[SOLVED] Problem with Preg_Match

[Styles2304]

If I shorten this to one line, it will populate an array but otherwise, it shows me an empty array. I thought at first it was because of white space but if I remove it all and put it on one long line, it still returns an empty array. Any ideas?

 

<?php
//Setting up the Patterns
$WeatherPattern = '/<td rowspan=\"3\" align=\"center\" class=\"weatherTempText\">(.*?)<\/td>
      <td align=\"center\" colspan=\"2\" class=\"weatherText\">
        
      <\/td>

    <\/tr>
    <tr>
      <td align=\"center\" class=\"weatherText\">WIND<\/td>
      <td align=\"center\" class=\"weatherText\">HUMIDITY<\/td>
    <\/tr>
    <tr>
      <td align=\"center\" class=\"weatherText\">(.*?) (.*?)<\/td>

      <td align=\"center\" class=\"weatherText\">(.*?)%<\/td>
    <\/tr>
    <\/table>
    <\/span>
  <\/td>
<\/tr>
<tr>
  <td class=\"radarimage\">
    <a href=\"\/content\/weather\"><img src=\"\/cache\/weather_current_conditions_radar_image\" border=0><\/a>

  <\/td>
<\/tr>
<tr>
  <td>
    <table border=\"0\" width=\"100%\" cellspacing=\"0\" cellpadding=\"0\">
    <tr>

      <td class=\"weatherTable\" align=\"center\">
        <span class=\"weatherText\">(.*?)<\/span><br>
        <img src=\"(.*?)\" ><br>

        <span class=\"weatherTemp2Text\">(.*?)<\/span>
      <\/td>
      <td class=\"weatherTable\" align=\"center\">
        <span class=\"weatherText\">(.*?)<\/span><br>
        <img src=\"(.*?)\" ><br>
        <span class=\"weatherTemp2Text\">(.*?)<\/span>
      <\/td>

      <td class=\"weatherTable\" align=\"center\">
        <span class=\"weatherText\">(.*?)<\/span><br>
        <img src=\"(.*?)\" ><br>
        <span class=\"weatherTemp2Text\">(.*?)<\/span>/';

//Getting the Info
$Page = file_get_contents('http://mywabashvalley.com/index.php');
preg_match($WeatherPattern, $Page, $Output);
print_r($Output);
?>

[helraizer]

preg_match("/$WeatherPattern/i", $Page, $Output);

 

Try that.

[hansford]

yeah you're going to have problems with that long a string.

 

you should try to match the first part of the string, wildcard everything in between and match the last part of the string.

[Styles2304]

Helraizer . . . that gave me the uknown modifier '<' error.

 

Hansford, since I'm needing to pull parts of the website out, how do I wild card everything in between the sections I need?

[effigy]

<pre>
<?php
$page = file_get_contents('http://mywabashvalley.com/index.php');
$result = array();
$patterns = array(
	'/(?<=weatherTempText">)(?P<current_temp>\d+°)/',
	'/(?<=weatherText">)(?P<current_wind>\d+\s+[A-Z]+)/',
	'/(?<=weatherText">)(?P<current_humidity>\d+%)/',
	'/(?<=weatherText">)(?P<day>[A-Z]{3})(?![A-Z]).*?<img src="(?P<img>[^"]+).*?Temp2Text">(?P<temp>\d+°)/s'
);
foreach ($patterns as $pattern) {
	preg_match_all($pattern, $page, $matches, PREG_SET_ORDER);
	$num_matches = count($matches);
	foreach ($matches as $match) {
		foreach (array_keys($match) as $key) {
			if (preg_match('/\A\d+\z/', $key)) {
				continue;
			}
			if ($num_matches == 1) {
				$result[$key] = $match[$key];
			}
			else {
				if (!array_key_exists($key, $result) || !is_array($result[$key])) {
					$result[$key] = array();
				}
				array_push($result[$key], $match[$key]);
			}

		}
	}
}
print_r($result);
?>
</pre>

 

Array

(

    [current_temp] => 66°

    [current_wind] => 13 SSE

    [current_humidity] => 88%

    [day] => Array

        (

            [0] => TUE

            [1] => WED

            [2] => THU

        )

 

    => Array

        (

            [0] => /media/gif/PrtlyCldyTstorm0030.gif

            [1] => /media/gif/PrtlyCldyTstorm0030.gif

            [2] => /media/gif/PrtlyCldy0031.gif

        )

 

    [temp] => Array

        (

            [0] => 84°

            [1] => 83°

            [2] => 90°

        )

 

)

 

[Styles2304]

wow . . . thanks! That does the trick!

[effigy]

Does everything make sense?

[Styles2304]

yup, crystal clear . . . dunno why I didn't think of that. Just a little confusing mixing the preg_match with what I've learned so far. Thanks again.