[SOLVED] PHP and Post

[Minase]

hy there i do have the following code

 

echo '
<tr><td align="center" class="tdn" colspan=3><select class=input name="wn" size=1><option value="b">tagged messages<option value="a">all messages<option value="c">untagged messages</select>

<select name="to" size=1 class=input>
<option value="l">delete</select>
<input type=submit name="do" class=input value="Go!"></th></tr>
';

if (isset($_POST['wn']))

if ($_POST['wn'] == 'a') {
mysql_query("DELETE FROM `" . DBPREFIX . "users_messages` WHERE ReciverID = " . $_SESSION['user_id']) OR DIE(mysql_error());
} elseif ($_POST['wn'] == 'b') {

foreach($_POST as $a => $b){

	if(preg_match("/x/",$a) && $b == 'on'){

		$id = str_replace("x","",$a);
		$note_query = mysql_query("SELECT * FROM `" . DBPREFIX . "users_messages` WHERE UID='".$id."' AND ID='".$_SESSION['user_id']."' ");
		if($note_query){
			$deleted++;
			mysql_query("DELETE FROM `" . DBPREFIX . "users` WHERE UID='".$id."'");
		}
	}
}

}

 

i was wondering what i did wrong,cause whatever i select it doesnt do anything.

if i select to delete everything (the query is good) but it doesnt delete..

thank you

[irvieto]

Hi.

 

First of all,  use proper html tags.

 

<option value="some_val">Some text</option>. 

 

Then, check your $_POST to see what is the information you are receiving..

print_r($_POST);

[thatsgreat2345]

Just to let you know you do not need to use echo to echo out HTML code. You can close the opening php tag, and then reopen a new one where you need it.

 

so instead of echo replace it with , this is assuming that there is PHP above this HTML code.

?>
<tr><td align="center" class="tdn" colspan=3>
<select class=input name="wn" size=1>
<option value="b">tagged messages</option>
<option value="a">all messages</option>
<option value="c">untagged messages</option>
</select>

<select name="to" size=1 class=input>
<option value="l">delete</option>
</select>
<input type=submit name="do" class=input value="Go!"></th></tr>
<?

 

[Minase]

thanks for help