

function count_array($val,$array){
$i = 0;
if(!is_array){
	return 'Second value is not an array.';
}else{
	foreach($array as $v){
		if($val == $v){
			$i++;
		}
	}
	return $i;
}
}

session_start();
$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '{$_SESSION['id']}'");
$row = mysql_fetch_array($sql);
$prods = explode(",",$row['AccountProductList']);
$listed = array();
foreach($prods as $prod){
     $p = trim($prod);
     $sql2 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p'");
     $row2 = mysql_fetch_array($sql2);
 if(!in_array($p,$listed)){
	echo 'ProductName: '.$row2['ProductName'].' ( '.count_array($p,$prods).' )<br />';
	$listed[] = $p;
}
}

CloudSex13 · May 15, 2008

To TheLittleGuy:

THANK YOU AGAIN.

I've been trying to accomplish this for about a month.

Oh my god.

=)

I also made a little change to organize the results by ProductType and separate them into different HTML tables,

would you suggest doing it this way?

function count_array($val,$array){
$i = 0;
if(!is_array){
return 'Second value is not an array.';
}else{
foreach($array as $v){
if($val == $v){
$i++;
}
}
return $i;
}
}

$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '1'");
$row = mysql_fetch_array($sql);
$prods = explode(",",$row['AccountProductList']);
$listed = array();
foreach($prods as $prod){
     $p = trim($prod);
     $sql2 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p' AND ProductType='Shirt'");
     $row2 = mysql_fetch_array($sql2);
if(!in_array($p,$listed)){
     echo "Shirts: ".$row2['ProductName']." (".count_array($p,$prods).") - $".$row2['ProductPrice']."<br>";
$listed[] = $p;
}
     $sql3 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p' AND ProductType='Shoes'");
     $row3 = mysql_fetch_array($sql3);
if(!in_array($p,$listed)){
     echo "Shoes: ".$row3['ProductName']." (".count_array($p,$prods).") - $".$row3['ProductPrice']."<br>";
$listed[] = $p;
}
     $sql4 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p' AND ProductType='Pants'");
     $row4 = mysql_fetch_array($sql4);
if(!in_array($p,$listed)){
     echo "Pants: ".$row4['ProductName']." (".count_array($p,$prods).") - $".$row4['ProductPrice']."<br>";
$listed[] = $p;
}
}

MadTechie · May 15, 2008

for some reason the IN doesn't like a varchar so i changed it to suite

<html>
<head>
<title>
Inventory
</title>
</head>
<body>
<div align=center>
<br><br><br>
<?php
$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '{$_SESSION['id']}'");
$row = mysql_fetch_array($sql);
$APL = $row['AccountProductList'];
$AccountID=$row['AccountID'];
$AccountName=$row['AccountName'];
?>
<b>Account ID</b>: <?php echo($AccountID); ?> | 
<b>Account Name</b>: <?php echo($AccountName); ?>
<br><br>
<?php
$getaccountlist = mysql_query("SELECT * FROM Products WHERE ProductID IN ($APL) ORDER BY ProductType");
echo "
<table>
<tr>
<td align=center colspan=4>
<b>Shirts</b>
</td>
</tr>
<tr>
<td>
Product ID
</td>
<td>
Product Name
</td>
<td>
Product Type
</td>
<td>
Product Price
</td>
</tr>";

$type = "";
while($row = mysql_fetch_array($getaccountlist))
{
$UserProductID = $row['ProductID'];
$UserProductName = $row['ProductName'];
$UserProductType = $row['ProductType'];
$UserProductPrice = $row['ProductPrice'];
//this If create headers for each type
if($type != $UserProductType)
{
	echo "<tr><td colspan=\"4\">$UserProductType</td></tr>";
	$type = $UserProductType;
}

echo "
<tr>
<td>
".$UserProductID."
</td>
<td>
".$UserProductName."
</td>
<td>
".$UserProductType."
</td>
<td>
".$UserProductPrice."
</td>
</tr>";
}

echo "</table>";
?>
</div>
</body>
</html>

CloudSex13 · May 15, 2008

To TheLittleGuy:

I just tested the code. It came out like this:

Shirts: White Tee (3) - $13
Shirts: (1) - $

Wtf?

The Little Guy · May 15, 2008

function count_array($val,$array){
$i = 0;
if(!is_array){
	return 'Second value is not an array.';
}else{
	foreach($array as $v){
		if($val == $v){
			$i++;
		}
	}
	return $i;
}
}


session_start();
$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '{$_SESSION['id']}'");
$row = mysql_fetch_array($sql);
$prods = explode(",",$row['AccountProductList']);
$listed = array();
foreach($prods as $prod){
     $p = trim($prod);
 if(!in_array($p,$listed)){
	$sql2 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p'");
	$row2 = mysql_fetch_array($sql2);
	echo 'ProductName: '.$row2['ProductName'].' ( '.count_array($p,$prods).' )<br />';
	$listed[] = $p;
}
}

CloudSex13 · May 15, 2008

I tried that out, still no luck with the ProductType separation. Any other suggestions man?

MadTechie · May 15, 2008

who code?

mine or TheLittleGuy:

CloudSex13 · May 15, 2008

To MadTechie:

That was to TheLittleGuy.

To TheLittleGuy:

I tried this code here using while statements,

but it seems to loop forever. Any suggestions if so?

