[SOLVED] Load an image from database into html table

[XpertWorlock]

echo "<table border='1'>
<tr>
<td>Image Name : </td>
<td>Image Size : </td>
</tr>";

while($row = mysql_fetch_array($result))
  {
  $name = $row['img_name']
  
  echo "<tr>";
  echo "<td> <img src="images/"$name".JPG"></td>";
  echo "<td>" . $row['img_name'] . "</td>";
  echo "<td>" . $row['img_size'] . "</td>";
  echo "</tr>";
  }
echo "</table>";


mysql_close($con);


?>

 

I get an error when trying to load the image, I know it's not right, but I can't figure out how to correctly do it in a table.  Any help is appreciated.

Do I need to use HTML and body tags around this all, currently it's just PHP tags

 

Thanks

Mike

[PFMaBiSmAd]

I get an error when trying to load the image

Unless you were willing to tell us what the error is and where it is occurring, no one in a Forum will be able to help you.

[XpertWorlock]

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/wutanggr/public_html/imagetag.php on line 24

 

this line :

 

echo "<td> <img src="images/"$name".JPG"></td>";

[PFMaBiSmAd]

Double-quotes inside of a double-quoted string must be escaped with \. Also, why not use the same syntax your other lines are already using -

 

echo "<td> <img src=\"images/" . $row['img_name'] . ".JPG\"></td>";

[XpertWorlock]

That works.  I'm still in the learning process, this helps me out, thanks a lot.