phpretard Posted June 4, 2008 Share Posted June 4, 2008 SOURCE CODE FOR FORM: <form method='post' action=''> <input type='hidden' name='id[0]' value='7'> <input class=input type='text' name='Name[0]' value='Larry Clark'> <input type='hidden' name='id[1]' value='8'> <input class=input type='text' name='Name[1]' value='Chris Sarrett'> <input type='hidden' name='id[2]' value='9'> <input class=input type='text' name='Name[2]' value='Buck McCreary'> </form> I POST THIS TO: $size = count($_POST['Name']); echo $size; <--------- THIS DISPLAYS IS THE NUMBER "1" $i = 0; while ($i < $size) { $Name= $_POST['Name'][$i]; echo $Name; <--------- ALL THIS DISPLAYS IS THE LETTER "A" <--WHAT"S UP WITH THAT? --> $id = $_POST['id'][$i]; echo $id; <------------- ALL THIS DISPLAYS IS THE LETTER "A" <--WHAT"S UP WITH THAT? --> mysql_query("UPDATE coaches SET Name='$Name' WHERE id='$id' LIMIT 1"); ++$i; } Shouldn't it show the values of the fields? I just want to update the stinking DB in one shot. Quote Link to comment Share on other sites More sharing options...
phpretard Posted June 4, 2008 Author Share Posted June 4, 2008 Could the problem be that I have a session set when you get to and/or post the form? Quote Link to comment Share on other sites More sharing options...
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