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Help please, new to PHP


Goon

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Hi, I've created a query which retrieves all data from my mysql table and displays the results on a new page. 

 

Can anyone tell me how to display the results on the same page?  The code used can be seen below.

 

Also, can I edit the code to return data from the database based on the what the user selects (from a dropdown menu) on the form rather then returning all data from the table.

 

Any help would be much appreciated

 

Code:

 

$result = mysql_query("SELECT * FROM $table")

or die(mysql_error()); 

 

echo "<table border='1'>";

echo "<tr> <th>Vehicle</th> <th>Size</th> </tr>";

// keeps getting the next row until there are no more to get

while($row = mysql_fetch_array( $result )) {

// Print out the contents of each row into a table

echo "<tr><td>";

echo $row['Vehicle'];

echo "</td><td>";

echo $row['Price'];

echo "</td></tr>";

}

 

echo "</table>";

?>

 

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Please use the Code BB tags in future. But the answer to your question is to submit the form to itself using $_SERVER['PHP_SELF']

For example:

 

<?php 
  if(isset($_POST['submit'])) {
    if(!empty($_POST['name']) {
      echo $_POST['name'];
    }
    else {
      echo 'Please enter your name!';
    }
  }
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
  <p>Name: <input type="text" name="name" /></p>
  <p><input type="submit" name="submit" value="Submit" /></p>
</form>

 

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