Need Echo Statment!

ballouta · June 21, 2008

Hello

I have googled for an email upload form, i found a code that i can undersdtand, I tried to modify it so only .ask extension is allowed and the file doesn't exceed 200KB (line 39!)

I uploaded .ask file and it was sent successfullt (as I want), I also tried to upload other types of files and it didn't send it (as I want)

but the form didn't inform the user that the file was NOT send because it is of diffrent extension or file size.

I just want to add this echo statment please

thanks

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>E-mail with Attachment</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>
<body>
<?php
   if ($_SERVER['REQUEST_METHOD']=="POST"){

	$size = $_FILES['filename']['size'];
	$name = $_FILES['filename']['name'];
	$array = explode( '.' , $name);

   // we'll begin by assigning the To address and message subject
   $to="malekface@hotmail.com";

   $subject="E-mail with attachment";

   // get the sender's name and email address
   // we'll just plug them a variable to be used later
   $from = stripslashes($_POST['fromname'])."<".stripslashes($_POST['fromemail']).">";

   // generate a random string to be used as the boundary marker
   $mime_boundary="==Multipart_Boundary_x".md5(mt_rand())."x";

   // store the file information to variables for easier access
   $tmp_name = $_FILES['filename']['tmp_name'];
   $type = $_FILES['filename']['type'];
   $name = $_FILES['filename']['name']; echo "name: $name<br>";
   $size = $_FILES['filename']['size'];

   // here we'll hard code a text message
   // again, in reality, you'll normally get this from the form submission
   $message = "A New File from GSCLOnline,org: $name";

   // if the upload succeded, the file will exist
   if (file_exists($tmp_name) && $array[1] == 'ask' && $size < 200 ){

      // check to make sure that it is an uploaded file and not a system file
      if(is_uploaded_file($tmp_name) ){

         // open the file for a binary read
         $file = fopen($tmp_name,'rb');

         // read the file content into a variable
         $data = fread($file,filesize($tmp_name));

         // close the file
         fclose($file);

         // now we encode it and split it into acceptable length lines
         $data = chunk_split(base64_encode($data));
     }
echo "Credits are decreased<br>";

      // now we'll build the message headers
      $headers = "From: $from\r\n" .
         "MIME-Version: 1.0\r\n" .
         "Content-Type: multipart/mixed;\r\n" .
         " boundary=\"{$mime_boundary}\"";

      // next, we'll build the message body
      // note that we insert two dashes in front of the
      // MIME boundary when we use it
      $message = "This is a multi-part message in MIME format.\n\n" .
         "--{$mime_boundary}\n" .
         "Content-Type: text/plain; charset=\"iso-8859-1\"\n" .
         "Content-Transfer-Encoding: 7bit\n\n" .
         $message . "\n\n";

      // now we'll insert a boundary to indicate we're starting the attachment
      // we have to specify the content type, file name, and disposition as
      // an attachment, then add the file content and set another boundary to
      // indicate that the end of the file has been reached
      $message .= "--{$mime_boundary}\n" .
         "Content-Type: {$type};\n" .
         " name=\"{$name}\"\n" .
         //"Content-Disposition: attachment;\n" .
         //" filename=\"{$fileatt_name}\"\n" .
         "Content-Transfer-Encoding: base64\n\n" .
         $data . "\n\n" .
         "--{$mime_boundary}--\n";

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "Message Sent";
      else
         echo "Failed to send";
   }
} else {
?>
<p>Send an e-mail with an attachment:</p>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" 
   enctype="multipart/form-data" name="form1">
   <p>From name: <input type="text" name="fromname"></p>
   <p>From e-mail: <input type="text" name="fromemail"></p>
   <p>File: <input type="file" name="filename"></p>
   <p><input type="submit" name="Submit" value="Submit"></p>
</form>
<?php } ?>
</body>
</html>

DanielWhite · June 21, 2008

Try changing:

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "Message Sent";
      else
         echo "Failed to send";

to this:


if ($type == 'ask') {

// Place any thing here if you want to show what happens if its accepted

} else {

// Place any thing here if you want to show what happens if its NOT accepted

echo "You did not upload a .ask file, Please try again.";
}

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "Message Sent";
      else
         echo "Failed to send";

papaface · June 21, 2008

Try changing:

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "Message Sent";
      else
         echo "Failed to send";

to this:


if ($type == 'ask') {

// Place any thing here if you want to show what happens if its accepted

} else {

// Place any thing here if you want to show what happens if its NOT accepted

echo "You did not upload a .ask file, Please try again.";
}

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "Message Sent";
      else
         echo "Failed to send";

You're code should be:

if ($type == 'ask') {

// Place any thing here if you want to show what happens if its accepted

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "Message Sent";
      else
         echo "Failed to send";

} else {

// Place any thing here if you want to show what happens if its NOT accepted

echo "You did not upload a .ask file, Please try again.";
}

I presume.

DanielWhite · June 21, 2008

Yeppers, try both. I just didn't want to mix it all up till we knew if it worked or not :-)

ballouta · June 21, 2008

Hi thanks for u all

I used papaface's code

if ($array[1] == 'ask') {

echo "it is working";

// now we just send the message

if (@mail($to, $subject, $message, $headers))

echo "Message Sent";

else

echo "Failed to send";

} else {

echo "You did not upload a .ask file, Please try again.";

}

When the file is .ask it printing: it is working, while it is NOT, it is NOt printing anything?!

very stange, why?

ballouta · June 22, 2008

Hi again

I need to add smthg to the form. When the .ask file is accepted. the code should make some DB process, but the varaible that I passed throught url before is not appearing in the (if accepted scope).