<?php

function count_array($val,$array){
$i = 0;
if(!is_array){
return 'Second value is not an array.';
}else{
foreach($array as $v){
if($val == $v){
$i++;
}
}
return $i;
}
}

$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '1'");
$row = mysql_fetch_array($sql);
$prods = explode(",",$row['AccountProductList']);
$listed = array();
foreach($prods as $prod){
     $p = trim($prod);
if(!in_array($p,$listed)){
$sql2 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p' ORDER BY ProductName");
$row2 = mysql_fetch_array($sql2);
while ($row2['ProductType'] = "Shirt") {
$shirts = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
}
while ($row2['ProductType'] = "Pants") {
$pants = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
}
while ($row2['ProductType'] = "Shoes") {
$shoes = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
}
}
}

?>

<table>
<tr>
<td>
<b>Shirts:</b>
</td>
</tr>
<tr>
<td>
<?php echo($shirts); ?>
</td>
</tr>
<tr>
<td>
<b>Pants:</b>
</td>
</tr>
<tr>
<td>
<?php echo($pants); ?>
</td>
</tr>
<tr>
<td>
<b>Shoes:</b>
</td>
</tr>
<tr>
<td>
<?php echo($shoes); ?>
</td>
</tr>
</table>

MadTechie · May 15, 2008

$row2['ProductType'] = "Shirt"

should be

$row2['ProductType'] == "Shirt"

on all 3 whiles

CloudSex13 · May 16, 2008

I love you.

CloudSex13 · May 16, 2008

I actually ran into another problem, but I tried to write a workaround but it did not work. Each section only displays one of each product type from AccountProductList. Is there any way for all of them to display? Here's the code I was working on and I'm surprised doesn't work:

$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '1'");
$row = mysql_fetch_array($sql);
$prods = explode(",",$row['AccountProductList']);
$listed = array();
foreach($prods as $prod){
     $p = trim($prod);
if(!in_array($p,$listed)){
$sql2 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p' ORDER BY ProductName");
$totalshirts = 1;
$totalpants = 1;
$totalshoes = 1;
while ($row2 = mysql_fetch_array($sql2)) {
if ($row2['ProductType'] == "Shirt") {
if ($totalshirts == 1) {
$shirts = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshirts = 2; 
} else { 
$shirts = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshirts = 1; 
}
} elseif ($row2['ProductType'] == "Pants") {
if ($totalpants == 1) {
$pants = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalpants = 2; 
} else { 
$pants = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalpants = 1; 
}
} elseif ($row2['ProductType'] == "Shoes") {
if ($totalshoes == 1) {
$shoes = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshoes = 2; 
} else { 
$shoes = ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshoes = 1; 
}
}
}
}
}

?>

<table>
<tr>
<td>
<b>Shirts:</b>
</td>
</tr>
<tr>
<td>
<?php echo($shirts); ?>
</td>
</tr>
<tr>
<td>
<b>Pants:</b>
</td>
</tr>
<tr>
<td>
<?php echo($pants); ?>
</td>
</tr>
<tr>
<td>
<b>Shoes:</b>
</td>
</tr>
<tr>
<td>
<?php echo($shoes); ?>
</td>
</tr>
</table>

CloudSex13 · May 16, 2008

--

CloudSex13 · May 16, 2008

--

CloudSex13 · May 16, 2008

I still have one minor problem, the results won't organize by ProductName as they're intended too. Any further suggestions?

$sql = mysql_query("SELECT * FROM Account WHERE AccountID = '1'");
$row = mysql_fetch_array($sql);
$prods = explode(",",$row['AccountProductList']);
$listed = array();
foreach($prods as $prod){
     $p = trim($prod);
if(!in_array($p,$listed)){
$sql2 = mysql_query("SELECT * FROM Products WHERE ProductID = '$p' ORDER BY ProductName");
$totalshirts = 1;
$totalpants = 1;
$totalshoes = 1;
while ($row2 = mysql_fetch_array($sql2)) {
if ($row2['ProductType'] == "Shirt") {
if ($totalshirts == 1) {
$shirts .= ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshirts = 2; 
} else { 
$shirts .= ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshirts = 1; 
}
} elseif ($row2['ProductType'] == "Pants") {
if ($totalpants == 1) {
$pants .= ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalpants = 2; 
} else { 
$pants .= ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalpants = 1; 
}
} elseif ($row2['ProductType'] == "Shoes") {
if ($totalshoes == 1) {
$shoes .= ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshoes = 2; 
} else { 
$shoes .= ''.$row2['ProductName'].' ('.count_array($p,$prods).')<br />';
$listed[] = $p;
$totalshoes = 1; 
}
}
}
}
}

?>

<table>
<tr>
<td>
<b>Shirts:</b>
</td>
</tr>
<tr>
<td>
<?php echo($shirts); ?>
</td>
</tr>
<tr>
<td>
<b>Pants:</b>
</td>
</tr>
<tr>
<td>
<?php echo($pants); ?>
</td>
</tr>
<tr>
<td>
<b>Shoes:</b>
</td>
</tr>
<tr>
<td>
<?php echo($shoes); ?>
</td>
</tr>
</table>

CloudSex13 · May 16, 2008

I apologize for all the posts. The database was having problems and posted everything multiple times. I only meant to post the one reply above this reply.

CloudSex13 · May 16, 2008

Hmm... I'm still searching for a solution to the ORDER BY problem. Anyone else has any suggestions?

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