using scandir() on other websites

[947740]

I want to read a directory from another website.  E.G. http://www.somewhere.com.  I then want to display a list of files from that directory.  The PHP manual says I have to use fopen(), but I am not sure how to use that in conjunction with scandir().  Basically, how do I read the directory using scandir() and fopen()?

[rhodesa]

First, the remote directory MUST have directory listing turned on. aka, when you navigate with your browser to the directory, it shows the list of files there.

 

If the normal scandir() doesn't work:

<?php
$dir = "http://www.somewhere.com/";
foreach(scandir($dir) as $file){
  print '<a href="'.$dir.$file.'">'.$file.'</a><br>';
}
?>

try opendir():

<?php
$dir = "http://www.somewhere.com/";
$dh  = opendir($dir);
while (false !== ($file = readdir($dh))) {
  print '<a href="'.$dir.$file.'">'.$file.'</a><br>';
}
?>

[947740]

Getting:

 

Warning: scandir(http://www.fmtabor.k12.ia.us/Teachers/shepherd/BoardPolicy/) [function.scandir]: failed to open dir: not implemented in D:\FM\test_read.php on line 3

 

Warning: scandir() [function.scandir]: (errno 2): No such file or directory in D:\FM\test_read.php on line 3

 

Warning: Invalid argument supplied for foreach() in D:\FM\test_read.php on line 3

 

--------------------------------------------------------------------------------

 

Warning: opendir(http://www.fmtabor.k12.ia.us/Teachers/shepherd/BoardPolicy/) [function.opendir]: failed to open dir: not implemented in D:\FM\test_read.php on line 10

 

Warning: readdir(): supplied argument is not a valid Directory resource in D:\FM\test_read.php on line 11

[rhodesa]

yeah...what you will have to do, is read the page like a webpage and parse it for the info. not sure what info you want or what you are trying to do with it...but this should get you headed in the right direction:

 

<?php
$html = file_get_contents("http://www.fmtabor.k12.ia.us/Teachers/shepherd/BoardPolicy/");
if(preg_match_all('/<br>\s+(.+?)\s+<(\w+)>\s+<A HREF="(.+?)">(.+?)<\/A>/',$html,$matches)){
  foreach(array_keys($matches[0]) as $n){
    $date = $matches[1][$n];
    $type = $matches[2][$n];
    $url = $matches[3][$n];
    $name = $matches[4][$n];
    print "<hr><br>Date: $date<br>Type: $type<br>Url: $url<br>Filename: $name<br>";
  }
}
?>

[947740]

The only problem with that is, I want to read directories from websites that even have default files.  If there is a default file, I will not be able to read the information?

 

(Your code worked, in case you were wondering. ;-)

 

Thanks for your help.

[rhodesa]

You won't be able to read a remote directory if it has a default page (or if indexes are disabled)...nor should you be able to

[947740]

Well, thank you for your help.

 

I promise, I was not trying to do anything...sinister...;-)