toamanz Posted June 5, 2008 Share Posted June 5, 2008 Guys, I am having a tough time getting the value of this drop down box. Here is the drop down code i got.. <select size="1" name="DDList" id="DDList" onChange="xajax_changeScrapAccess(this.options[this.options.selectedIndex].value)"> {$DD_options} Where DD_options is as below <option selected>friends</option> <option>friends of friends</option> <option>everyone</option> Now here is the function function xajax_changeScrapAccess($arg) { $access_mode = $arg['scrpr']; if($access_mode=="everyone") { $access_mode = "EVERY"; } } I just want to get the value in $access_mode liek if the user select private, i should get the value private in access_mode variable? Help will be much appreciated Thanks Aman Link to comment https://forums.phpfreaks.com/topic/108900-to-get-the-value-of-the-drop-down-box-in-function/ Share on other sites More sharing options...
discomatt Posted June 5, 2008 Share Posted June 5, 2008 PHP wont see any form variables unless a form is posted. You can do this in the background using JavaScript... You seem to be confusing client-side and server-side scripting. Link to comment https://forums.phpfreaks.com/topic/108900-to-get-the-value-of-the-drop-down-box-in-function/#findComment-558641 Share on other sites More sharing options...
hansford Posted June 5, 2008 Share Posted June 5, 2008 this --> $access_mode = $arg['scrpr']; should just be --> $access_mode = $arg; Link to comment https://forums.phpfreaks.com/topic/108900-to-get-the-value-of-the-drop-down-box-in-function/#findComment-558656 Share on other sites More sharing options...
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