When I first open this form page, I echoed the varaiable and i can see it, but when i press submit and the file is .ask, the echo doesn't show me the variable (cuz it is empty) and the DB code is not applied.

kindly help

Bendude14 · June 22, 2008

how about adding the variable to a hidden field and pass it with POST when you submit the form

ballouta · June 22, 2008

Hi

I edited the form to this:

?>

<p>Upload your ask file. Please keep youf filename as is.</p>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"

enctype="multipart/form-data" name="form1">

</form>

<?php } ?>

and I added this get in the begining:

$user= $_GET['user'];

echo "The User = $user";

When I first open the this form, i can see the ablove lin echoed user name!

when submitted, the username doesn't appear.

Bendude14 · June 22, 2008

The information stored in $user should be available like this after you have submitted the form

<?php

$user = $_POST['user'];

?>

ballouta · June 23, 2008

I don't any problem now posting the user anymore.

I made some modifications to the code. It is logiually working now, If the user (after quering the DB) doens't have any credits, the file is NOT sent, the same idea if the file is NOT .ask.

If the user has credits and the file is .ask, the file is sent and i got it in my inbox. other DB process traces show that everything is 100% correct.

When the file is sent, the code prints : File sent (which is correct)

When it is NOT sent, i need to inform the user that the file is not .ask or he doesn't have enough credits

Where do I add this echo?

thanks

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Send Your ask File</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>
<body>
<?php
include('../CMS/global.inc.php');

   if ($_SERVER['REQUEST_METHOD']=="POST"){

	$size = $_FILES['filename']['size'];
	$name = $_FILES['filename']['name'];
	$array = explode( '.' , $name);
	$user = $_POST['user'];
	$date = date("y-m-d");

   // we'll begin by assigning the To address and message subject
   $to="malekface@hotmail.com";
   $subject="File to unlock";

   // get the sender's name and email address
   // we'll just plug them a variable to be used later
   //$from = stripslashes($_POST['fromname'])."<".stripslashes($_POST['fromemail']).">";
   $from = "GSCL";

   // generate a random string to be used as the boundary marker
   $mime_boundary="==Multipart_Boundary_x".md5(mt_rand())."x";

   // store the file information to variables for easier access
   $tmp_name = $_FILES['filename']['tmp_name'];
   $type = $_FILES['filename']['type'];
   $name = $_FILES['filename']['name'];
   $size = $_FILES['filename']['size'];
   
   		//check if the user has credits before sending a file
$query = "SELECT * FROM `credits` WHERE `user` = '$user' ";
$result = mysql_query($query);
$row = mysql_fetch_array($result);

   // here we'll hard code a text message
   // again, in reality, you'll normally get this from the form submission
   $message = "A New File from GSCLOnline.org: $name";

   // if the upload succeded, the file will exist
   if (file_exists($tmp_name) && $array[1] == 'ask' && $size < 200  && $row[num]>=1){

      // check to make sure that it is an uploaded file and not a system file
      if(is_uploaded_file($tmp_name) ){

         // open the file for a binary read
         $file = fopen($tmp_name,'rb');

         // read the file content into a variable
         $data = fread($file,filesize($tmp_name));

         // close the file
         fclose($file);

         // now we encode it and split it into acceptable length lines
         $data = chunk_split(base64_encode($data));

$query=" INSERT INTO `uploaded` ( `user` , `sentfile` , `date` , `received`) VALUES
('$user', '$name', '$date', 'N')";
$query_result = mysql_query ($query, $dbh);

$query = " UPDATE `credits` SET `num` = num-1 WHERE `user` = '$user' ";
$result = mysql_query($query);


     }//end if uploaded file

      // now we'll build the message headers
      $headers = "From: $from\r\n" .
         "MIME-Version: 1.0\r\n" .
         "Content-Type: multipart/mixed;\r\n" .
         " boundary=\"{$mime_boundary}\"";

      // next, we'll build the message body
      // note that we insert two dashes in front of the
      // MIME boundary when we use it
      $message = "This is a multi-part message in MIME format.\n\n" .
         "--{$mime_boundary}\n" .
         "Content-Type: text/plain; charset=\"iso-8859-1\"\n" .
         "Content-Transfer-Encoding: 7bit\n\n" .
         $message . "\n\n";

      // now we'll insert a boundary to indicate we're starting the attachment
      // we have to specify the content type, file name, and disposition as
      // an attachment, then add the file content and set another boundary to
      // indicate that the end of the file has been reached
      $message .= "--{$mime_boundary}\n" .
         "Content-Type: {$type};\n" .
         " name=\"{$name}\"\n" .
         //"Content-Disposition: attachment;\n" .
         //" filename=\"{$fileatt_name}\"\n" .
         "Content-Transfer-Encoding: base64\n\n" .
         $data . "\n\n" .
         "--{$mime_boundary}--\n";

      // now we just send the message
      if (@mail($to, $subject, $message, $headers))
         echo "file sent! ";
      else
         echo "Failed to send";
   }
} else {
//echo "File was Not sent, you either don't have enough credits or the file is not .ask";
?>

<p>Upload your ask file. Please keep your filename as is.</p>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" 
   enctype="multipart/form-data" name="form1">
   <p>File: <input type="file" name="filename"></p>
<? $user= $_GET['user'];  echo "Usr name in get = $user"; echo" <input type='hidden' name='user' value='$user'>"; ?>
   <p><input type="submit" name="Submit" value="Submit"></p>
</form>
<?php } ?>

</body>
</html>

ballouta · June 23, 2008

any help plz

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