need some asstaince with table display

[webguync]

can anyone tell me what's wrong with the syntax on the code posted above?

[tapos]

see this http://www.php.net/manual/en/function.substr.php

[webguync]

OK, I figured out what was wrong with what I had, thanks

[webguync]

I am having a few issues with my form results page.

 

The employee name isn't displaying at all

 

<tr id="header"><th colspan="2" id="ResultsMessage">'.$message.'</th></tr>
<tr>
<td>Employee Name:'.$emp.'</td><td>Employee ID:'.$emp_id.'</td>
</tr>

 

the variables were set at the top of the page as

$emp = $_SESSION['emp_name'];
$emp_id = $_SESSION['emp_id'];

 

$message is set as

 

$message = 'Assessment Update results for '.$emp.',('.$emp_ID.')  submitted by '.$Assessor.','.$Assessor_ID.' on  '.$now;

 

$emp isn't displaying here either.

 

also how can I add html to $message. Whenever I try, I get an error

 

such as:

 

$message = 'Assessment Update results for '.$emp.',('.$emp_ID.')  submitted by '.$Assessor.','.$Assessor_ID.' on <span class="red"> '.$now</span>;

[darkfreaks]

<?php
echo'

<tr id="header"><th colspan="2" id="ResultsMessage">'.$message.'</th></tr>
<tr>
<td>Employee Name:'.$emp.'</td><td>Employee ID:'.$emp_id.'</td>
</tr>';


$message = "Assessment Update results for $emp,($emp_ID)  submitted by $Assessor,$Assessor_ID on $now";
?>

[webguync]

that didn't make any difference.

 

I have on a previous page, a form with input checkboxes and a select menu to choose different people to select different boxes of information. When they submit the form, they are sent to the results page with information on which boxes they selected and the name they selected from the form on the previous page.

 

the information from the text boxes selected displays fine, but the variable for the name chosen to select on does not.

 

here is the code I am using for the select menu

 

<select name="emp_id" onchange="this.form.submit()" />
    ';
while(list($id,$name,$emp_id) = mysql_fetch_row($result)){
// this will select the current employee int he dropdown box
$selected = $id == $eid ? "selected" : "";
    echo '<option value="'.$id.'" '.$selected.' />'.$name.' (' .$emp_id.')</option>'."\n";
$_SESSION['employee_name'] = $name;
$_SESSION['emp_id'] = $id;
}
echo '</select>

 

and then on the results page:

 

<tr>
<td>Employee Name:'.$emp.'| Employee ID:'.$emp_id.'</td>
</tr>

 

the session information from the select menu is not coming through to the next page (results page).