Tainted Kitten Posted July 6, 2008 Share Posted July 6, 2008 <?php $query = "SELECT * FROM registereddogs WHERE `Sire` LIKE '%" . $x_ID . "%'"; $result=mysql_query($query); $row=mysql_fetch_array($result); echo $row['Name']; ?> This is only bringing up one result for me, and there's more records in the table which need to be displayed. It is showing the right record, just one of them rather than multiple. It could possibly be a result of the other SQL queries on this page, but from what I've posted here, is there a problem? I can post the full page if need be...It just gets a little complicated. Thanks, and hope this makes sense. Quote Link to comment Share on other sites More sharing options...
Tainted Kitten Posted July 6, 2008 Author Share Posted July 6, 2008 Never mind, got it! Quote Link to comment Share on other sites More sharing options...
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