[SOLVED] How to turn a variable string into it's own variable?

[blurredvision]

I have a FOREACH loop running on an array.  With this FOREACH, each index is returned as the variable, $wildcard.  What I'd like to do is that for each index that runs, I'd like to turn the value of the $wildcard variable into it's own variable.

 

For example:

 

include('config.php');

$wildcardarray = array ('apple', 'orange', 'banana');
foreach ($wildcardarray as $wildcard) {
if ($wildcard == 'apple' || $wildcard == 'orange' || $wildcard = 'banana') {
	echo '<tr><td>' . $variable_in_question . ' <input type=checkbox blah blah />';
}
}

 

That's a rough example of what I'm trying to do, but where it has the $variable_in_question, I want that to be a dynamic variable that is created from whatever the value of $wildcard is.  So if $wildcard == apple, I want that variable to be $apple.  The $apple variable then comes from the included config file where I've stored multiple strings in a central location for easy editing.  In this example, $apple would be something like this: $apple = 'Check here for apple.'

 

Not the greatest example, but it should work to get my point across.  Can this be done, and how?  Thanks a lot for any help!

[Perad]

$wildcardarray = array ('apple', 'orange', 'banana');
foreach ($wildcardarray as $key => $wildcard) {
if ($wildcard == 'apple' || $wildcard == 'orange' || $wildcard = 'banana') {
	echo '<tr><td>' . $wildcard . ' <input type=checkbox blah blah />';
}
}

[thebadbad]

Perad, not what he's after. blurredvision, you're looking for a variable variable, i.e. $$wildcard

 

<?php
include('config.php');

$wildcardarray = array ('apple', 'orange', 'banana');
foreach ($wildcardarray as $wildcard) {
if ($wildcard == 'apple' || $wildcard == 'orange' || $wildcard = 'banana') {
	echo '<tr><td>' . $$wildcard . ' <input type=checkbox blah blah />';
}
}
?>

[blurredvision]

Awesome, didn't realize it'd be that easy.  Let me ask another question, then.  Using my example, what if my array looked like this:

 

<?php
include('config.php');

$wildcardarray = array ('$apple', '$orange', '$banana');
foreach ($wildcardarray as $wildcard) {
if ($wildcard == 'apple' || $wildcard == 'orange' || $wildcard = 'banana') {
	echo '<tr><td>' . $$wildcard . ' <input type=checkbox blah blah />';
}
}
?>

 

This example more closely mirrors the actual work I'm doing.  To shed a bit more light on this, I'm creating my array with an fgets from the first line of a text file, and each index of the array is created from comma delimited list.  This line of the text file would look something like this:

 

#$item1,$item2,$item3,$item4

 

...which would make the array look something like this:

 

$wildcardarray = (explode(",",substr(fgets($read),1)));

 

The # is to comment out that first line so our java program won't see it.  The $wildcardarray then looks like ([0] => $item1, [1] => $item2, so-on and so-forth).

 

I haven't checked with the superiors yet, but I'm guessing they'll want to keep the $ there since these are the variable names we'll be using.  However, the $ isn't really needed in this text file, and if I take it out, the variable variable works great.  However, how can I leave the $ in the values of the array and still get it to reference the config file and take the appropriate string?

 

I tried something like this, but it didn't work: $(substr($wildcard,1)

 

If that's confusing, then I apologize, I even confuse myself when I actually try to explain it.  If you guys do not understand what I'm trying to do, then forget about it, and I'll push to get rid of the $ in the text file I'm creating the array from.

 

Thanks!

[blurredvision]

Nevermind about my previous post, I got it working now.  I just had to do

 

$wildcard = substr($wildcard,1);

 

...before my echo statement, then use

 

$$wildcard

 

...in my echo statement.  I was just implementing it wrong.

 

Thanks a lot for the help!!!