Passing array as param

[allinurl]

does anyone knows how to pass an array into a URL, what I mean is if I have Array ( [0] => var1 [1] => var2 ) into the url as parameter, so I end up with something like: url.com?param=$var1&param=$var2 Thanks in advance

[xyn]

I would do this..

 

my array:

<?
$vars =array(
'test','ash','din'
);

$url ='mypage.php?';
foreach($vars as $param => $value){
$url.="&$param=$value";
}

print $url;
?>code]

[thebadbad]

Are you trying to generate an URL from an array? In your example, you're using "param" as a name in the query string twice. That's impossible. If you want to 'convert' an array's keys and values into names and values in a query string, this'll do:

 

<?php
$url = 'http://url.com?';
$array = array('name' => 'Joe', 'age' => 23);
foreach ($array as $key => $val) {
$url .= "$key=$val&";
}
$url = substr($url, 0, -1);
echo $url;
// http://url.com?name=Joe&age=23
?>

[xyn]

Your code does exactly what my example does, except yours uses more lines 

[allinurl]

thanks thats what I was looking for~~

[thebadbad]

Your code does exactly what my example does, except yours uses more lines 

 

Except yours outputs an invalid URL. Hint: placement of ampersand Also, I specified the keys in the array. And included a comment.

 

Who cares anyway.

[xyn]

my url wasnt invalid, its not hard to make an associative array :l, and thats the params sorted. but i dont care agreed.

[thebadbad]

Your script outputs "mypage.php?&0=test&1=ash&2=din" which is invalid/malformed. There shouldn't be an ampersand following the question mark.